Let $M$ be a smooth manifold, $f: M \mapsto M$ be a $C^{r}$ diffeomorphism, for $r \geq 1$. Let $\Lambda \in M$ be a submanifold in $M$ that is invariant under the action of $F$, i.e. $F(\Lambda)=\Lambda$. Suppose that $\Lambda$ is compact. We call $\Lambda$ a normally hyperbolic invariant manifold (NHIM) if there exist a constant $C>0$, splitting rates $0< \lambda < \mu^{-1} < 1$ and a splitting of the tangent space to $M$ at each $z \in \Lambda$
$$T_{z}M = E^{s}_{z}\bigoplus E^{u}_{z} \bigoplus T_{x}\Lambda$$
such that $$v \in E^{s}_{z} \quad \Leftrightarrow \quad \mid Df^{n}(z)v \mid \leq C\lambda^{n} \mid v\mid, \quad n\geq0,$$ $$v \in E^{u}_{z} \quad \Leftrightarrow \quad \mid Df^{n}(z)v \mid \leq C\lambda^{\mid n \mid} \mid v\mid, \quad n\leq0,$$ $$v \in T_{z}\Lambda \quad \Leftrightarrow \quad \mid Df^{n}(z)v \mid \leq C\mu^{\mid n \mid} \mid v\mid, \quad n \in \mathbb{Z}.$$
My question is: how do we determine the splitting rates $\lambda$ and $\mu$ ? Do we need to ensure that $\mu$ has some apriori determined value, or can we just pick $\textbf{any}$ $\mu$ such that the above is satisfied?
Foe example, consider $F(x,y) = (2x, \frac{y}{2})$. Then $F$ has a hyperbolic fixed point at the origin with eigenvalues $\{2, \frac{1}{2} \}$. Now let us increase the phase space and add two more identity variables $(p,q)$ to obtain the map $f$:
$f(x,y,p,q,) = (2x, \frac{y}{2}, p, q)$ where $(x,y,p,q,) \in \mathbb{R}^{3} \times \mathbb{S}^{1}$. We have NHIM
$$\Lambda = \{(x,y,p,q): x = 0, \quad y = 0, \quad (p, q) \in \mathbb{R} \times \mathbb{S}^{1} \}$$
We can take $\lambda = \frac{1}{2}$ here. Taking any $v = (0,0, p, q) \in T_{z}\Lambda$, we have $| Df^{n}(z)v| = \sqrt{p^{2} + q^{2}} \leq C\mu^{\mid n \mid} \mid v\mid$.
Therefore, does it follow that we may pick $\textbf{any}$ $C \geq 1$ and $\textbf{any}$ $1 < \mu < 2$ to satisfy the above inequalities?