I was wondering about the following problem.
We want to place $n$ points $x_1,\ldots,x_n\in \mathbb R^3$ on the sphere of $\mathbb R^3$, $\mathbb S^2$, such that they are as far as possible.
We note that the problem is easy on $\mathbb R^2$.
Here what it would look like on $\mathbb R^3$:
In other words, let $d$ be the usual distance on $\mathbb R^3$ and let's define the functions $f_n$ for $n\geqslant 2$:
$$\begin{matrix} f_n\colon & (\mathbb S^3)^n &\to &[0,2] \\ &(x_1,\ldots,x_n)&\mapsto &\min\big\{d(x_i,x_j),\ (i,j)\in \{1,\ldots,n\}^2, i\ne j\big\}. \end{matrix}$$
Since $(\mathbb S^3)^n$ is compact, and $f$ is continuous, $f$ attain a maximum $M_n:= \max f$.
Here is are two examples, the first one shows a configuration that has no chance to attain the maximum, the second one is a more serious candidate.
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If $n=2$, we can place the two points opposite two each other, $(-1,0)$ and $(1,0)$ for instance, and we get $M_2=2$.
If $n=3$, I would tend think that and equilateral triangle would be the solution to our problem, thus $M_3$ would be equal to $\frac 32$.
If $n=4$, I think the solution is to put a regular tetrahedron in the sphere, and some geometry show that $M_4$ then equal to $\frac{2\sqrt 6}3$.
Some questions.
Is there a generic way to calculate $M_n$?
If we can not find a formula for $M_n$, can we at least conduct an asymptotic analysis of the sequence $(M_n)$?
Do you know any references where this problem is treated?
