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enter image description here This picture has no further description,from the place I saw. I tried to solve it using Menelaus's Theorem, and I came up to the equation:

$$\frac{1}{CD} \times \frac{AF}{BF}=\frac{AE}{CE} \times \frac{1}{BD}$$

After joining, If we produce AO, then it meets BC at D.

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    There is no point $D$ in the diagram – 2017-01-07
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    That is ceva's theorem, as the intersection of AO and BC is D. – 2017-01-08

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