I have a problem.
Assume that we have a logic circuit realizing fast modular exponentiation. On the basis of this circuit we build a logical formula CNF.
We know basis (number) for fast modular exponentiation. Of course, this number is written to the circuit (and formulas CNF) in the form of binary variables 0/1: $a_{1}, a_{2} ... a_{k}$. We have also binary variables defining the exponent - but they are not defined, and we will look for them in our problem.
The logic circuit is constructed such that the result of the exponentiation must be equal to $r$ (binary variables $r_{1}, r_{2} ... r_{k}$). CNF formula is true only when the result is correct.
The question is as follows. The exponent in fast modular exponentiation can have $y$ bits.
Is when we add one bit to the length of the exponent of the computational complexity of the formula CNF our problem should increase $2x$?
In theory, the algorithm has to search a lot more combinations, because increasing the length exponent of $1$ bit means that we have not up to $A^{2^{y}}$, but to the number: $A^{2^{y+1}}$.
We are talking about the worst case.
From my initial calculations show, however, that complexity does not increase exponentially. Increases linearly (I use MiniSAT to solve CNF formula). I do not know if I'm incorrect in my software code (maybe so).
What can you say about the problem? What should have complexity?