Given,
$$\frac{2xz-1}{z} + \frac{2xy-1}{x} + \frac{2yz-1}{y} = 3$$
I have tried this in so many ways but unable to factorise.
Please help me to solve this.
How to factorise following equation?
0
$\begingroup$
factoring
-
0What do you mean by “factorize” the equation? – 2017-01-05
-
0@Michael Hope like getting (x-2z)(y-z)=0 something like that. – 2017-01-05
-
0The nicest form I was able to get it into, by multiplying across by $xyz$ and then collecting like terms, is: $$2xyz(x+y+z)-(xy+yz+xz)=3xyz$$ – 2018-11-14