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On Page 54 of Hatcher's K-theory and vector bundles text he outlines the reduced external product. I have understood the argument, including the fact that it is a restriction of the unreduced external product. What I don't understand is how he has obtained the commutative diagram in the middle of the page. In particular, why $K(X) \otimes K(Y)$ is isomorphic to $(\widetilde{K}(X) \otimes \widetilde{K}(Y)) \oplus \widetilde{K}(X) \oplus \widetilde{K}(Y) \oplus \mathbb{Z}$.

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Since $K(X) \cong \tilde K(X) \oplus \def\Z{\mathbf Z}\Z$, we have $$ K(X) \otimes K(Y) \cong \bigl(\tilde K(X) \otimes \Z\bigr) \oplus \bigl(\tilde K(Y) \otimes \Z\bigr)$$ Taking termwise products, and using that $R \otimes \Z \cong R$, for each $R$, we have $$ K(X) \otimes K(Y) \cong \tilde K(X)\otimes \tilde K(Y) \oplus \tilde K(X) \oplus \tilde K(Y) \oplus \Z$$

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    In the first line the tensor products and direct sums are reversed.2017-02-16