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Given a compact set $A$ in $\mathbb{R}^2$ with positive 2-dimensional Lebesgue measure, does there always exist $S, T \subset \mathbb{R}$ both Lebesgue measurable and non empty, such that $\mu (S)>0$ or $\mu (T) > 0$, and $S \times T \subset A$ ?


I found answers to similar questions, but the hypothesis were weaker : $A$ Borel measurable, or $S$ and $T$ both non null sets (and with such hypothesis, the statement is false).

I also found a theorem from Mycielski which might answer this question. The reference is

J. Mycielski, Algebraic independence and measure, Fund. Math. 61 (1967), 165-169

but I could not find it. Apparently, the theorem states that :

Suppose $A$ is a compact subset of plane of positive area. Then there are non empty perfect sets of reals $X$,$Y$ such that $X$ or $Y$ has positive length and $X \times Y \subset A$.

But I think that I am lacking context. Any help on the problem itself, or a link to a page where I could find the complete statement of the theorem, would be greatly appreciated.

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    Perfect, thank you very much !2017-01-04

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Jan Mycielski's paper "Algebraic independence and measure" is available here.