Let $\mathbb Q$ be the set of all rational numbers and $X\subset \mathbb R$ nonmeasurable (in the sense of Lebesgue). What we can say about the Minkowski sum $X+\mathbb Q$, is it measurable or not?
Is the Minkowski sum of the rational numbers and a nonmeasurable set again nonmeasurable?
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real-analysis
lebesgue-measure
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0$\mathbb Q$ here is all rational number. – 2017-01-05
1 Answers
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The sum $X+\mathbb Q$ may be measurable or nonmeasurable, depending on the choice of the nonmeasurable set $X.$
If $X$ is a Vitali set, then $X+\mathbb Q=\mathbb R$ is measurable.
A Bernstein set is a set $X\subset\mathbb R$ such that both $F\cap X$ and $F\setminus X$ are nonempty for every uncountable closed set $F.$ A Bernstein set is nonmeasurable; moreover, the usual construction of a Bernstein set (by transfinite induction) can easily be modified so as to guarantee that $X+\mathbb Q=X.$