Let $P(x)$ be the xth prime, $P(0)=2$
Given a prime $p$, does it always exists a $n$ such $\sum_{x=0}^{n}P(x) = 0$ $(mod$ $p)$ ?
Example :
$p=7$
$2+3+5+7+11=28=4*7$
Best regards
Let $P(x)$ be the xth prime, $P(0)=2$
Given a prime $p$, does it always exists a $n$ such $\sum_{x=0}^{n}P(x) = 0$ $(mod$ $p)$ ?
Example :
$p=7$
$2+3+5+7+11=28=4*7$
Best regards
http://oeis.org/A111287 is smallest $k$ such that $p_n$ divides $\sum_{i=1}^kp_i$. It says, "It follows from a theorem of Daniel Shiu that $k$ always exists," and many more details are given. [And I'm pretty sure I have already seen, maybe even posted, this answer to m.se before]
EDIT: I found the earlier question, Every prime number divide some sum of the first $k$ primes. and have voted to close this one as a duplicate.