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I have 3 expressions:

$f(x)=e^{ikx}+Ae^{-ikx}; g(x)= Be^{kx}+Ce^{-kx}; h(x)=De^{ikx}$

I want to find $|A|^2$ by letting

${f'(0)\over f(0)}={g'(0)\over g(0)}$ and ${g'(a)\over g(a)}={h'(a)\over h(a)}$

I have done the calculations myself and got $|A|^2=1$. But this is not the expected answer. Could someone tell me if I have made a mistake?

Thanks.

  • 1
    How does letting those things equal each other help you find anything? It looks to me like $A=f(0)-1$ is a pretty swift route and the other two functions are irrelevant. Is there more to this question than what you've written here?2011-10-22
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    I am getting A=0. what is the expected answer??2011-10-22
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    @craig: you probably should be posting your **actual** problem.2011-10-22
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    @craig Can you tell the entire question??2011-10-22
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    @RamanaVenkata: Thanks. I am very sorry, I just realized there is a typo in my question. The $i$'s in $g(x)$ shouldn't be there. I have edited it. Um, I was expecting something between 0 and 1 (though I might be wrong...) Sorry again.2011-10-22
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    Also, you might be wanting to edit your title to let it resemble your problem.2011-10-22
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    In what terms do you need A ??2011-10-22
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    @RamanaVenkata: I just need $|A|^2$2011-10-22
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    Okay in what terms do you need $|A|^2$ ??2011-10-22
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    @RamanaVenkata: What ever it might be...2011-10-22
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    I am getting something like this $\left(\dfrac{BC-BCe^{2ka}}{B^2e^{2ka}-C^2}\right)^2$. If you can give some more information it would be helpful..2011-10-22
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    @craig: if this is a tunneling problem in quantum mechanics, $g(x)$ should probably be a function of $\kappa x$, where $\kappa \neq k$.2011-10-22
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    I don't know quantum mechanics I am asking for any initial conditions or boundary conditions something like that.2011-10-22

2 Answers 2

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The first condition, that $f'(0)/f'0)=g'(0)/g(0)$, is equivalent to $A=-z/w$ where $z$ and $w$ are the complex number $z=B-C-\mathrm i(B+C)$ and $w=B-C+\mathrm i(B+C)$. If $B$ and $C$ are real numbers, $w=\bar z$ hence $|A|=1$. (The only case when $w=0$ is $B=C=0$, and then $g(0)=0$ hence $g'(0)/g(0)$ does not exist.) The second condition is irrelevant since it uses values at $a$.

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From the first condition we can conclude :

$(A=-1 \lor k=0 \lor B=C) \land (A=1 \lor k=0 \lor B=-C)$

From the second condition we have that:

$(k=0 \lor C=Be^{2ka}) \land (k=0 \lor C=-Be^{2ka})$

so...

$a)$if $k=0 \Rightarrow A$ is undetermined

$b)$if $B=\pm C=0 \Rightarrow A$ is undetermined

If we observe the second condition we can see that $C$ cannot be at same time $Be^{2ka}$ and $-Be^{2ka}$ which means that $k=0 \lor B=\pm C=0$,therefore $A$ is undetermined.