2
$\begingroup$

Is there expression for an operator that gives for any analytic periodic function its period?

P.S.

In my view this probably means solving the following system of equations:

$$f^{(n)}(0)=f^{(n)}(T)$$

against $T$.

I just wonder whether the solution to this system can be written in a form of one expression.

P.P.S. Alternatively the equation can be written as

$$\Delta f(Tz)≡0$$

  • 0
    I can't think of any operator that would be able to handle both elliptic functions and the function $x-\lfloor x\rfloor$...2011-05-07
  • 2
    What is an expression? What is a periodic function? (For example, is the indicator function of $\mathbb{Q}$ a periodic function? What is its period?)2011-05-07
  • 0
    I am interested in operator that returns (minimal) period for analytic functions.2011-05-07
  • 0
    So... it would have to return one result for exponentials and two results for elliptic functions, then?2011-05-07
  • 1
    If you want to focus on analytic functions, do specify that. If you have further conditions on the functions you are interested in - please specify them. If you add context to why you want this operator, other ideas that might be useful can be given instead.2011-05-07

1 Answers 1

1

If you just want an abstract operator you could define for the function $f: A \mapsto B$ the period length $P$ as (you need some norm to define whats "small"):

$P(f)=\min(p \in \mathbb{R} | \exists z: |z|=p: \forall x \in A: f(x+z)=f(x))$ if the minimum exists. If you want some generic function (that will be more useful) to actually determinate the period length you have to make some assumptions about $f$ as there probably isn't any more generic useful formula.

  • 0
    Yes. I want a constructive formula that gives an actual expression or encodes an algorithm of how to find such period.2011-05-07
  • 0
    As I said you have to make an assumption about the functions you want to look at then.2011-05-07
  • 0
    I meant analytic functions.2011-05-07
  • 0
    So you can try to find the smallest strictly positive root (in terms of $y$) of $f(x)-f(x+y)$ which is again a numerical problem (note that it has to hold for all $x$).2011-05-07