Let us denote by $X_n$ the number of possible words of length $n$ ending with the letter $X$, and similarly $Y_n, Z_n$. Then the reccurence applies:
$$X_{n+1} = X_n + Y_n + Z_n$$
$$Y_{n+1} = X_n + Z_n$$
$$Z_{n+1} = X_n + Y_n$$
$$X_1 = Y_1 = Z_1 = 1$$
This can be easily programmed to obtain the requested number of possibilities:
$$X_{30} + Y_{30} + Z_{30} = X_{31} = 367'296'043'199$$
The recurrence can be further simplified by using $Y_n = Z_n$ (see the comment by @Gerry):
$$X_n = 2 X_{n-1} + X_{n-2}$$
We notice that the number of sequences of the length $n$ is $X_{n+1}$. The sequence $X_n, n \ge 1$, is $\{1, 3, 7, 17, 41, 99, 239, 577, ...\}$. This are numerators of continued fraction convergents to sqrt(2). This page gives also the explicit solution:
$$X_n = \frac{1}{2}[(1-\sqrt{2})^n + (1+\sqrt{2})^n]$$
The sequence $Y_n$ (and $Z_n$) is $\{1, 2, 5, 12, 29, 70, 169, ...\}$ which are the Pell numbers.
Since you are also interested in a program for generating the words, I posted a running C++ program to Ideone. The program represents a string $XYZ...$ by the integer in the base 3, $a = 012..$, which is stored as an array of integers $[0,1,2...]$. A new combination is generated by adding $1$ to $a$ in base 3 system and ignoring the forbidden combinations $..11..22..$.
EDIT. I included the explicit reccurence for $X_n$ based on the comment by @Gerry. He mentions also the method for finding the explicit solution.