Here's an easy one. I just can't think straight tonight. If I have $$S=((sec*75)+f)*588$$ What are the two equations I need to solve for $sec$ and to solve for $f$ ? Also, $1sec = 75f$?
Solving $S=((sec*75)+f).*588, 1sec = 75f$
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algebra-precalculus
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1Divide both sides by 588 to get $\frac{1}{588}S=75sec+f$. Replace $sec$ with $75f$, then divide both sides by $75^2+1$ to get $f$, and multiply that answer by $75$ for $sec$. Is that what you're trying to do? – 2011-09-06
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2You already have two equations. Replace the $sec$ in your first with what it's equal to; that is, $75f$. – 2011-09-06
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0@anon Yes... Thats what I was after. Thanks. Can you put it in an answer so I can close it? Thx – 2011-09-06
1 Answers
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$$S=588(75sec+f)$$ $$\frac{1}{588}S=75sec+f$$ Replace $sec$ with $75f$, $$\frac{1}{588}S=75(75f)+f=(75^2+1)f$$ $$\frac{S}{588(75^2+1)}=f$$ and multiply the above by 75 for $sec$. It's possible (seeing the two 75s paired together) there was an error made before the given question was posed but I'll leave that up to you OP.