I found this limit within the Calculus Single Variable book from Thomas. $$ \lim _{x \to -2^-} (x+3) \frac{|x+2|}{(x+2)}$$
This is how I'm trying: First of all, we need to found where the absolute value will apply. $$|x+2|$$ $$x+2=0$$ $$x=-2$$ $$ -3+2<0 $$ $$ -1+2>0 $$
So the function will change of sign in this interval: $$(-\infty, -2)$$ Then I´m trying to solve by substitution but im stuck with the |x+2|, I don't know what to do within the absolute value :(. Thanks.