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I'm having trouble with integrating this function. Could someone please add the steps to get to the answer? Initial condition $y(0) = 2$.

$y' = 4e^{0.8t}-0.5y$

Answer:

$y= 4/1.3(e^{0.8t} - e^{-0.5t}) + 2e^{-0.5t}$

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    That answer is not right unless you are also given an initial condition $y(0)=2$.2012-07-29
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    @Code-Guru, I got as far this with C=-3.\\ $y = 5e^{0.8t} - 0.5yt +C$ \\ $(1+.5t)y = 5e^{0.8t} + C$ \\ $y = (5e^{0.8t})/(1+0.5t) + C$ \\ $y=(5e^{.8t})/(1+.5t) + C$ Robert Israel, I've added the initial conditions2012-07-29
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    Please edit your question to include your work. Also you should indicate if you have a specific question about something that you don't understand.2012-07-29

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