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Compute the probability that a randomly chosen positive divisor of $10^{99}$ is an integer multiple of $10^{88}$

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    What have you tried? Or, in the spirit of the 'question', maybe I should say: Show us what you tried.2012-03-24
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    Hint: a divisor is of the form $2^m5^n$ with $0\leq m,n \leq 99$. It is divisible bt $10^{88}$ only when $m,n\geq 88$2012-03-24

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