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$\begingroup$

$$\frac{10}{r-3}+\frac4{3-r}=6$$

I am not sure how to solve this equation I know both that both denominators on the left side if multiplied by negative 1 equal the other one.

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    Do you mean $\frac{10}{r-3}$ or $\frac{10}{r}-3$? You can indicate which you mean by using parentheses2012-04-28
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    Hint: $(r-3)=-(3-r)$2012-04-28
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    With the hints provided I did this 10(r-3)-4 which then I turned into 10r-30-4=6 which then I got into 10r=40 which then I got my answer as r=4.2012-04-28
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    You can accept the answer you found most helpful by clicking the checkmark below the voting arrows.2012-04-28

3 Answers 3