$\log 2,\log 2^{x-1}$, and $\log 2^{x+3}$ are $3$ consecutive terms of an arithmetic progression; find (i) the value of $x$;
what is value of x in an arithmetic progression involving logarthms
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sequences-and-series
arithmetic
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0Please check that I correctly interpreted what you wrote when I made the exponents $x-1$ and $x+3$. – 2012-04-13
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0$$\log 2^{x-1}-\log 2=\log 2^{x+3}-\log 2^{x-1}$$ – 2012-04-13