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Possible Duplicate:
Partial latin square with $\le n-1$ filled cells

http://ajc.maths.uq.edu.au/pdf/22/ocr-ajc-v22-p247.pdf

Could someone please further explain the inductive step here in Theorem 5 in more explicit terms, or write the proof in explicit terms? I'm afraid I don't see how the inductive step makes sense for the completion of a Latin square.

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    Already asked at [Partial latin square with $\le n-1$ filled cells](http://math.stackexchange.com/questions/169334/partial-latin-square-with-le-n-1-filled-cells)2012-07-12
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    Gerry, I think it is worth mentioning that this is a corollary of the question you linked. Not a duplicate.2012-07-13
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    Danielle added this question to the original question - it is there.2012-07-13
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    And I’ve posted an answer there.2012-07-14

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