I am interested in solving the general solution for the following set of equations:
$$f'(t)=g(t)$$ $$g'(t)=-2f(t)-\frac{9}{4}k(t)$$ $$h'(t)=-f(t)+2k(t)$$ $$k'(t)=-2g(t)-h(t)$$
How can I get the general solution here?
So far I get to $$f(t)=\int \! g'(t)dt=\int-2f(t)-\frac{9}{4}k(t)dt$$ And then I'm lost
Thanks for all your help!