I am having trouble finding the partial derivative. And clues or hints regarding said problem and how to find saddle points/local maxima is appreciated.
Calculate the partial derivative, local minima/maxima, and saddle points.
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multivariable-calculus
derivatives
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0Note that if you set the derivatives to zero and solve, you will get the only stationary point $x=y=-\sqrt[3]{2}$. If you substitute this into the second derivative, you will get the matrix $\pmatrix{2 & 1 \\ 1 & 2}$, which is positive definite, hence this is the only local minimum. – 2012-11-24