I'm trying to figure out how to solve this problem:
$$\frac{d}{dt} \arcsin(\sqrt{2t})$$
Wolfram Alpha gives me the following answer:
$$ \frac{1}{\sqrt{2 - 4t}\sqrt{t}} $$
Here is what I've gotten:
$$y = \arcsin{\sqrt{2t}}$$ If $u = (2t)^{1/2}$ then $u' = \frac{1}{2} 2 t^{-1/2}$ therefore:
$$\frac{dy}{dt} = \frac{1}{\sqrt{1 - 2t}} \cdot \frac{1}{2 \sqrt{2t}}$$
Any Help?