4
$\begingroup$

I thought it does not have absolute maximum, but wanted to just check and see why

  • 4
    it's a continuous function on a closed interval, so it better have a maximum2012-03-13
  • 0
    Your function has to have an absolute maximum, by *Weierstrass theorem*.2012-03-13
  • 0
    I think I might have got confused with the local maxima2012-03-13

2 Answers 2