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Is my calculation correct for this rotation around a point?

A point a(-19.94,392.11) is rotated -49.45 degrees, what is the new coordinates of point a?

My solution:

x' = x*cos(0) - y*sin(0) y' = x*sin(0) + y*cos(0)  x' = (-12.961) - (-298.0036) y' = (15.15) + (254.92)  x' = 285.04 y' = 270.07 
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    Is there a connection between this question and [this other question](http://math.stackexchange.com/questions/122850/where-is-zero-degrees-on-a-graph) posted a quarter of an hour later? It sure looks like it; even the $\theta$ written like a $0$ is the same.2012-03-21
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    @joriki sure is :P, I made this question also(before I remembered I had a registered account I could use)2012-03-21

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