I am trying to evaluate the following integral, but don't know how to take the coefficient of $z$ out of the parenthesis to get it into the Cauchy integral form. Any help is appreciated.
$$ \oint_C \frac{\sin 2z}{(6z-\pi)^3}dz$$
I am trying to evaluate the following integral, but don't know how to take the coefficient of $z$ out of the parenthesis to get it into the Cauchy integral form. Any help is appreciated.
$$ \oint_C \frac{\sin 2z}{(6z-\pi)^3}dz$$