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I want to create a multiple-choice exam consisting of $N$ problems. Each problem has $M$ mutually-exclusive options. If you don't choose any option, you will get $0$. If you wrongly choose, you will get $-1$. Otherwise you will get $1$.

To pass the exam, at least you need to have a score of $x$ where $0. When an uneducated toddler plays with the answer sheet and behaves randomly, what is his/her probability to pass? The toddler knows that she/he cannot choose 2 or more options for each problem.

If you think my question is not clear enough, you can make some answers, each for the possible case you think.

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    For those who give answers, be patient. I am waiting for more answers and comments to make a final decision. This comment will be removed later.2012-11-04
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    This question is not sufficiently clear. What does "behaves randomly" mean? Does the student answer every question? Are they equally likely to skip a question as to answer it? Are they equally likely to skip a question as to select any one of the options? Please clarify.2012-11-04
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    What an odd declaration... Anyway, while waiting you might try to make the question complete by specifying the probability that the student does not choose any option at a given problem. Other hypotheses are missing which one can guess, but not this one.2012-11-04
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    The more interesting question is how many questions the student should guess to maximize their pass probability.2012-11-04
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    @DavidWallace: The student (or the toddler in my last edit) can skip and answer with the same probability. Randomly freedom.2012-11-04
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    You mean, skip with probability 1/2 and choose any given option with probability 1/(2M)?2012-11-04
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    @did: You have the same chance to answer or skip. When you answer, you have the same chance to select one option among the others. I don't know how to rephrase this mathematically.2012-11-04
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    *I don't know how to rephrase this mathematically*... I just did.2012-11-04
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    If there are M possible answers to a question, is the probability of choosing a particular one of them $\frac{1}{M+1}$ and of choosing no answer $\frac{1}{M+1}$? Or is the probability of choosing a particular one of them $\frac{1}{2M}$ and of choosing no answer $\frac{1}{2}$?2012-11-04

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