Where am I going wrong?
Find the difference quotient for: $f(x)=2-x-3x^2$
$$\frac{[ 2-(x+h)-3(x+h)^2 ] - [ 2-x-3x^2 ]}{h}$$
$$\frac{2-x-h-3x^2-6hx-3h^2-2+x+3x^2}{h}$$
$$\frac{-3h^2-6hx-h}{h}$$
$$-3h-6x-1$$
Where am I going wrong?
Find the difference quotient for: $f(x)=2-x-3x^2$
$$\frac{[ 2-(x+h)-3(x+h)^2 ] - [ 2-x-3x^2 ]}{h}$$
$$\frac{2-x-h-3x^2-6hx-3h^2-2+x+3x^2}{h}$$
$$\frac{-3h^2-6hx-h}{h}$$
$$-3h-6x-1$$
Well, nowhere. Everything is OK.