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Suppose that $d|m$ and that $a≡b \space (mod \space m)$. Explain why it is also true that $a≡b \space (mod \space d)$.

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    Um, what is $l$? If $d=l=6$ and $m=5, a=1, b=6$, then it isn't true. Did you mean $d\mid m$?2012-09-26
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    Sorry, yes meant to say $d|m$.2012-09-26

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