Here is the problem. If
$$\lim_{x\to-2}x^3 = - 8$$
then find $\delta$ to go with $\varepsilon = 1/5 = 0.2$.
Is $\delta = -2$?
Here is the problem. If
$$\lim_{x\to-2}x^3 = - 8$$
then find $\delta$ to go with $\varepsilon = 1/5 = 0.2$.
Is $\delta = -2$?