I thought it does not have absolute maximum, but wanted to just check and see why
Absolute maximum value of $\sin^2(x)-\sin(x)$ in $[0,\frac{3\pi}{2}]$
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calculus
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4it's a continuous function on a closed interval, so it better have a maximum – 2012-03-13
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0Your function has to have an absolute maximum, by *Weierstrass theorem*. – 2012-03-13
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0I think I might have got confused with the local maxima – 2012-03-13