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Solve $$\int\limits_{0}^{3}\int\limits_{-\sqrt{9-y^2}}^{\sqrt{9-y^2}}\int\limits_{0}^{9-3\sqrt{x^2+y^2}}dzdxdy.$$

Update: The problem is setting up the integral. What I have tried was $$\int\limits_{0}^{\pi}\int\limits_{-3}^{3}\int\limits_{0}^{9-3r}dzrdrd\theta.$$ It gave me $54\pi$ and I don't think it's right.

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    @Sigur are you sure?2012-11-06
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    Sorry, I didn't see the $r$ after $dz$. Now $\int _{0}^{\pi }\!\int _{-3}^{3}\!\int _{0}^{9-3\,r}\!1{dz}r{dr}\,{d\theta} =-54\,\pi$2012-11-06

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