Given: $C=10$, $C^a=3$, $C^b=5$, how to solve $C^{2a-b+1}$.
I would be very grateful if somebody show me how to solve this.
Thanks.
Given: $C=10$, $C^a=3$, $C^b=5$, how to solve $C^{2a-b+1}$.
I would be very grateful if somebody show me how to solve this.
Thanks.