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Without using L'Hopital's Rule, how does one find $\lim_{x \to 0^{+}} \frac{\ln(x+1)}{x}$?

I was hoping to find a way using basic calc I, pre-differentiation knowledge and not knowing the definition of $e$--much like you can prove $\lim_{x\to\infty} \frac{\sin x}{x} = 1$ using a geometric argument and the squeeze rule/theorem.

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    Do you know how to find $\lim\limits_{h\to 0}\dfrac{f(0+h)-f(0)}{h}$ when $f(x)=\ln(x+1)$? I.e., do you know how to find the derivative of $\ln(x+1)$ at $0$? What is your definition of $\ln$?2012-09-18

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