What would be the necessary condition for a matrix of any $n \times n$ to have eigenvalue 1? I know that it must have a corresponding eigenvector - that is obvious - I want to know things like how values must be, or things like that.
What is the necessary condition for a matrix to have eigenvalue 1?
1
$\begingroup$
linear-algebra
matrices
-
0There must be a vector that is unchanged by multiplication with the matrix, I don't really think there is much more to it... – 2012-12-11
-
1In relation to what Jaime said, think about how matrix multiplication works with a column vector X, that is, what has to be true about the system of equations A represents? This only gets you so far though, really there's only one thing this gives you from the linear algebra properties (the things you already mentioned). – 2012-12-11
-
0$A-Id$ would then have eigenvalue $0$, hence would be nonivertible. – 2012-12-11
-
0@berci, that's not technically true, consider I, it has eigenvalue 1, and is most definitely non-singular. Ah missed what you were saying, never mind. – 2012-12-11
-
0@Vilid: but $I-I = 0$ is most definitely singular. – 2012-12-11