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If column vectors of ${\bf B}$ are independent and normalized, can we conclude the row summation of $({{\bf B}^T{\bf B}})^{-1}$ nonnegative? By row summation, I mean $({{\bf B}^T{\bf B}})^{-1}{\bf 1}$. ${\bf 1}$ is a vector with components all one's.

Sorry for this question. Seems what I need is only ${\bf 1}^T({\bf B}^T{\bf B}){\bf 1}>0$. But this is trivial.

Thank you all so much!

  • 0
    What is the row summation?2012-04-16
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    @MartinArgerami I'd think it is the sum of the entries in a row?2012-04-16
  • 0
    What's the background, motivation for this question?2012-04-16

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