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How does the transform rule help us solve this problem? Does this just mean I can rewrite the problem as:

$$\mathcal{L}^{-1}\left\{\frac{6}{(s+3)(s+3)}\right\} = \int_0^t \frac{6}{\tau(\tau+3)(\tau+3)}d\tau$$

Which I can then do what with?

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    Well, can you actually solve the integral and come up with the inverse Laplace transform?2012-12-11
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    Wolfram tells me that the integral does not converge.2012-12-11
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    How about working it from another angle first. What is the inverse Laplace transform of F(s)? (Do it the way you know how.) Can you now figure out how to use that to move forward?2012-12-11
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    Should I use a table to look this up?2012-12-11
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    Do you know the method of partial fractions?2012-12-11
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    Do you know (or can compute) the inverse transform of $$\frac{6}{(s+3)^2}\,?$$2012-12-11

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