How come the preimage of
$y=x^2$
given
$T = [-2, 1]$
is
$-1 \leq x \leq 1$
3
$\begingroup$
Shouldn't it be
$-\sqrt 2 \leq x \leq 1$
?
How do you determine the preimage step by step?
functions
discrete-mathematics
asked
2012-12-08
user id:52147
43
2
2bronze badges
4 Answers
4
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