0
$\begingroup$

I took a number, $2012^{2012}$.

Then I cancelled all the $9$'s which appeared in its expansion. I also cancelled all the digits which added up to $9$ viz $1 + 3 + 5 , 2 + 7$ etc. What will be the sum of remaining digits?

Please help.

  • 1
    So, [casting out nines](http://en.wikipedia.org/wiki/Casting_out_nines)? [In that case...](http://www.wolframalpha.com/input/?i=PowerMod%5B2012%2C+2012%2C+9%5D)2012-07-07

3 Answers 3