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Is there a way to represent this integral in terms of summation of series? $$ \int_0^\infty {1 \over x^x}dx$$ Like for example: $$ \int_0^1 {1 \over x^x}dx = \sum_{n=1}^\infty {1 \over n^n}$$ I am not getting an answer from Mathematica.

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    thanks @Sasha I didn't know that ... but how to evaluate the integral with $ \infty $?2012-08-20
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    Oops, sorry. I guess I missed the question.2012-08-20
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    your info was helpful ;)2012-08-20
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    This doesn't look like an exact duplicate to me. I vote not to close.2012-08-20
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    To start talking about this integral i think you have first to define what is $1/x^x$ when $x=0$.2012-08-20
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    it's an improper integral2012-08-20
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    thats true. ^_^2012-08-20
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    The numerical value is 1.995455957500138000... and the [Inverse Symbolic Calculator](http://isc.carma.newcastle.edu.au/index) finds nothing.2012-08-20

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