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I am not given the standard deviation in this problem. I understand that the following holds when the data is normally distributed:

Upper 95% bound $= (\bar{X} + (SE) \cdot 1.96)$

I have all of these values, but the only way I see to relate them to $n$ is through:

$$SE = \frac{\sigma}{\sqrt{n}}$$

but because I dont have the stdev, I don't understand how all of these pieces connect so that I can find $n$.

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    As a two sided bound (X¯-(SE)⋅1.96, X¯+(SE)⋅1.96) is a 955 bound. But as a one-sided bound (X¯+(SE)⋅1.96) is a 97.5% bound.2012-08-27

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