0
$\begingroup$

I'm trying to solve this problem but I can't figure how. Can you help me?

$$A=\frac{\sin \alpha+\cos(3\pi/2-\alpha)+\tan(5\pi+\alpha)}{\csc(2\pi-\alpha)+\sin(5\pi/2+\alpha)}$$

If $\tan \alpha=-2/3$ and $\alpha \in$ IV quadrant, calculate the value of the expression.

Thanks.

  • 0
    Pardon me, but what are "sen" and "tg"? Are these abbreviations for "sine" and "tangent"? if so, the only standard abbreviations in English are "sin" and "tan".2012-03-26
  • 0
    Fixed. Sorry for that, the english is not my native language.2012-03-26
  • 0
    No problem; that's why I asked.2012-03-26
  • 0
    Can somebody help?2012-03-26

1 Answers 1