How is it that a finitely additive probability measure on a field may not be countably subadditive? I know that the field must be countably additive and thus finite additivity does not suffice, but I'm struggling with the reasoning.
Finitely additive probability measure thats not countably subadditive
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probability
measure-theory
probability-theory
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0What do you mean by "the field must be countably additive"? – 2012-09-27