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$$ x = 1/2, v[2,−2], t = 3, P(1, 2)$$ x = speed, v = orientation, t = time, p is a point.

I tried this : $$((2, -2) - (1,2)) \sqrt{1^2 + 4^2} $$

I got my <1,4> from $(2-1, 2-(-2))$ , which is my directional vector. Right ?

which is equal to $$ (1, -4) \sqrt{17} $$

my final answer is : $$(1,2) + 1/2((1,-4)\sqrt {17})$$ Is it ok ?

Then I'm asked : what would be the equation if it was 'unit speed' instead of m/sec

Not sure what to do.

Thanks

1 Answers 1