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I am currently having issues with calculating plane intersection of a ray.

I start with the following equation $P = P_0 +tR_t$

$R_t$ is the Unit Vector of the Trajectory.

Now we have a plane which is given by

$Ax+Bx+Cx +D = 0$

Where the normal vector is given by $N = \langle A,B,C\rangle$

To calculate the Plane Intersection you find $t$

$t = \frac{R_0\cdot N + D}{R_t \cdot N}$

Then once you have that you substitude and find intersection.

Assuming I want to find the ray intersection to the y=0 plane, what would be my D value in this case. I know that is should be $D=-Ax-By-Cz$ . But how to determine x,y,and z?

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    help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!2012-11-29

1 Answers 1