2
$\begingroup$

Question related to: On the propagation of singularities in PDE and https://math.stackexchange.com/questions/164277/hypoellipticity-and-singular-support.

in what sense is to interpret the sentence the schrodinger operator has infinite propagation speed. And what about the fact that if there is a singularity at $t=0$, then at $t=\epsilon$ there isn't anymore?

1 Answers 1