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You have a sixty-card deck. It has:

  • 3 Aa and 3 Ab cards (6 A cards)
  • 4 B cards
  • 4 C cards
  • 4 Da and 2 Db cards (6 D cards)
  • 14 Ea and 10 Eb cards (24 E cards)

At the begining of the game, you draw 7 cards. Then, at the begining of each turn, you draw one card.

What are the chances of having these cards by these turns?

  1. One E card
  2. Another E card, and a A card
  3. Another E card, and a B card
  4. Two C cards
  5. A D card

It doesn't matter if you drew your D card at the beginning of the game or on turn 5 - as long as you have on turn five, you satisfy the conditions. How would you calculate this?

What if you don't draw a card on your first turn?

  • 0
    Are you familiar with the rule of successive conditioning? If you can apply that, the rest is just a lot of tedious counting.2012-06-13
  • 0
    @TimDuff: No, I'm not - care to explain?2012-06-13

1 Answers 1