Sorry.I don't know enough about convex optimization.
How can I know this function for the $\theta$ vector
$(\theta_0+\theta_1x_1+\theta_2x_2-y_0)^2$
is a convex function?
The other variables are arbitrary constants.
Thanks in advance.
How can I know this simple quadratic function is a convex function?
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convex-optimization
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0If you will rewrite it with no brackets, you will realize, that there are term only of the order 1 and 2. That means that the function is quadratic. Maybe I just didn't understand your question? – 2012-06-13
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0I'm asking why its convex on theta @JohnSmith – 2012-06-13
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0Oh, yeah I has a mistake in my question @JohnSmith – 2012-06-13
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0I still can make no sense of the question (perhaps my bad, though): what is $\,\theta\,$ and where does it appear in the question? What are $\,x_1\,,\,x_2\,,\,y_0$? What's the domain and what the range of this assumed function?? – 2012-06-13