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I was trying to show whether or not the function:

$f: [0,1 ] \rightarrow \mathbb{R}$

$f(x)= \frac {1}{n}$ for $x = \frac {1}{n}$ $(n \in \mathbb{N})$

and

$f(x) = 1$ if the condition isn't satisfied

was integrable, but I'm having trouble figuring out the upper and lower sums. If anyone could point me in the right direction I would appreciate it.

2 Answers 2