The problem is the following:
If $x$ and $y$ are integers such that $\dfrac{4x^2-1}{4x^2-y^2}=k$ is also an integer, does it implies that $k=1$?
This equation is equivalent to $ky^2+(1-k)4x^2=1$ or to $(k-1)4x^2-ky^2=-1$. The first equation is a pell equation (if $k$ is a perfect square) and the second is a pell type equation (if $k-1$ is a perfect square). I've tried setting several values of $k$ to get some solutions but i got nothing. I'm starting to think that $k$ must be $1$.