4
$\begingroup$

$\frac{\pi}{3}e$ is approximately equal to:

2.84657807422452235515451695651552483167829617858837165395986704339307620371911026919085462323682464797125831417055915588210706253023200799687278781793023471514007199829654447617582233348895922031024237096797835826800351909013449542434666218846881388726409761904569405458137658722823724181557439473446917219291006835569333157358766322654791237966966946623595073544349432678461546724384333992745425590086011913751990685057546632872448319697537470763226921527595140181054405265139836753917775379775697089746424785856104245156874061419780994637730604531480206814256732829792410814871969646790020050463395548624913283274551800217089819065169939172989203287463740049502718515202660522891769528913026965548612122163723732564317175312804182112811958680271600871936194429224533157202322236063849980512815661793560779711542728888881905074320...

While $e$ contains a lot of repeating digits - I'd normally expect this to disappear once $\pi$ is introduced.

It almost looks like the further along you go, the greater the degree of repetition.

Is this just due to an interesting interaction that occurs only with decimal approximations of pi and e, or is there more going on?

  • 4
    It does seem curious to me. I didn't see a lot of repeated digits, especially so "early on", for $\pi$ or for $e$.2012-10-24
  • 3
    Any statistics on the frequency of 2-string, 3-string, ..., n-string? (substrings made of $n$ identical numbers)2012-10-24
  • 4
    I believe this is more like numerology than mathematics.2012-10-24
  • 1
    I'll code that up this evening if someone doesn't beat me to it.2012-10-24
  • 4
    This question seems to be another example of how people greatly underestimate just how "clumpy" uniformly random data is.2012-10-24
  • 1
    For what it's worth, the digits shown contain 670 single digits, 67 pairs, 7 triples, and 1 run of six digits.2012-10-24
  • 0
    @RahulNarain: your counts are for disjoint groups. My count of pairs (86) $=$ your count of pairs (67) $+2\times$ your count of triples (7) $+3\times$ your count of quadruples (0) $+4\times$ your count of quintuples (0) $+5\times$ your count of sextuples (1)2012-10-24

1 Answers 1