$$x(t)= A+ A_1\sin (2 \pi f t + \theta ) + A_2\cos (2 \pi f_1 t + \theta )$$ I want to find the Fourier transform $|\mathcal{F}[x(t)]|^2$ . Is this possible by hand? I can find the Fourier transform but then raise to power seems difficult.Is there any shortcut for this ?
Calculate by hand fourier transform of this sort of.
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calculus
fourier-analysis
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0Have you tried the various formulae for the various products $\cos x \sin y,$ etc? – 2012-10-03
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0I'm confused. Are you trying to calculate $\mathcal{F}\{x(t)\}$ and then square it? – 2012-10-03
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0@Pragabhava yes but the real part :) – 2012-10-03