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Consider the following statement: $$\forall \epsilon > 0,\space\exists\delta>0:(|x-a|\lt\delta\implies|f(x)-L|\lt\epsilon).$$ (a) Write the converse of the statement.
(b) Write the contrapositive of the statement.

I am stuck on how to complete these problems because I do not understand the notation

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    Have you read you course notes ?2012-12-06
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    Yes, I still just do not understand where to begin.2012-12-06
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    Do you understand the notation $$\forall x,\exists y:(P\implies Q)\;?$$ That’s all the notation that you need to understand in order to do the problem.2012-12-06
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    So for the converse do I want to say: ∀p,∃q: (X>Y)? And I know that the contrapositive is just the negation of both sides. So, For all x there does not exist a Y where P yields Q? or is it: For all x there does not exist a Y where P does not yield Q?2012-12-06

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