Could someone help me solve the initial value problem
$y'' - xy = x^2 \\ y(0) = 2 ; y'(0) = 1$
by the $\bf method\bf$ $\bf of\bf$ $\bf power\bf$ $\bf series \bf $.
I'm not really sure how to handle the $x^2$ when it isn't being multiplied by some form of $y$. Advice?