I think it would be $\frac{2k}{n^2}$ but I am not sure.
algebra-precalculus
asked 2012-06-07
user id:33184
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11bronze badges
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@Brett, that's not fair! Now everybody else's answers look worse. – 2012-06-07
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In general, blind speculation is not a very good problem solving method. Study the solutions well so that you remember a starting point next time (in this case, it was factoring.) – 2012-06-07
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In general, when reducing a fraction, factoring is your friend. – 2012-06-07
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Since "reducing" is "canceling factors", yes. – 2012-06-07
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Why did you think it was $\frac{2k}{n^2}$? – 2012-06-07
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@TonyK Sorry, the OP had half uppercase and half lowercase. Lowercase just looked better to me. – 2012-06-07