Consider the surface of revolution of the curve $$y = x^2$$ where $0 < x < 1$. By writing a suitable integral, show that the area of this surface is 3.81 units. (You are advised to work in cylindrical polar).
Surface of revolution using cylindrical polars
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calculus
surfaces
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0You are advised not to direct imperatives at us and to formulate questions instead. – 2012-12-02
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0A surface of revolution lives in $3$-space with coordinates $x$, $y$, $z$. What is the axis of revolution in your case? What is the plane containing the curve $y=x^2$ with respect to the axis of revolution? – 2012-12-02