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I can't seem to figure this problem out, there doesn't seem to be enough information.

Find the standard equation of the parabola that has a vertical axis that has $x$-intercepts $-5$ and $3$ and has a lowest point with a $y$-coordinate of $-7$.

I could either do $0 = a(-5 -h)^2 -7$ or $0 = a(3 - h)^2 - 7$ but either way it seems like I don't have enough information. I guess I could just find $a$ in terms of $h$ or viceversa but I feel like there is an easier solution. Any advice?

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    For some basic information about writing math at this site see e.g. [here](http://meta.math.stackexchange.com/questions/5020/), [here](http://meta.stackexchange.com/a/70559/155238), [here](http://meta.math.stackexchange.com/questions/1773/) and [here](http://math.stackexchange.com/editing-help#latex).2012-10-15

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