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I have three points:

$P = (2,5)$

$Q = (12,5)$

$R = (8,-7)$

I need to find the equation of the line thru $R$ which is perpendicular to $PQ$.

How do I do this? $PQ$'s gradient is $\frac{5-5}{12-2}=0$ so the line perpendicular to that has what kind of gradient?

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    They call it analytic **geometry** for a reason. Draw a picture!2012-03-10

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