I have to prove that $\ln(x) > 3*[(x-1)]/(x+1)$ for $x > 1$...
Using Lagrange's theoreme... I have no idea where to start because I dont even have an interval? Can you give me a hint?
I have to prove that $\ln(x) > 3*[(x-1)]/(x+1)$ for $x > 1$...
Using Lagrange's theoreme... I have no idea where to start because I dont even have an interval? Can you give me a hint?