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Let $M\subset \mathbb C^2$ be a hypersurface defined by $F(z,w)=0$. Then for some point $p\in M$, I've $$\text{ rank of }\left( \begin{array}{ccc} 0 &\frac{\partial F}{\partial z} &\frac{\partial F}{\partial w} \\ \frac{\partial F}{\partial z} &\frac{\partial^2 F}{\partial ^ 2z} &\frac{\partial^2 F}{\partial z\partial w} \\ \frac{\partial F}{\partial w} &\frac{\partial^2 F}{\partial w\partial z} & \frac{\partial^2 F}{\partial w^2} \\ \end{array} \right)_{\text{ at p}}=2.$$

What does it mean geometrically? Can anyone give a geometric picture near $p$?

Any comment, suggestion, please.

Edit: Actually I was reading about Levi flat points and Pseudo-convex domains. I want to understand the relation between these two concepts. A point p for which the rank of the above matrix is 2 is called Levi flat. If the surface is everywhere Levi flat then it is locally equivalent to $(0,1)\times \mathbb{C}^n$, so I have many examples....but what will happen for others for example take the three sphere in $\mathbb{C}^2$ given by $F(z,w)=|z|^2+|w|^2−1=0$. This doesn't satisfy the rank 2 condition. Can I have precisely these two situations?

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    Hint: try some examples, e.g. $F=z^2+w^2-2$ at $(1,1)$. If one first derivative is zero and the other is nonzero, you get another example, e.g. $F=e^{zw}-1$ at $(0,1)$.2012-02-28
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    @bgins, hmm.. thanks.. But actually i was reading Levi flat point and Pseudo-convex domain, I want to understand relation of these two concept.... The point $p$ for which above matrix rank is 2 is called is levi flat....If surface is everywhere leviflat then it is locally equivalent to $(0,1)\times \mathbb C^n$.... so i have many examples....but what will happen for others for example take two sphere in $\mathbb C^2$ that is $F(z,w)= |z|^2+|w|^2-1=0$ this doesn't satisfy rank 2 condition.... can i have precisely these two situation ..2012-02-28
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    So you got an answer to http://mathoverflow.net/questions/88782/what-does-non-levi-flat-point-mean-geometrically, but not to http://mathoverflow.net/questions/85178/every-where-levi-flat, I see.2012-02-28
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    @bgins, No, I got answer for both with the help given in the comment in those questions.... But still i am not able to prove the equivalence of various definition of levi flat.... that is why I asked this question to get some clue.... +1 for your first comment.2012-02-28
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    @PradipMishra: I edited the question slightly. I hope that I didn't change the meaning of your last sentence (or of anything else for that matter). I don't have time to think about the answer at the moment, but the definition I am familiar with involves the Levi form. A hypersurface in $\mathbb{C}^2$ has a complex line in its tangent bundle (i.e. the subspace of its tangent space that is invariant under multiplication by $i$). If this is an integrable distribution, then we say it is Levi flat.2012-03-02
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    Levi flat and convex are not the only possibilities. I think you might find the following unpublished book of Cieliebak and Eliashberg to be of interest: http://www.mathematik.uni-muenchen.de/~kai/classes/Stein05/stein.pdf Look especially at Chapter 2. I think section 2.4 will relate to your question, but I am not entirely sure.2012-03-02
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    @SamLisi, thanks for reference.....2012-03-03
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    Can you verify your matrix is correct? If you consider $F(z,w) = z + \bar z$, your matrix is \\[ \begin{pmatrix} 0 & 1 & 0 \\\ 1 & 0 & 0 \\\ 0 & 0 & 0 \end{pmatrix} \\] clearly of rank 2, and this indeed is Levi flat. Now consider $F(z,w) = z \bar z + w \bar w - 1 = 0$ to give the (convex) $S^3$. Now you have \\[ \begin{pmatrix} 0 & \bar z & \bar w \\\ \bar z & 0 & 0 \\\ \bar w & 0 & 0 \end{pmatrix}\\] This also has rank 2. I think that you should have some derivatives with respect to $\bar z$ and $\bar w$ showing up.2012-03-07

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