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How can I verify the following trigonometric identity? $$\frac{\sin^3 A + \cos^3 A}{\sin A+\cos A} = 1-\sin A\cos A.$$

My work so far is $$\begin{align*} &\frac{\sin\cos(\sin^2+\cos^2)}{\sin+\cos}\\ &\frac{\sin\cos(1)}{\sin+\cos} \end{align*}$$

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    Use the [formula for factoring a sum of cubes](http://www.purplemath.com/modules/specfact2.htm) (what you did was incorrect).2012-07-17
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    I think we both saw this formatting problem, Arturo.2012-07-17

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