How to solve these trigonometric equations?
$$\tan2x-\sin4x = 0$$
and
$$\tan2x = \sin x$$
I can't do this, please help me! I did this:
\begin{align} \tan2x &= 2\sin x\\ \\ \frac{\sin2x}{\cos2x} &= \tan x \end{align}
How to solve these trigonometric equations?
$$\tan2x-\sin4x = 0$$
and
$$\tan2x = \sin x$$
I can't do this, please help me! I did this:
\begin{align} \tan2x &= 2\sin x\\ \\ \frac{\sin2x}{\cos2x} &= \tan x \end{align}