A standard deck of 52 cards. It seems obvious that the probability of getting a particular suit (say diamonds) on the first try is 13/52. After that, if we do not get diamonds, our chances are 13/51. But how should we calculate the probability of getting at least once diamonds if we have two attempts?
What are the chances that a particular suit shows up at least once in the first two cards?
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probability
combinatorics
card-games
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5The easiest way is to calculate the probability of **not** getting a diamond in the first two cards and subtract that from $1$. – 2012-09-24