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Could any one help me for this one ?

If $f$ is continuous on $[0,1]$ and $f(0)=1$, then $$\lim\limits_{a\to 0}G(a)=\frac{1}{a}\int_{0}^{a}f(x)dx=?$$

  • 2
    What does the fundamental theorem of calculus say in this case?2012-06-01
  • 0
    What is $G(0)?$2012-06-01
  • 0
    from question isn't it clear that $G(a)=\frac{1}{a}\int_{0}^{a}f(x)dx$?2012-06-01

2 Answers 2