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Suppose you have a standard deck of 52 cards and add a 53rd card which is a “wild card” and can stand for any other card.

  1. What’s the probability of getting a straight?

  2. What’s the probability of getting a flush?

I feel like this increases the complexity to a point at which I'm not sure how to do the problem. It's simple without the wild card.

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    Stop hiding your questions after they have been answered.2012-01-26

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