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I would like to count the below :

$(a^{2}I_{n} + b^{2}I_{n})^{-1}$ * $(aI_{n} bI_{n})$ = ?

Any idea? Note the second bracket is a matrix (1x2) and $I_{n}$ is an identity matrix.

Thanks in advance

  • 3
    How come the second bracket is $1\times2$? The identity matrix, by definition, is a square matrix. So, your two bracketed terms, as well as their products, are square matrices.2012-12-02
  • 1
    I think $(aI_nbI_n)$ is meant to be $(aI_n\ bI_n)$, a matrix with $n$ rows and $2n$ columns.2012-12-03
  • 0
    I see. That makes sense, but we still need the OP to confirm it.2012-12-03

2 Answers 2