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I am trying to find the area of a shaded area for the equations $x = y^2 - 2$ and $x = e^y$

The range in from y = -1 to y = 1

This tells me that I need to find

$$\int_{-1}^{1}y^2 - 2$$ and $$\int_{-1}^{1}e^y$$

$$\int_{-1}^{1}y^2 - 2$$ is $y^3/3 - 2y$ = $-10/3 $ Which is wrong so I am guessing I am suppose to do absolute value so I magic it to $10/3$

$$\int_{-1}^{1}e^y$$ is $e^y$ = $2.71... - .3678...$

Which is obviously wrong and so is the answer I get.

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    What do you want to compute? Two integrals? Or the area between the curves $y = 1$, $y=-1$, $x = y^2 - 2$ and $x = e^y$?2012-04-28
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    I have the picture already, it is provided by the horrible person named Stewart in his book. He cuts it off from y = -1 to y =12012-04-28
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    Oops! My apologies: I misread one of the curves. Ignore my previous comment. You will indeed be integrating from $y=-1$ to $y=1$.2012-04-28
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    I have never voted anything down and won't start to do so, but in my view such a lousy question is an insult to the community.2012-04-28
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    @Christian That isn't at all constructive or helpful. If you want to be an ass I am in chat, you can make fun of me all you want.2012-04-28

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