1
$\begingroup$

Solve for $d$

$$2x-2yd=y+xd$$ $$2(x-yd)=y+xd$$ $$2(x-yd)-y=xd$$ $$\frac{2(x-yd)-y}{x}=d$$ Now I think this is wrong considering I have a $d$ on the other side and I would have to reverse my work and end up at the beginning. Any small pointers or tips? Thanks!

  • 0
    Group all the terms with $d$ in them on one side, and everything else on the other. Factor out the $d$...2012-07-16
  • 1
    Is it; $\dfrac{2x-y}{x-2y}=d$ ???2012-07-16
  • 0
    $\dfrac{2x-y}{x + 2y} = d$, if I'm not mistaken2012-07-16
  • 0
    Oh, right. I wrote the OP wrong in my notebook. Thanks a lot. This was easier than I made it out to be!2012-07-16
  • 0
    You might consider writing up your work in an answer. Then you can accept your own answer (seems funny, doesn't it!) to indicate that this problem is solved.2012-07-16
  • 0
    I re-wrote everything like I always do! I'm a good student!2012-07-16

1 Answers 1

2

(When I said "... write up your work in an answer", I meant like THIS!)

$$2x−2yd=y+xd$$ $$2x - y = 2yd + xd$$ $$2x - y = d(2y + x)$$ $$\dfrac{2x-y}{2y+x} = d$$

(You can formally "accept" any answer by clicking the check mark in the upper left hand corner. If you'd like to wait a few hours/days for a better answer to come along, or write your own, feel free. )