How to solve the equation: $$\frac{2008\cdot2006\cdot2004\cdots1006}{1\cdot3\cdot5\cdots1003}=4^x $$
equation $\frac{2008\cdot2006\cdot2004\cdots1006}{1\cdot3\cdot5\cdots1003}=4^x $
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algebra-precalculus
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2If you mean $$\frac{2008\cdot 2006\cdot 2004\cdots 1006}{1\cdot 3\cdot 5\cdots 1003}=4^x ,$$ replace $.$ with $\cdot$ (\cdot) and $...$ with $\cdots$ (\cdots). – 2012-09-22