Solve $$ 3x^2 - 2y^2 =1 $$ in $ \mathbb{Z}$.
How can we do it?
( All of answers gave me a great help. Thanks a lot kind stackexchangers.)
Solve $$ 3x^2 - 2y^2 =1 $$ in $ \mathbb{Z}$.
How can we do it?
( All of answers gave me a great help. Thanks a lot kind stackexchangers.)