Show that for all $x>0$ we have $\ln(1+x)>x-\frac{x^2}{2}+\frac{x^3}{3}-\frac{x^4}{4}$.
I know it has to do with taylor expansion but somehow I cannot prove it rigorously.
Show that for all $x>0$ we have $\ln(1+x)>x-\frac{x^2}{2}+\frac{x^3}{3}-\frac{x^4}{4}$.
I know it has to do with taylor expansion but somehow I cannot prove it rigorously.