I have $\cos{Q}=-0.5$, required to find $180^{\circ}\leq Q\leq 360^{\circ}$.
What I tried: The acute angle is $60^{\circ}$, then, since cosine is negative on third quadrant, I suppose the value is $180^{\circ}+60^{\circ}=240^{\circ}$. Am I right?
I have $\cos{Q}=-0.5$, required to find $180^{\circ}\leq Q\leq 360^{\circ}$.
What I tried: The acute angle is $60^{\circ}$, then, since cosine is negative on third quadrant, I suppose the value is $180^{\circ}+60^{\circ}=240^{\circ}$. Am I right?