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I know that there is an equation for finding the nth roots of a complex number, which easily done once you have the modulus and argument of the complex number in question. There would be n roots. But how do I know how many solutions there are to an exponential raised to a complex number?

Thanks for any help out there!

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    Use $e^{r\theta}=r\cdot cos (\theta) + r\cdot sin(\theta)i$2012-03-14
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    @you: I am not sure that is quite correct2012-03-14
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    oops! It's too late for me to edit it now. I mean "$re^{i\theta}$"2012-03-14

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