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The 'ring of differential operators wrt x' ?

Thx.

  • 10
    The ring of *linear* differential operators *with constant coefficients*, rather.2012-06-25
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    @MarianoSuarez-Alvarez: Isn't $\mathbb{C}[d/dx]$ only *isomorphic* to the aforementioned ring?2013-01-01
  • 0
    It depends on what, exactly, the notation means, really.2013-01-01

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