0
$\begingroup$

Need the formula to find $x$ in the below equation.

$$\frac{A_1}{(1+x)^{y_1}} + \frac{A_2}{(1+x)^{y_2}} + \frac{A_3}{(1+x)^{y_3}} + \cdots + \frac{A_n}{(1+x)^{y_n}} = 0\;(\mbox{or }0.0001)$$

where $A_1,\dots,A_n$ can be any real numbers.

$y_1,\dots,y_n$ can be any numbers between 0 and 1 (including 0 and 1).

  • 0
    @AustinMohr A's can be negative2012-11-03
  • 2
    What makes you think there is such a formula?2012-11-03

2 Answers 2