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Can the Surface Area of a Sphere be found without using Integration?

A ball is effectively a pyramid with "curved" based. If we know the surface, which is $O=4 \pi r^2$, we know the volume, which is $V=\frac{1}{3} \cdot A \cdot r = \frac43 \pi r^3$

I know I can derive the surface of the ball with calculus. Is there another way?

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    Some geometrical approach is given in robjohn's answer [here](http://math.stackexchange.com/questions/164/why-is-the-volume-of-a-sphere-frac43-pi-r3/194953#194953).2012-11-21
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    It depends on what you call calculus. Archimedes showed it was the same as the curved surface area of the surrounding cylinder so $2\pi rh = 4 \pi r^2$.2012-11-21
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    Similar question: [Can the Surface Area of a Sphere be found without using Integration?](http://math.stackexchange.com/q/73348/752).2012-11-21

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