So there are 480 squares and 99 mines on the advanced level of minesweeper. It got me thinking, what would be the chances of winning the game randomly clicking each square? So not being influenced by numbers and without it doing any multi openings, so you would need to click 381 boxes (I think) :)
Minesweeper, random odds.
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probability
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1The number of mines is fixed: $99$. The probability of hitting a mine at first click is therefore $99/480$. Provided that you survived the first click, the probability of hitting a mine on the second click is $99/479$. The probability of surviving $n$ clicks, with $1\leq n\leq 381$, is therefore $1 - 99^n/\prod_{i=0}^{n-1}(480-i)$. – 2012-02-18
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1Hitting a mine at first click is impossible in the Minesweeper that comes with Windows. – 2012-02-18
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0I was like "Oh so that's the... wait NOW WE MUST RECALCULATE IT ALL OVER! – 2013-05-08