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Give all solutions of the system of congruences:

$$x \equiv 3 \pmod 5 $$ $$x \equiv 2 \pmod 4$$ $$x \equiv 5 \pmod 7$$

Then give the least strictly positive solution.

  • 0
    Since this is HW, can you please tell us what you have tried?2012-09-30
  • 0
    I know that I have to find a corresponding x that solves all three. To do so I have to find one for the first two.2012-09-30

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