Given the geometric series
$\frac{1}{1-z} = \sum_{n=0}^n = 1 + z + z^2 + ...$
If there is a function $f(z)=\frac{1}{z+j}$ how would you get it's Taylor series about center z = 1? I have tried the following to get it into the form of $\frac{1}{1-(z-z_0)}$
$$f(z) = \frac{1}{1-(z-1)+j-2)}$$
but that is clearly not right, or i don't think it is anyway.
Could I get some hints as to how to proceed?