0
$\begingroup$

The following problem is giving me trouble:

  • Suppose $X \subset \mathbb{A}^{n}$ is an affine algebraic set, and $S \subset X$ is a subset. Show that if $\bar{S}$ is the closure of $S$ in the Zariski topology, then $\bar{S}= V(I(S))$.

I have no idea where to start.

  • 1
    Remember that the closure of a set $S$ is the smallest closed set containing $S$2012-05-03

1 Answers 1