0
$\begingroup$

if $a^2bc^3 = 25$ and $ab^2= 5$, how would you find $abc$?

Is there a formula of which these are a part of? What I've done is this:

$$abc^3 = \frac{25}a\quad\implies\quad abc = \frac{25}{ac^2}$$

But how would I use the $ab^2$?

  • 0
    Please use Latex2012-12-11
  • 0
    What you wrote was unambiguous, but it would be a good idea to learn the basics of $\LaTeX$ so as to make your posts more readable; you can get a very good start [here](http://meta.math.stackexchange.com/questions/5020/mathjax-basic-tutorial-and-quick-reference).2012-12-11
  • 0
    @Brian M. Scott Thanks, I'll sure take a look at that2012-12-11

1 Answers 1

1

Note that $\left(a^2bc^3\right)\left(ab^2\right)=a^3b^3c^3=(abc)^3$. Can you finish it from here?