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For what values of $t$ is the speed of the particle increasing?

I tried to find the first derivative and I get $$6t^2-48t+90 = 0$$ $$ t^2-8t+15 = 0$$

Which is giving me $ t>5$ and $0 < t < 3$, but the book gives a different answer

  • 0
    Calculus and algebra-precalculus? That seems contradictory :-)2012-03-04
  • 1
    Speed is increasing, is not the same as position is increasing.2012-03-04

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