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Possible Duplicate:
Limits without l'Hôpital

I have a limit which is to be evaluated without using l'Hôpital's rule or series expansion. $$ \lim_{x \rightarrow 0}\frac{\frac{\sin x}{x} - \cos x}{2x \left ( \frac{e^{2x} - 1}{2x} - 1 \right ) }$$ Is it possible to evaluate it without l'Hôpital's rule or series expansion only using trigonometric and algebraic manipulation?

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    i think this is a duplicate .2012-06-13
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    can you send the link?? ... to the original ... i'll delete the question2012-06-13
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    Lol ... you are right ... i sounded like 'lopital' ... though they taught L hospital ... in school ... lol :D2012-06-13
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    how do i eliminate those e's??2012-06-13
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    Lol ... when did he ask??? he never told me2012-06-13
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    i would still like to know it ... without expanding ... if it's possible2012-06-13

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