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If the value of my answer when I compute the limit of a function as it tends to c is 0. Not infinity. Is it then continuous?

That is the limit as $x$ tends to $90$ in the function $f(x) = \cos (x)$

The answer of the above is 0, is the function continuous at 90? Thanks

Edit: Please determine the continuity or otherwise of $$f(x) = \frac{x-36}{\sqrt x - 36}$$ at the point x = 36.

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    You want to say, I suppose, "as $x$ tends to $90^\circ$". Yes, the function is continuous at $x=90^\circ$, since $\lim\limits_{x\rightarrow90^\circ}\cos(x)=0=\cos(90^\circ)$.2012-06-06
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    Do you really mean $$\frac{x-36}{\sqrt{x}-36}\ ?$$ Or do you mean $$\frac{x-36}{\sqrt{x}-6}\ ?$$2012-06-06
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    @Mob: If you add material to the question that *substantially* changes the question, then please indicate so explicitly.2012-06-06
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    The former. Just how it is in the question.2012-06-06

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