I'm having trouble with integrating this function. Could someone please add the steps to get to the answer? Initial condition $y(0) = 2$.
$y' = 4e^{0.8t}-0.5y$
Answer:
$y= 4/1.3(e^{0.8t} - e^{-0.5t}) + 2e^{-0.5t}$
I'm having trouble with integrating this function. Could someone please add the steps to get to the answer? Initial condition $y(0) = 2$.
$y' = 4e^{0.8t}-0.5y$
Answer:
$y= 4/1.3(e^{0.8t} - e^{-0.5t}) + 2e^{-0.5t}$