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Obtain the equation of right circular cylinder with radius of the base as 2 units. Its axis passes through $(1, 2, 3)$ and direction cosines are given as $(2, -3, 6)$

I got $45x^2+40y^2+13z^2+12xy-36yz-24zx-42x-280y-126z+294 = 0$

  • 0
    Formula 9 or formula 10 from [here](http://mathworld.wolfram.com/Point-LineDistance3-Dimensional.html) would be useful...2012-07-08
  • 0
    As $2^2+3^2+6^2=7^2$ the correct direction cosines are $(\frac 27, \frac {-3}7, \frac 67)$2012-11-18

2 Answers 2