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We have $$W = 10 + 0.895m -12.33c^{0.18} + 12.33c^{0.18}$$

we calculate the differential of m, which is $0.895$ and the differential of $c$, which is something like $$-12.33/c^{0.82} + 12.33/c^{0.82}$$ and what then?

what do we do with $c$. I am confused...

  • 2
    The way you've written it, the terms involving $c$ cancel out.2012-11-10

1 Answers 1