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dy/dx = k(L-y) where k and L are constants y(0)= 0

How does one find the integral for this and whats the reasoning please?

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    this looks like a differential equation to me2012-10-21
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    This has been answered many times on this site already...2012-10-21
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    $dy/dx=f(x)g(y)$ gives $dy/g(y) = f(x)dx$ if $g(y)\ne 0$.2012-10-21
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    See here, for a similar example: http://math.stackexchange.com/a/43176/12422012-10-21

2 Answers 2