Supremum of an union of bounded sets
7
$\begingroup$
Given
$A$
,
$B$
are bounded subsets of
$\Bbb R$
. Prove
$A\cup B$
is bounded.
$\sup(A \cup B) =\sup\{\sup A, \sup B\}$
.
Can anyone help with this proof?
real-analysis
analysis
asked
2012-10-20
user id:43902
73
3
3silver badges
7
7bronze badges
1
(1) is very, very easy, and (2) isn’t much harder; do you have any ideas at all about how to proceed?
–
2012-10-20
0
I am very positive that I got 1. But I am not sure how to start with the (2) one.
–
2012-10-20
2 Answers
2
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