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Let $A$ and $B$ be arbitrary non-empty sets and let $F\colon A\to P(B)$, be an arbitrary function which covers $B$ in the sense that $\forall b \in B$, $\exists a \in A$ such that $b \in F(a)$ holds.

Using axiom of choice show there exists a function $G: B \rightarrow A$ ,such that for all $b\in B$, $b \in F(G(b))$

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    I'm having trouble understanding why you flagged your own post to say it was one of your own exam questions. If this is an ongoing exam, this seems like a breach of confidence and I advise you to remove your question. If not, then there is no reason to flag it.2012-11-30

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