How does the transform rule help us solve this problem? Does this just mean I can rewrite the problem as:
$$\mathcal{L}^{-1}\left\{\frac{6}{(s+3)(s+3)}\right\} = \int_0^t \frac{6}{\tau(\tau+3)(\tau+3)}d\tau$$
Which I can then do what with?
How does the transform rule help us solve this problem? Does this just mean I can rewrite the problem as:
$$\mathcal{L}^{-1}\left\{\frac{6}{(s+3)(s+3)}\right\} = \int_0^t \frac{6}{\tau(\tau+3)(\tau+3)}d\tau$$
Which I can then do what with?