I am trying to find $f(x)$ if I know that $$f''(x) = -2+12x-12x^2, \quad \; f(0)=4,\ f'(0)=12 $$
First I found the first derivative $$ f'(x)= -2x+6x^2-4x^3+C$$
and then I found the function, which is: $$f(x)=-x^2+2x^3-x^4+Cx+D$$
Now I am lost as to what to do with those values they gave me $ f(0)=4,\ f'(0)=12 $
Where do i proceed from here?