Btw, please don't give me the answer. I just wanna know how to raise a logarithm to its cube cause I'm stuck in this part, but don't solve it for me.
$$\log \sqrt[3]x = \sqrt[3]{\log x}$$ I tried different ways but. When I input the values in my calculator, it just doesn't match.
My answer: is it right? $$1/3\log x =\sqrt[3]{\log x}$$ $$\log x = 3\sqrt[3]{\log x}$$ $$a = 3\sqrt[3]{\log x}$$ $$a^3 = \log x^{27} $$ $$\log x^3 = \log x^{27}$$ $$\log x^{24} = 0$$ $$ x = \sqrt[24]{1}$$ $$ x = 1$$