I am reading this page about logarithm: http://www.andrews.edu/~calkins/math/webtexts/numb17.htm
And saw this piece of transformation:
$$\log_b(\frac{2x^2 + 2x}{12}) = 0$$
Take exponents of both sides, yielding:
$$\frac{x^2 + x}{6}= b^0$$
$$\frac{x^2 + x}{6} = 1$$
I understand where $b^0$ comes from, but could not understand how it became $1$ on the third line.
Can anyone explain?
Much appreciated!