2
$\begingroup$

I read the above recently. What is this '$p$-component'? What does the double '$\|$' mean? It looks like divide '$|$' but not quite. I understand $p^k | a^t - 1$ but not $p^k\|a^t - 1$

  • 2
    It's from [this answer.](http://math.stackexchange.com/a/156614/242)2012-06-17

3 Answers 3