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I would appreciate it if anyone could tell me if what I am doing is correct The question is:

Which is greater $1$ or $|x|$ if $x^2+2y^2=2$ and $y=\frac{1}{2} $

Here is what I go after simplifying $x = \pm \sqrt{\frac{3}{2}}$ = $\pm1.2250$

Thus $|x|=1.2250$ which is greater than $1$.

However the text says that $1$ is greater than $|x|$ , should I consider that a misprint ?

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    Your computation looks right to me.2012-07-12
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    The fact that $x^2 > 1$ immediately gives that $|x| > 1$. To see this, $x^2 = |x|^2$, and is increasing for positive $x$. Yeah though your work seems to pan out.2012-07-12

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