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The equations I have are

$\phi=(-ag/\omega)\cos(kx)\sin(\omega t)e^{kz}$

and

$\eta=a\cos(kx)\cos(\omega t)$

I know that $d\phi/dz=d\eta/dt$

but when I partially differentiate and rearrange I get

$gk e^{kz}= \omega^2$ and I don't know how to get rid of the exponential function.

  • 0
    How does $h$ enter your equations? Do the parameters depend on $h$?2012-11-26
  • 0
    The original equation is $\phi=-ag/\omega cos(kx)sin(\omega t) (cosh(k[z+h])/ cosh(kH))$ but as h tends to inifity $\phi$ simplifies to the equation in the question.2012-11-26
  • 0
    Do you know why the original equation simplifies as h tends to infinity? How do I show that the original equations simplifies as h tends to infinity?2012-12-08

0 Answers 0