0
$\begingroup$

If $g$ is one-to-one and $f$ is onto, then we can't say anything about $f \circ g$, correct?

and if $f\circ g$ is one-to-one and onto, then $g$ is one-to-one and $f$ is onto?

$$g(x) > f(g(x)) = f \circ g$$

$A > Z$ and $Z > B$

we need to look at set $A$ (all elements of $A$ have to map to one unique element of $Z$ to see whether a function $g$ is one-to-one and set $B$ to see if $f$ is onto (there's an arrow to every elements).

Just wanted to make sure I understood correctly.

  • 0
    What do you mean by $g(x) > f(g(x))$?2012-11-04
  • 0
    its an arrow one function to the other2012-11-04

1 Answers 1