Suppose that I had to find $\log_{10}(8952!)$. Now, since $\log(a) + \log(b) = \log(ab)$, this can be rewritten to the following summation:
$$\sum_{x=1}^{8952}{\log_{10}(x)}$$
Would there be a general way to compute this in terms of $\log_{10}(x)$?