Given $2x^2 + y^2 = 4$, find $y''$. I found the first derivative which is $y' =$ ${-2x}\over y$.
I then got to $2(xy' - y)\over y^2$ and I don't know where to go from there.
Given $2x^2 + y^2 = 4$, find $y''$. I found the first derivative which is $y' =$ ${-2x}\over y$.
I then got to $2(xy' - y)\over y^2$ and I don't know where to go from there.