$L^2([0,1])$ is a set of first category in $L^1([0,1])$?
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How to show that $L^2([0,1])$ is a set of first category in $L^1([0,1])$?
Thank you.
functional-analysis
asked 2012-05-02
user id:30491
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Welcome to Math.stackexchange. People can help you better if you tell us what you have tried to do, what your thoughts are, your guesswork, or any relevant information, really! – 2012-05-02
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Also answered here: http://math.stackexchange.com/a/18404 – 2012-05-02
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generic solution to all such problems: use the open mapping theorem. 2nd category implies onto. – 2012-05-02
1 Answers
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