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My question is about the function $f(z)=e^{-z^2}$. Is it everywhere continous? Holomorphic?

Thanks,

Dan

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    Short answer: Yes.2012-12-06
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    Try [Cauchy–Riemann equations](http://en.wikipedia.org/wiki/Cauchy–Riemann_equations)2012-12-06

2 Answers 2