Let the least square problem be $Ax=b$. If the vector $v$ satisfies $A^*v=0$, why does adding a multiple of $v$ to the right hand side $b$ does not change the solution, e.g., $Ax=b+tv$, for $t$ a constant?
Thanks.
Let the least square problem be $Ax=b$. If the vector $v$ satisfies $A^*v=0$, why does adding a multiple of $v$ to the right hand side $b$ does not change the solution, e.g., $Ax=b+tv$, for $t$ a constant?
Thanks.