2
$\begingroup$

For distributions the scaling property, $f(ax) = \frac{1}{|a|} \mathcal{F(\frac{u}{a})}$, of the Fourier transform is no longer true. Is there a source that lists which properties of the Fourier transform remain true even for distributions and which are false?

  • 3
    Are you sure about the failure of the scaling property?2012-12-22
  • 0
    I agree with Guiseppe. The scaling property is commonly exploited with Dirac delta functions.2012-12-22

1 Answers 1