How do I find the arch length of
$$x^{\frac{2}{3}}+y^{\frac23}=1$$
The hint given was "4x the arc in first quadrant"
I think I am supposed to use the formula:
$$L=\int^b_a \sqrt{1+(f'(x))^2} dx$$
I tried plotting the equation in a graphing utility like https://www.desmos.com/calculator, which results in an error.
So I tried expanding the term :
$$y=\sqrt{(1-x^{\frac{2}{3}})^3} = \sqrt{1-2x^{\frac{2}{3}}-x^2}$$
Then how do I proceed? Complete the square? Doesn't look likes its in an appropriate form?