A couple questions on my homework I'm struggling with are as follows. If anyone could help me with these that would be awesome
$$\frac{dy}{dx} + 3y = 12x+19,\qquad y(0)=-4.$$
$$\frac{dy}{dx}=(4x+9y)/3x\qquad y(1)=2$$
Sorry but here's another that I seem to be getting wrong. $$\frac{dx}{dy}=(x−8)e^{−2y} \qquad y(8)=\ln(8)$$
The solution I get is $y=\ln(2x^2-16x+64)/2$ but apparently that's wrong
Thanks