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Possible Duplicate:
prove that $(2n)!/(n!)^2$ is even if $n$ is a positive integer

Show that $\binom{2n}{ n}$ is divisible by 2?

Any help would be appreciated..

  • 0
    The answers here might help: http://math.stackexchange.com/questions/78533/prove-that-2n-n2-is-even-if-n-is-a-positive-integer2012-02-28
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    $\binom{m+1}{k+1}=\frac{m+1}{k+1}\binom{m}{k}$.2012-02-28
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    See the following quesiton: http://math.stackexchange.com/questions/78533/prove-that-2n-n2-is-even-if-n-is-a-positive-integer2012-02-28
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    it is not a doublicate! Here is the solution by the way: https://math.stackexchange.com/q/2377961 Apply 2) and you are good!2017-07-31

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