How can I prove that for all $t\in[0,\frac{\pi}{2}], \cot^2t\leq\frac{1}{t^2}\leq1+\cot^2t$, with $\cot$ the cotangent function ? Thank you
Inequality for $\cot$
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trigonometry
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0Are you sure you have written the inequality right? – 2012-01-11
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0Pretty much, yes. Why ? – 2012-01-11
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0I think we can derive a simpler inequality to prove from the given inequality, and prove it by derivatives or similar. – 2012-01-11