How many ordered pairs of $(x, y$) exist in the following case?
$$\cos(x+y) = 1/e$$
$$\cos(x-y) =1$$
where both $x, y$ are less than or equal to pi.
How many ordered pairs of $(x, y$) exist in the following case?
$$\cos(x+y) = 1/e$$
$$\cos(x-y) =1$$
where both $x, y$ are less than or equal to pi.