$x$ is a positive integer less than $100$. When $x$ is divided by $5$, its remainder is $4$. When $x$ is divided by $23$, its remainder is $7$. What is $x$ ?
What is the best way to solve a problem given remainders and divisors?
3
$\begingroup$
algebra-precalculus
-
0ah yeah that makes sense. I thought maybe there was a way outside of brute force, but that is extremely simple and fast – 2012-08-25