Find $y'$ if $\sin(x+y) = \cos(xy)$. I got ${-\cos(x+y)\over \sin(xy) * (x+y)}$. Please use Implicit Differentiation. Did I get the answer right?
Find $y'$ if $\sin(x+y) = \cos(xy)$
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implicit-differentiation
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0ok ${-ysin(xy)-cos(x+y)\over cos(x+y)+xsin(xy)}$ correct? – 2012-10-16
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1It is fine now. – 2012-10-16