Let $a=\pmatrix{1\\1}, b=\pmatrix{1\\2}, c=\pmatrix{2\\1}$. Solve $xa + yb = c$ for $x, y \in \mathbb{C}$.
Does this mean I do $$1x+1y=2$$ $$1x+2y=1$$ and would be the final answer?
Let $a=\pmatrix{1\\1}, b=\pmatrix{1\\2}, c=\pmatrix{2\\1}$. Solve $xa + yb = c$ for $x, y \in \mathbb{C}$.
Does this mean I do $$1x+1y=2$$ $$1x+2y=1$$ and would be the final answer?