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I'm trying to do the problem

3√40x^4/y^9.

When you try to reduce the index for 40^4, its going to be 4/3. How does the index get reduced into 2x√5x? I understand 3 cubed of 40, but what happens to the 4/3

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    It's hard to understand what you have written. Do you mean $\root3\of{40x^4/y^9}$?2012-09-17

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