Can someone walk me through how to do the following problem so I can attempt a few more practice problems?
If: $$\int_{1}^{5} f(x) dx = 12 $$ and $$\int_{4}^{5} f( x) dx = 3.6$$ find: $$\int_{1}^{4} f( x) dx$$
Would it simply be $12 - 3.6$ ?
EDIT
If: $$\int_{0}^{9} f(x) dx = 37 $$ and $$\int_{0}^{9} g( x) dx = 16$$ find: $$\int_{0}^{9} 2f(x)+3g(x) dx$$
Would this simply be: $2 \times 37 + 3 \times 16$?