How in this situation (presented in image) can I prove that $|CA|+|CB|=2|AB|$?
Proving that $|CA|+|CB|=2|AB|$ in a general $ABC$ triangle
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geometry
euclidean-geometry
triangles
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0Is $\Delta ABC$ equilateral? – 2012-11-01
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0We don't know if it is equilateral. – 2012-11-01
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0So maybe if we can't proove that a=b, can we proove that |CB|+|CA|=2|AB|? If yes, how? – 2012-11-01
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0If someone had find topic with this question it would be really nice to post a link here. – 2012-11-01
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0Does anybody has a link for the topic with this question? I've heard it was discussed on this forum, but I can not find it here. – 2012-11-02