3
$\begingroup$

I don't understand why the set of natural numbers constitutes a commutative monoid with addition, but is not considered an Abelian group.

  • 1
    What is the additive inverse of $n\neq 0$?2012-12-07
  • 32
    It's not a nonabelian group. It's an abelian nongroup.2012-12-07
  • 1
    Note that $\mathbb N$ is not considered a group (even less an abelian group), but your question title suggests that it is considered a non-abelian group - no it isn't even a non-abelian group.2012-12-07
  • 0
    Such a "great" question deserves more than 3 upvotes!2012-12-09

4 Answers 4