$$\frac{10}{r-3}+\frac4{3-r}=6$$
I am not sure how to solve this equation I know both that both denominators on the left side if multiplied by negative 1 equal the other one.
$$\frac{10}{r-3}+\frac4{3-r}=6$$
I am not sure how to solve this equation I know both that both denominators on the left side if multiplied by negative 1 equal the other one.