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Suppose $p(0,0)=\frac{1}{18}$, $p(0,1)=\frac{3}{18}$, $p(1,0)=\frac{4}{18}$, $p(1,1)=\frac{3}{18}$, $p(2,0)=\frac{6}{18}$, $p(2,1)=\frac{1}{18}$.

Does $E[X|Y]= E[X]$ and $E[Y]= E[Y|X]$?

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    What is left to explain after the answers you received here?2012-04-28

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