4
$\begingroup$

Let $f:\mathbb R\to\mathbb R$ be a function with the property that $f(a+b)=f(a)+f(b)$ for all real numbers $a$ and $b$. Assume that the limit as $x\to 0$ of $f(x)$ is equal to some real number $L$. Show $L=0$.

I started to attempt to use the epsilon-delta definition of continuity, but I'm stuck. Please help!

Edit: While I know that the functions for which this is true are, for example, $f(x)=cx$, I can't assume anything that is not given.

  • 0
    Is $f$ continuous?2012-12-13
  • 0
    @kneidell I don't think you need continuity, just that $\lim_{x\to 0} f(x)$ exists. There are definitely functions of this sort which are not continous on all of $\mathbb R$, but are continuous at $0$.2012-12-13
  • 0
    (I should have said, assuming axiom of choice, there are definitely functions of this sort... Basically, you just need a basis of $\mathbb R$ as a vector space over $\mathbb Q$ to get non-continuous examples. Indeed, you don't need even a basis, just a representation of $\mathbb R\cong V\oplus W$ where $V$ and $W$ are two non-trivial $\mathbb Q$-vector spaces.2012-12-13

3 Answers 3