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1) Removable discontinuity at $x=8$; vertical asymptote at $x=7$.

2) $\lim\limits _{ x\rightarrow 0 }{ f\left( x \right) } =\frac { 2 }{ 9 }$ ; vertical asymptote at $x= -9/4$

3) Hole at $(-4, 2)$

4) Vertical asymptote at $x= 2$; hole at $(6,3)$

Could you please provide a solution to each condition?

Thanks very much

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    What do mean by a hole?2012-07-02
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    @Marvis Removable discontinuity.2012-07-02
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    I am guessing those are supposed to mean removable discontinuity. I don't know how to make an equation for each requirement though.2012-07-02

3 Answers 3