How would I show that $|\sin(x+iy)|^2=\sin^2x+\sinh^2y$?
Im not sure how to begin, does it involve using $\sinh z=\frac{e^{z}-e^{-z}}{2}$ and $\sin z=\frac{e^{iz}-e^{-iz}}{2i}$?
How would I show that $|\sin(x+iy)|^2=\sin^2x+\sinh^2y$?
Im not sure how to begin, does it involve using $\sinh z=\frac{e^{z}-e^{-z}}{2}$ and $\sin z=\frac{e^{iz}-e^{-iz}}{2i}$?