$$3^{1 + 2\log_3(y-x)} = 48$$ With this problem I have difficulty getting rid of the exponent.
$2\log_5(2y - x - 12) = \log_5(y-x) + \log_5(y + x)$
$$3^{1 + 2\log_3(y-x)} = 48$$ With this problem I have difficulty getting rid of the exponent.
$2\log_5(2y - x - 12) = \log_5(y-x) + \log_5(y + x)$