3
$\begingroup$

Using the Logarithmic Differentiation find the derivative of $y=\sqrt{x(x-1)/(x-2)}$...so I tried,but the result is not correct..can you show me a hint?

so $\ln y= 0.5\ln[x(x-1)/(x-2)]$

$$\ln y=0.5[\ln x+\ln(x-1)-\ln(x-2)]$$

$$\ln y=0.5\ln x+0.5\ln(x-1)+0.5\ln(x-2)$$

$$y'=0.5\ln x+0.5\ln(x-1)-0.5\ln(x-2)[\sqrt{x(x-1)/(x-2)}]$$

  • 0
    I gave your question a more descriptive title, and added the `calculus` tag.2012-11-20
  • 0
    Check the plusses and minuses in the third row. Also, it'd be helpful if said what you got when you went on, instead of just saying it's not the same as what you want...2012-11-20
  • 0
    Your last line should be $y'=\frac 12 \left(\frac 1x+\frac 1{x-1}-\frac 1{x-2}\right)\sqrt{x(x-1)/(x-2)}$ (you forgot to differentiate the $\ln$ terms and the parenthesis).2012-11-20

2 Answers 2