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Use inverse function theorem to evaluate $d/dx \arcsin(x)$.

How is this any different then finding it using implicit differentiation? Thanks!

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    Do you mean the theorem that gives the derivative of the inverse of $f$ in terms of $f$? It's different in that you are just using a formula to obtain the derivative. Of course, the second step when using implicit differentiation brings you that formula.2012-04-12

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