2
$\begingroup$

Can any general formula (dependent on $n$) be derived for this expression:

$$\sum_{k = 1}^n 2^k k^2$$

If yes , then how we determine that any series can be converted into formula and what are ways to do that.

  • 1
    I am new to this group and don't know how to add characters like Sigma and all , that's why wrote this expression like that. Please also tell me how you write such characters .2012-07-17
  • 1
    if you edit your question, you can see what the source format looks like. You can cancel the editing if you want after your curiosity is satisfied.2012-07-17
  • 0
    @tesla You should take a look at some of the links given in the answers to [this question](http://meta.math.stackexchange.com/questions/1773/do-we-have-an-equation-editing-howto).2012-07-17
  • 0
    See http://math.stackexchange.com/questions/30732/how-can-i-evaluate-sum-n-1-infty-frac2n3n1 and http://math.stackexchange.com/questions/50919/calculate-the-sum-of-the-infinite-series-sum-n-0-infty-fracn4n.2012-07-17

2 Answers 2