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Highest power of a prime $p$ dividing $N!$

In decimal form, the number $100!$ ends in how many consecutive zeroes. I am thinking of the factorization of $100!$ but I am stuck. I try to count them and since there are 10, 20, 30,..., 100, there are at least 11 zeros. How should I proceed.

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    And also this http://math.stackexchange.com/questions/17916/how-come-the-number-n-can-terminate-in-exactly-1-2-3-4-or-6-zeroes-but-n/17917#179172012-11-03
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    See also this nice answer: http://math.stackexchange.com/a/216002/289002012-11-03

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