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Solve for a, b, c, and d in the equation:

$\left(\begin{array}{cc} 2 & -6 \\ -a & 8 \end{array}\right) = \left(\begin{array}{cc} 2b & 4c \\ 15 & 3d \end{array}\right)$

$2b/2 = 2/2 \rightarrow b = 1$

$4c/4 = -6/4 \rightarrow c = -1.5$

$-a/1 = 15/-1 \rightarrow a = -15$

$3d/3 = 8/3 \rightarrow d = 2.667$

Is that correct? OR

$4c = -6$

$-a = 15$

$2b = 2$

$3d = 8 $

$-a = (-1)\times 15 = -15$

$2b = 2\times 2 = 4$

$4c = 4\times (-6) = -24$

$3d = 3\times 8 = 24$

$\left(\begin{array}{cc} 4 & -24\\ -15 & 24\end{array}\right)$

4 Answers 4