$ \sin(2x) \cdot \cos(2x) + \sin(2x) = 0 $
In the correction model I have something I don't understand is done in the first step:
$ \sin 2x(\cos 2x + 1) = 0 $
Is this step correct? And can someone explain that step to me?
$ \sin(2x) \cdot \cos(2x) + \sin(2x) = 0 $
In the correction model I have something I don't understand is done in the first step:
$ \sin 2x(\cos 2x + 1) = 0 $
Is this step correct? And can someone explain that step to me?