Say you have a function: f (m,n)
f (m,n) = m if n = 1 f (m,n) = n if m = 1 otherwise f (m,n) = f (m - 1, n) + f (m, n - 1)
Pre-calculated value:
1 2 3 4 5 6 2 4 7 11 16 3 7 14 25 4 11 25 5 16 6
Just wondering if there could be formula of f(m,n)
, instead of doing a dynamic progrmming or recursive calculation to get the value.