I am trying to solve the following equation:
$$(t+4)dx=4(1+x^2)dt$$
As far as I can remember I have to move x to left and t to right and form an integration. What should I do? Does deviding both side by $(t+4)$ helps? what will be next?!
update
ok as mrf suggested I came to this:
$$\int \frac 1{1+x^2}\,dx = 4\int\frac 1{t+4}\,dt$$
This will be:
$$\tan^{-1}(x)+C == $$
I am not sure about right side...any tips?!