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A Cone whose vertical angle is $\pi/3$ has its lowest generator horizontal and filled with a liquid. Prove that the pressure on the curved surface is $\frac{W\sqrt{19}}{2}$, where $W$ is the weight of the liquid.

From my view: I would also like to find out the center of pressure, for my conceptual clarity.

SUBNOTE: I am using SL Loney "The elements of Statics and Dynamics" and it doesnt have hydrostatics portion. Can you suggest me some good book, which handles hydrostatics etc ?

Soham

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    What do you mean by 'has its lowest generator horizontal'?2012-07-15
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    Its lying horizontal on a plane. The term highest or lowest doesnt make much sense if its standing up.2012-07-15
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    A cone is generally characterized by a height and a radius. You said 'vertical height'. Did you mean radius, diameter? What is a 'lowest generator'? Also, you might want to consider a more recent text, Loney's is from 1932...2012-07-15
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    I am so sorry, it was a very bad typo. I meant vertical angle as $\pi/3$ and not vertical height. Here vertical angle means the apex angle. Can you suggest a book.2012-07-15
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    I used Massey's "Mechanics of Fluids", but this was in the late '70s. I don't have enough point of comparison to know whether or no it is a 'good' book. It was focused more on the engineering issues rather than physics.2012-07-15
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    @copper.hat I also have an engineering background, and dealt with things from a more engineering perspective.2012-07-15

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