4
$\begingroup$

I've already proven that if we assume f is bijective and g is bijective, then $(g \circ f)$ is bijective. I've also proven that$(g \circ f)^{-1}$ exists. I'm stuck on this part, however. Any suggestions?

  • 0
    Do you know the rule for groups? The proof here is the same.2012-12-04

3 Answers 3