I have a triangle and I know the coordinates of two vertices: $A=(x_1,y_1), B=(x_2,y_2)$
All the angles: $ABC = 90^\circ, CAB = 30^\circ$ and $BCA = 60^\circ$ and all the edge lengths. How can I find the coordonates of the third verix $C=(x_3,y_3)$?
I know there are two solutions (I want both).
Thank you.