Given a triangle $\Delta ABC$ with angle $\angle ACB=90^\circ$. The bisector of $\angle ACB$ intersects $AB$ at $L$. If $AC=4 \operatorname {cm}$. and $BC=5 \operatorname {cm}$, find the distance between the orthocenter $H_1$ of $ALC$ and the orthocenter $H_2$ of $BLC$.
Distance between orthocenters
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geometry