Let $ f: \mathbb{R}^{2} \rightarrow \mathbb{R}^{2} $ be a bijective function. If the image of any circle under $ f $ is a circle, prove that the image of any straight line under $ f $ is a straight line.
A bijection from the plane to itself that takes a circle to a circle must take a straight line to a straight line.
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$\begingroup$
geometry
functions
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2Where is this problem from? – 2012-10-14
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0This problem was a question some of my classmates and I discussed over tea-time. We have regular discussions like this. Have you seen it somewhere before? – 2012-10-14
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0Mostly I'm wondering if you happen to know for a fact that this is true (e.g. because it was stated in a book of problems somewhere) or just believe it to be true. – 2012-10-14
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0I'm not sure if this was obtained from a book. However, someone in my group mentioned that this was a folklore result and that he had seen a proof of it in some article. None of the rest of us could find a proof ourselves, and that fellow had trouble remembering the article where he had seen the proof. – 2012-10-14
1 Answers
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This has the result (second page). I hope it's thorough enough to placate your curiosity...
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0Thanks! You've provided a very nice pancake indeed. – 2012-10-14