How can I solve: $(\frac{x}{16})^{\frac{1}{3}} = \sin(t)$ for t?
Solve x = sin(t) for t
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$\begingroup$
trigonometry
parametric
1 Answers
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$$t=\arcsin\big(\frac{x}{16}\big)^{\frac{1}{3}}$$
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1What have I done wrong then? http://www.wolframalpha.com/input/?i=y%3D13cos%28arcsin%28x%2F16%5E1%2F3%29%29-5cos%282arcsin%28x%2F16%5E1%2F3%29%29-2cos%283arcsin%28x%2F16%5E1%2F3%29%29-cos%284arcsin%28x%2F16%5E1%2F3%29%29 – 2012-02-19
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0@KianMayne You left out parentheses — exponentiation has higher precedence than division. Does [this](http://www.wolframalpha.com/input/?i=y%3D13cos%28arcsin%28%28x%2F16%29^1%2F3%29%29-5cos%282arcsin%28%28x%2F16%29^1%2F3%29%29-2cos%283arcsin%28%28x%2F16%29^1%2F3%29%29-cos%284arcsin%28%28x%2F16%29^1%2F3%29%29#) look better? – 2012-02-19
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0I got it, where I had previously got $$({\frac{x}{16}})^{\frac{1}{3}}$$ it should have been $$\frac{x^{\frac{1}{3}}}{16^\frac{1}{3}}$$ – 2012-02-19
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0@Potatoswatter I noticed that, but as I mentioned ^ there it was a problem with my original calculation – 2012-02-19
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0@KianMayne Hard to tell what's wrong without any context. The two expressions in your comment are the same, exponentiation distributes over multiplication. The mistake was $\frac{x}{16^{1/3}}$. Is there still a problem? – 2012-02-19
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0@Potatoswatter Here is the primary question: http://math.stackexchange.com/questions/110961/solving-parametric-equation-multiple-coefficients-of-trigonomic-functions – 2012-02-19