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Did I tackle this implicit differentiation correctly?

$$5x^2+3xy-y^2=5$$

$$10x+3x\dfrac{dy}{dx}+3y-2y\dfrac{dy}{dx}=0$$ $$\dfrac{dy}{dx}(y-2y)=-10x-3z-3y$$

$$\dfrac{dy}{dx}=\dfrac{-10x-3x-3y}{y-2y}$$

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    A couple of algebra slips.2012-11-22

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