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Possible Duplicate:
Proving that the sequence $F_{n}(x)=\sum\limits_{k=1}^{n} \frac{\sin{kx}}{k}$ is boundedly convergent on $\mathbb{R}$

From Stewart, we cannot find a calculus 2 easy way to prove this:

$$\sum^{\infty}_{n=1}\frac{\sin[n]}{n}=\frac{1}{2}(\pi-1)$$

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    What's $[n]$ suppose to be? perhaps the question has a typo?2012-11-02
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    Kerry just means $\sin(n)$2012-11-02
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    @BabakSorouh: But floor of a natural would be quite redundant.2012-11-02
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    Yeah floor or $n$ is just $n$, but this may just be it because sum of $\sin(n)/n$ is $1/2(\pi-1)$2012-11-02
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    Also look here http://math.stackexchange.com/questions/161960/sum-inequality-sum-k-1n-frac-sin-kk-le-pi-1/183471#1834712012-11-02
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    This is not a duplicate. I need a proof acceptable at calculus 2 student's level.2012-11-02

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