Could somebody tell me how to find the integral $$\int_{-\infty}^{\infty}\frac{dx}{1+ae^{bx^2}}$$ for constants $a$ and $b$?
Thanks!
Could somebody tell me how to find the integral $$\int_{-\infty}^{\infty}\frac{dx}{1+ae^{bx^2}}$$ for constants $a$ and $b$?
Thanks!