Find the smallest number that is made up of each of the digits $1$ through $8$ exactly once and is divisible by $88$.
Smallest number divisible by $88$ using digits $1$ through $8$.
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elementary-number-theory
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0$12437568$ should work, but what did you try? – 2012-03-20
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0I know that in order to be divisible by 11, the alternating digit sums has to be divisible by 11.But didn't know where to start – 2012-03-20
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0I get it, I start with two sets $\{1,3,5,7\}, \{2,4,6,8\}$ and since the sums are $16$ and $20$, I have to find a way to exchange a digit from each of these sets – 2012-03-20
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0Yes. good keep looking you will find the answer – 2012-03-20