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If $x \geq \min\{y,w\}$ then $x \leq y+w$.

This is kind intuitive,very trivial. Or not? It's like triangular inequality, isn't it?

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    $x \leq y+x$ is just $0 \leq y$, no?2012-08-14
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    Now I edited...it´s $x\leq y+w$.My bad.2012-08-14
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    @MeAndMath It is still false as stated. See sebigu's example below.2012-08-14
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    Every $x$ sufficiently big will disprove your conjecture.2012-08-14

1 Answers 1

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This is wrong. Take $y,w=1$ and $x=3$.

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    Yes,yes,yes.If you considerate $y,w$ to be equal it´s wrong.Right.I forgot that possibility...what if $y\neq w$ ?2012-08-14
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    Then take $y=0, w=1$ and $x=2$.2012-08-14
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    Take $y=2,w=3$ and $x=6$.2012-08-14
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    GREAT!THANKS IN ADVANCE!2012-08-14
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    No problem. Please mark this questing as solved.2012-08-14
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    Of course!It's done!2012-08-14