I'm trying to do the problem
3√40x^4/y^9.
When you try to reduce the index for 40^4, its going to be 4/3. How does the index get reduced into 2x√5x? I understand 3 cubed of 40, but what happens to the 4/3
I'm trying to do the problem
3√40x^4/y^9.
When you try to reduce the index for 40^4, its going to be 4/3. How does the index get reduced into 2x√5x? I understand 3 cubed of 40, but what happens to the 4/3