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I want to let fall a perpendicular from a point A in space being given by $A_x, A_y$ and $A_z$ on a plane being given by two vectors $B$ and $C$.

Ultimately I want to determine the foot x0 of the perpendicular. Note: This is not the question, this is the introduction. Here the questions follow.

I found

$$x_0 = p \vec+ t_0*n$$

while

$$t_0 = \frac{(d - n*p)}{n^2}$$

what is d in my case?

Is the vector n squared the same as:

$$n^2_x = n_x*n_x$$ $$n^2_y = n_y*n_y$$ $$n^2_z = n_z*n_z$$

Is the $\mathrm{Vector}_n * \mathrm{Vector}_p$ the same as $(np = \mathrm{Vector}_n * \mathrm{Vector}_p)$?

$$ np_x = n_x*p_x$$ $$ np_y = n_y*p_y$$ $$np_z = n_z*p_z$$

Thanks go to the one who formatted it. As you are at it, can you put arrows over the appropriate p and n vectors? Then you can remove this phrase.

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    Two points do not Uniquely determine a plane. May be, you'll have to make your question precise.2012-02-21
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    "...given by two vectors B and C" The question is precise, you are unable to comprehend it, though.2012-02-21
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    -1 for a "perfectly fine" attitude. Here, read [this](http://en.wikipedia.org/wiki/Dot_product).2012-02-21

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