Can someone help me simplify this boolean expression? $$(a+b+c+d)(a'+b'+c'+d')$$
so if I use the distributive property, I'll get:
$$ab'+ac'+ad'+ba'+bc'+bd'+ca'+cb'+cd'+da'+db'+dc'$$
I'm stuck after this step...
Can someone help me simplify this boolean expression? $$(a+b+c+d)(a'+b'+c'+d')$$
so if I use the distributive property, I'll get:
$$ab'+ac'+ad'+ba'+bc'+bd'+ca'+cb'+cd'+da'+db'+dc'$$
I'm stuck after this step...