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My question is how to solve this algebra equation.

$$\frac8{y-2}-\frac{13}2=\frac3{2y-4}$$

Can anyone help me solve this.The issue is that I am stuck.

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    I am sure how to format it but this is what I mean (8/y-2)-(13/2)=(3/2y-4)2012-04-28
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    Do you mean the way I edited it, or $$\frac8y-2-\frac{13}2=\text{something}\;?$$2012-04-28
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    Hint: Multiply both sides by $(y-2)$. Or, if the problem is correctly written the way Brian put it in the comments instead of in the post above, multiply both sides by $y$.2012-04-28
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    I like how Brian edit it the first time on my original post.2012-04-28
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    I did that the problem is on 13/2 part I get y^22012-04-28
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    @JamesDelRio what is the LCM for all three fractions? Multiply both sides of the equation by that LCM, and reduce the resulting fractions... (The LCM doesn't involve any '$y^2$'...)2012-04-28

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