Find the fixed points of a nonlinear two-dimensional system:
$$\dot{x} = \sin y$$ $$\dot{y} = x - x^3.$$
I know that $0 = x(1 - x²) \implies x = 0, 1, -1$. I am not sure what to do after this.
Find the fixed points of a nonlinear two-dimensional system:
$$\dot{x} = \sin y$$ $$\dot{y} = x - x^3.$$
I know that $0 = x(1 - x²) \implies x = 0, 1, -1$. I am not sure what to do after this.