Integrate the following: $$\int\frac{e^{\arctan(x)}}{1+x^2}\,dx$$
let $u = \arctan(x)$ , then $du = \frac{1}{1+x^2} dx$
$$\int e^u du$$ $$e^u + C$$ $$e^{\arctan(x)} + C$$
I am not sure if I did this right, this was a question on the final that I had today. Any help checking is appreciated.