I have found an equation for the cost of a cylindrical can (with height $h$, radius $r$, cents $k$) to be $C(h,r)=k(2\pi r)(r+h)$ and I am trying to figure out for a fixed volume $V_0$, show that the minimum cost for the can occurs when $\frac {h}{r}=2$. Any help would be greatly appreciated.
Calculus of the cost of a can
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calculus