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Given two second degree conic equations: $$ax^2+by^2+cx+dy+e=0$$ and $$fx^2+gy^2+hx+iy+j=0$$ [All coefficients are real]

To solve these equation for $x$ and $y$ a direct substitution yields a polynomial of fourth degree in $x$ (or $y$) as: $$kx^4+lx^3+mx^2+nx+o=0$$ Is there any easier way to evaluate the coefficients of fourth degree Polynomial $(k,l,m,n,o)$ in $x$ (or $y$) in terms of $a$, $b$, $c$, $d$, $e$, $f$, $g$, $h$, $i$, $j$.

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    "easier" than what? Which 4th degree polynomial are we talking about? Just the product of the two you have?2012-03-05
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    easier than a direct substitution of one variable into the second equation2012-03-05

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