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Possible Duplicate:
inequalty concering inverses of positive definite matrix
Is $B^{-1}-A^{-1}$ a positive definite matrix?

$P, Q$ are symmetric square. If $P \geq Q > 0$ then show $P^{-1} \leq Q^{-1}$.

Thanks for your help!

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    You should probably clarify that $\ge$ means that the difference is positive (or nonnegative) definite. I was reading it as a componentwise inequality...2012-11-19

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