0
$\begingroup$

Possible Duplicate:
Find a closed form for this sequence: $a_{n+1} = a_n + a_n^{-1}$

If a sequence is defined as $ a_{n+1}=a_{n}+\frac{1}{a_{n}} $

where $a_1 = 1$

Find the general value of $a_n$ as $f(n)$

Thanks

  • 1
    What is $a_0$ ?2012-10-17
  • 0
    So you're looking for a closed (non-recursive) form for your $a_n$. To get there, you're really going to need an initial value ($a_0$ or $a_1$), as Teddy points out.2012-10-17
  • 0
    Hey! I included the required initial value.2012-10-17
  • 0
    and also this http://math.stackexchange.com/questions/10065/2012-10-17

1 Answers 1