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If we have a probability density function given by $f(y)=\frac{a}{y^2}$ where $0, how do we find F(y)?

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    The cumulative distribution function is in principle defined for all $y$. So a complete answer would be $F(y)=0$ if $y , and $F(y)=1-\frac{y}{a}$ if $y \ge a$. Depending on the mood of the grader, leaving out the uninteresting part $F(y)=0$ if $y might lose you a mark.2012-02-28
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    $F(y)\neq 1-\frac{y}{a}$ but $1-\frac{a}{y}$ .2012-07-07

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