Show $x^2$ in the interval $(0,1/3]$ has no fixed points.
I understand that the range of that domain is always lower than $y=x$, but what is a proper way of showing this? $$\left(0,\frac13\right] \to \left(0,\frac19\right]$$
Show $x^2$ in the interval $(0,1/3]$ has no fixed points.
I understand that the range of that domain is always lower than $y=x$, but what is a proper way of showing this? $$\left(0,\frac13\right] \to \left(0,\frac19\right]$$