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Let $\{{A_n}\}$ be the closed subsets of $X$, such that ${A_n} \subset \operatorname{Int}{A_{n + 1}}$ and $ \cup {A_n} = X$, if $A_1$ and all $\operatorname{cl}(A_n-A_{n-1})$ have the covering dimension at most $m$, does $X$ have the covering dimension at most $m$?

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    "\rm{Int}" A doesn't look the same as "\operatorname{Int} A"; the latter provides proper spacing before and after "Int": $\operatorname{Int} A$. But curly braces around the first part wrecks that: {\operatorname{Int}} A: ${\operatorname{Int}} A$. When you figure out why that's how it _ought_ to work, you'll understand something about typesetting. (This distinction between the effects of \rm and of \operatorname doesn't work on Wikipedia, but I think that may change when they adopt mathJax in a few months.2012-04-19
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    Your example should be `{\rm Int} A` rather than `\rm{Int} A`, since `\rm` doesn't take a parameter — it is simply a switch that changes the current font.2012-04-20

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