The usual $x^2-2xy+y^2$ still applies. – 2011-04-19
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There is nothing to "solve". You have an expression, not an equation. – 2011-04-19
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Did you mean to have it equal to $0$? – 2011-04-19
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@Arturo Obviously the OP seeks to solve the problem of simplifying the expression. As a native (US) English speaker, I see no problem using the word solve in such a context. – 2011-04-19