Can someone please explain how to rewrite the expression $r+(3/2)s-(1/3)t$ in terms of $a, b,$ and $c$, where $r= \log (a), s=\log(b) \text{ and } t=2\log(c)$. The rewritten expression should be in the form of $\log (g(a,b,c))$
How do I rewrite the expression $r+(3/2)s-(1/3)t$
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algebra-precalculus
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0Use $\log(x)+\log(y)=\log(xy)$, $\log(x)-\log(y)=\log(x/y)$, $k\log(x)=\log(x^k)$. – 2011-08-11