I'm trying to find out what the graph of the function $y= \sin^2(\sqrt{x})$ looks like. Can someone please help me?
What is the first derivative of $y= \sin^2(\sqrt{x})$?
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calculus
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0Do you know the chain rule? Have you plotted the function? – 2011-03-20
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0@Rasmus, I've just looked up the chain rule but I'm not sure how to apply it. And yes I've plotted the function on excel, but I need to know the mathematical boundaries of it. – 2011-03-20
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0Boundaries? Do you mean where the function is defined? $\sin$ takes all real arguments, and the square root function is defined for all non-zero $x$, so the domain is $[0, \infty)$. – 2011-03-20
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0adding to Billare, $\sin(x)$ gives values in $[-1,1]$, so $\sin^2(x)$ gives values in $[0,1]$ and so does $\sin^2(\sqrt{x})$. – 2011-03-20