Find an equation of the tangent line to the graph of $y= \sqrt{x-3}$ that is perpendicular to $6x+3y-4=0$.
I don't understand what it's asking. Is this the normal line? How do I solve this?
Find an equation of the tangent line to the graph of $y= \sqrt{x-3}$ that is perpendicular to $6x+3y-4=0$.
I don't understand what it's asking. Is this the normal line? How do I solve this?