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A triangle has a vertex $A$ at $(0,3)$, vertex $B$ at $(4,0)$, and vertex $C$ at $(x,5)$. If the area of the triangle is $8$, what is the value of $x$?

I did this problem out by using the formula of the given coordinates of the vertices. My answer was 2.66.

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    Please put the problem **in the body of the question**, not in the title!2011-05-17
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    Is there a question here?2011-05-17
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    Good for you. Do you have a question? Your answer is not exactly correct.2011-05-17
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    @Arturo: True but I presume she wanted to know how to proceed.2011-05-17
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    or may be even check the answer with us.2011-05-17
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    @Chandru: I'm not criticising you, so I don't see why the need to defend yourself. But since you bring it up, why did you assume "she wanted to know how to proceed", if she said she had already finished?2011-05-17
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    @Arturo: Don't know. Can't really justify that.2011-05-17
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    @Briana791: If the question asked for the *positive* $x$ that works, you have found it. More precisely, $x=8/3$. But, as a picture may persuade you, there is also a negative $x$ that gives area $8$.2011-05-17

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