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Use Newton's method to apporzimate the indicated root of the equation correct to six decimal places. The negative root of $e^x = 4-x^2$

I do not know what a negative root is nor do I really know what I am supposed to do. I am guessing raise everything by loge.

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    A negative root $x$ of a function $f$ is a value $x \in \mathbb{R}$ such that $x < 0$ and $f(x)=0$2011-10-27
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    Also the question is not really different from the one you just asked ( http://math.stackexchange.com/questions/76421/newtons-method-problem ), didn't you learn anything from the answer? :-/2011-10-27
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    I have no idea what you just said.2011-10-27
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    What Listing said was that a "negative root" is a root that happens to be a negative number. A root of an equation is a *solution* to the equation. So they are asking you to find the negative value of $x$ that makes $e^x = 4-x^2$ true.2011-10-27

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