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Firstly sorry for this topic's title..
$${P(x)\over x^2}=x-1 \Rightarrow {P^3(x)\over x^2}=?$$

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    Hint: $P(x)=x^2(x-1)$. Therefore $(P(x))^3=?$. Therefore $\frac{(P(x))^3}{x^2}=?$.2011-11-13
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    P(x) same as p(x) ?2011-11-13
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    @daniel yes....2011-11-13

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