Let an acute triangle ABC be given. Prove that the circles whose diameters are AB and AC have a point of intersection on BC. How do I go about this problem? Can You Please Give Me a Hint?
Acute triangle: circles with diameters of two sides meet on the third
5
$\begingroup$
geometry
euclidean-geometry
-
0Does this only apply for acute triangles? I think it applies for all. – 2012-03-31