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Suppose $a$, $b$, $c$, and $d$ are positive numbers and each is not equal to $1$.

If $\log_a(d)$, $\log_b(d)$, and $\log_c(d)$ are an arithmetic progression in this order, then what is $(ac)^{\log_a(b)}$ equal to?

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    Please write your question coherently.2011-03-14
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    @PEV, maybe he's using google translator. If I had the rep, I'd change "be" to "let"... (edit: thanks Henry!)2011-03-14
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    @The Chaz: people seem to be able to propose edits even if they don't have the rep to implement them. I don't know how, but I see the proposed edits (and have accepted a bunch and never rejected one).2011-03-14
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    @Ross *Now* I have the option to edit it. Maybe it's time- (or post-count) sensitive??2011-03-14
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    @The Chaz: I dunno. I know the ability to edit is rep sensitive, but I don't know how the low-rep people propose them. Maybe there is a delay to let the higher-rep people fix things first (which I would not support, but what do I know?) All I can suggest is to work with what you have-it sounds like you will be a positive contributor to the site.2011-03-14
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    @Ross Thanks! I'm more of an edit-the-imperative-out-of-the-question than a lecture-them-silly kind of guy, and I appreciate the occasional link to Lmgtfy.com - so I guess that only puts me at odds with ... one person?? :)2011-03-14
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    @The Chaz: I suspect the link to Lmgtfy.com will put you at odds with more than one, but I am not included in that set. I tend to provide the link, but I agree a Google and Wikipedia search should be a prerequisite to posting. After all, posters are asking for free help from unknown strangers. So I feel that each of us should provide whatever help we feel like (based on how the question is asked, as well as what the question is, and our mood of the moment). And if you ask for help, you take the risk of not liking what you get. One view.2011-03-14

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