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Let's have the number $5^{2^{n-1}}$ where $n$ any non-zero natural number. I conjecturally say that between the following two bounds we will always obtain $n$ primes of the form $4x+1$. $[(5^{2^{n-1}})^{1/n}]e^{1/n}<...>[(5^{2^{n-1}})^{1/n}]e^{-1/n}$

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    And what might make you think such a thing?2011-11-19
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    If you answer this conjecture it will lead to a third way of counting primes besides the two other well known methods.2011-11-19
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    "the two other well known methods"?2011-11-23

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