0
$\begingroup$

Is it possible to write $\int_{-\infty}^\infty e^{-iqu}\left( \frac{A}{\sqrt{1-iau}}+\frac{B}{\sqrt{1-ibu}}\right)^Ndu$ in this form $\int\frac{e^{-iu}}{(\sqrt{1-iau})^n(\sqrt{1-ibu})^m}du$

  • 0
    Binomium formula?2011-01-18
  • 0
    tat makes it more complicated...??2011-01-18
  • 0
    But that's precisely what you want.2011-01-18

2 Answers 2