$N(R) \subset \operatorname{ann}_R (M)$ if M is simple left module
How do I prove this?
Know that if $a$ is in $N(R)$, then $a^n=0$ for some element. However, don't see how to go from this.
$N(R)=\sum \{ I\}$ where I is nilpotent ideal of R.
$N(R) \subset \operatorname{ann}_R (M)$ if M is simple left module
How do I prove this?
Know that if $a$ is in $N(R)$, then $a^n=0$ for some element. However, don't see how to go from this.
$N(R)=\sum \{ I\}$ where I is nilpotent ideal of R.