By the inequality here or using integration I can get the following lower bound for $\log(n!)$. How can I get a better lower bound for $\log(n!)$?
$$\log(n!)>\log\left(\frac{(n+1)^n}{e^n}\right)$$
By the inequality here or using integration I can get the following lower bound for $\log(n!)$. How can I get a better lower bound for $\log(n!)$?
$$\log(n!)>\log\left(\frac{(n+1)^n}{e^n}\right)$$