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$\begingroup$

I am stuck trying to solve for $A$ in

$$3 = 11\sin^2 A - 2\sin 2A$$

I cannot see a way to manipulate to get like terms and hence factor it.

Thanks!

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    Hint, use: $\sin^2 A = (1-\cos 2A)/2$.2011-12-16

2 Answers 2