I am having trouble figuring out how I can solve this log:
$$6 \log(x^2+1)-x=0$$
The steps i've thought to take so far are as follows:
step 1: subtract the right most x to the other side of the equation:
$$6 \log(x^2+1) = x$$
step 2: divide by 6:
$$\log(x^2+1)=\frac{x}{6}$$
step 3: make both sides an exponent of 10 to get rid of the log:
$$x^2+1 = 10^{\frac{x}{6}}$$
step 4. ??????????????