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Prove that an autonomous ODE $f(x)=x'$ has no nonconstant periodic solutions.

I guess I could prove it by contradiction by saying $x(t+T) = x(t)$ implies $x(t) =$ constant.

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    Can you be more specific, so that we can better help you?2011-07-21
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    @Derrick: please ask a complete question. Right now, it is really not possible to answer anything useful!2011-07-21

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