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This a sub-part of an big question,If I have $P(R_1|Q)$ how can we compute $P(R_1'|Q)$ ?

It is given $R_1$,$R_2$ and $R_3$ are mutually exclusive events I computed $P(R_1|Q)$ using baye's theorem.

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    If $R_1'$ is the complement of $R_1$ then $P(R_1'|Q) = 1-P(R_1|Q)$, but from your question I can't tell if that's what you are asking.2011-05-06
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    Yeps,that's what I am asking but how is it working? I know that $P(R_1') = 1-P(R_1)$ but i could not understand howz it holding for the conditional also?2011-05-06
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    Go back to the definitions. What is $P(R_1|Q)$? What is $P(R_1'|Q)$? What is their sum?2011-05-06

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