I need to find the derivative of:
$$ h(x) = \int_{0}^{x^2} (1-t^2)^{1/3} \, dt $$
Would the answer to that just be:
$$ (1-x^4)^{1/3}? $$
I need to find the derivative of:
$$ h(x) = \int_{0}^{x^2} (1-t^2)^{1/3} \, dt $$
Would the answer to that just be:
$$ (1-x^4)^{1/3}? $$