2
$\begingroup$

I'm looking for solution to this non-homogeneus problem.

$\frac{\partial u}{\partial t}-\frac{\partial^2 u}{\partial x^2}=F(x,t)$ for $0, $t>0$

$u(x,0)=0$

$u(0,t)=\frac{\partial u}{\partial x}(x=\pi)=0$

Does anyone know how to proceed?

  • 0
    What are the boundary conditions at the boundary of the $x$ variables? At $x=\pi$ you have specified something (is it now $u=0$ or $u'=0$?). What happens at $x=0$?2011-03-01
  • 0
    Sorry, I corrected the text2011-03-01
  • 0
    This question has been solved perfectly. Hope that the asker has been diving enough and accept the answer at an early date.2013-04-21

3 Answers 3