Sketch the region enclosed by the given curves. Decide whether to integrate with respect to $x$ or $y$. Then find the area of the region bounded by $x+y^2= 6$ and $x+y=0$
this is what i got but it i wrong $6\cdot 3 - 3^3/3 - 3^2/2 - 6\cdot (-2) - (-2)^3/3 - (-2)^2/2$