Show that $$1+ac+ab+3a\leq b+c+abc+3bc$$ if $1\leq a\leq bc,$ $1\leq b\leq ac,$ $1\leq c\leq ab.$
How to prove the following inequality: $1+ac+ab+3a\leq b+c+abc+3bc$?
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0Where is the inequality from? – 2011-12-18