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A (a matrix) = 1 3 0                 2 1 -1 

A: R^3 ----> R^2 linear
v -----> Av

Let B = {(1,0,2),(0,1,-1),(2,1,3)} basis of R^3, C= {(2,1),(3,2)} basis of R^2

Compute the matrix A ith respect to B of R^3 and C of R^2

I have the solution but I don't really uunderstand the workings.

Sol: A(1,0,2) = (1,0) = a11 (2,1) + a21(3,2) = 2(2,1) - (3,2)

A(0,1,-1) = (3,2) = 0(2,1) + 1(3,2)

A(2,1,3) = (5,2) = 4(2,1) - 1(3,2)

this gives the matrix:

2 0 4
-1 1 -1

The main bit I don't understand is why (1,0) and (3,2) and (5,2) are chosen??

1 Answers 1