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I have a logarithmic equation that I am meant to find the value of $x$ for:

$2\log_{9}(x)$ = $1/2$ + $2\log_{9}(5x+18)$

I get as far as here when I realize I cannot use the quadratic formula.

$\log_{9}\left( \dfrac{x^{2}}{(5x+18)^2}\right)= \dfrac{1}{2}$

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    But you know what to do with $\log_9(x^2)=\log_9(3)+\log_9((5x+18)^2)$, yes?2011-11-09

2 Answers 2