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What is the number of positive integers that, when $2004$ is divided by them, leave a remainder of $24$?

A. $036$

B. $020$

C. $022$

D. $021$

E. $014$

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    i tried using factorization method. i can find the numbers with remainder 0 like this..suppose i have 72.i can go in this way 1*72=72 (remainder=0); 2*36=72 (remainder=0)..and so on....but i cant find the sol. for the above question...:(2011-02-04
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    Look for the divisors of 2004-24.2011-02-04

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