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Unsure on the procedure on this one and then how to explain it. I don't think this function has any rational roots, right?

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    It depends on what you're allowed to use. If you evaluate $f(-2)$ and $f(2)$, what do you get? If you're allowed something like the [intermediate value theorem](http://en.wikipedia.org/wiki/Intermediate_value_theorem) and you know that polynomials are continuous, then these two values get you what you want. At the level of precalculus I don't know offhand.2011-12-15

5 Answers 5