Let $G = \langle a,b | a^3=b^3=(ab)^3 =1\rangle$. I'm trying to compute centralizers in $G$; in particular, I'm interested in the centralizers of $ab$, $ba$, $a^2$, and $b^2$. Does anyone know a good way to compute these centralizers? Will GAP do it for me or anything? Thanks.
computing centralizers in the von dyck group $\langle a,b | a^3=b^3=(ab)^3 =1\rangle$
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group-theory
gap
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1GAP can help, because this group is polycyclic. – 2011-09-21
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0@Steve: How can GAP handle the group? I have to hand GAP a polycyclic presentation and somehow tell GAP that the group is polycyclic? – 2011-09-21