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If have well-known formula $(n + 1) n / 2 = 1 + 2 +\cdots+ n$. If the difference between the closest numbers smaller, will obtain, for example $(n + 0,1) n / (2 \cdot 0,1) = 0,1 + 0,2 +\cdots+ n$. Now if the difference between the closest numbers the smallest possible, will obtain $(n + 0,0\ldots1) n / (2 \cdot 0,0\ldots 1) = 0,0\ldots1 + 0,0\ldots2 + \ldots + n$, so can conclude $n ^ 2 / 2 = (0,0\ldots1 + 0,0\ldots2 + \cdots + n) / 0,0\ldots1$ whether conclude is correct?


EDITED VERSION:

If have well-known formula $\frac{(n + 1)n}2 = 1 + 2 +\dots+ n$.

If the difference between the closest numbers smaller, will obtain, for example $\frac{(n + 0,1) n}{2.0,1} = 0,1 + 0,2 +\dots + n$.

Now if the difference between the closest numbers the smallest possible, will obtain $\frac{(n + 0,0\dots1) n}{2 . 0,0\dots 1} = 0,0\dots 1 + 0,0\dots 2 + \dots + n$ , so can conclude $\frac{n ^ 2}2 = \frac{0,0\dots1 + 0,0\dots2 + \dots + n}{0,0\dots1}$ whether conclude is correct?


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    By comma symbol, you mean decimal point?2011-12-17
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    @ZeeshanMahmud Comma is used as [decimal separator](http://en.wikipedia.org/wiki/Decimal_separator) in many countries.2011-12-17
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    Marko: I guess both these account belong to you: http://math.stackexchange.com/users/20189/marko and http://math.stackexchange.com/users/21380/marko; Maybe it would be good for you to register, so that you can better follow all questions you posted. (After you do it, you can even ask moderators to merge you account with the older unregistered ones.)2011-12-17
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    shiver me nimbers2011-12-17
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    Marko: I've tried to edit your question using TeX for better readability. (And maybe some other users will improve it a little more.) You should check whether I did not change the meaning of your question, unintentionally. If you're satisfied with the edited version, you can remove the original one.2011-12-17
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    I've merged the duplicate accounts 'marko'. Please do try as @Martin suggested and register.2011-12-19
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    possible duplicate of [Formula for the sum of the squares of numbers](http://math.stackexchange.com/questions/92662/formula-for-the-sum-of-the-squares-of-numbers)2012-01-10

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