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Given $\tan A = \sqrt3$ and $\csc B = -\sqrt2$ where $A,B \in[\pi,\frac{3}{2}\pi]$,

evaluate

$\cos^2A + (\cot B)(\sin A)$.

I haven't been able to figure out the angle for $B$.

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    Edited your question to insert latex. I hope i didn't change your question in any way.2011-11-22
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    You don't need to figure out what angle $A$ and angle $B$ are. But in fact, angle $B$ is not hard. Its cosecant is $-\sqrt{2}$, so its sine is $-1/\sqrt{2}$. Familiar? In your intervaal, it is hafway between $\pi$ and $3\pi/2$.2011-11-22
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    I have also done some editing. I hope the question remains the same.2011-11-22

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