How can I calculate the area of a hexagon which all of it's angles are equal given 3 of it's sides?
Edit:
I forgot the constraint that opposite sides have same length, e.g. for hexagon $ABCDEF$
$AB = DE$
$BC = EF$
$CD = FA$
Calculating the area of a special hexagon
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$\begingroup$
geometry
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6If you take an arbitrary (large enough) equilateral triangle and cut off its corners you can fit the sides which cut off the corners to the numbers you are given, but different equilateral triangles will give different areas. Note also that if you have a horizontal (bottom) side and the two sides adjacent to it, you can create a pentagon with two sides from the ends of the bowl you have, and then a hexagon by cutting off the top corner with a horizontal line, but this is not fixed and different choices give different areas. So the three sides are insufficient to determine the area. – 2011-08-31
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0@Mark Bennet: you are right, I forgot a constraint, see the edit. – 2011-08-31