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I am trying to compute $\Delta y$ and dy for a given value of x and dx = $\Delta x$ I am given $y=2x-x^2$ x=2 and $\Delta x = -.04$

Not really sure what to do here, feels like something is missing. I thought I knew how to do these problems but they took another approach to it than what I am used to.

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    Do your notes indicate $\Delta y=f(x+\Delta x)-f(x)$ and $dy=f'(x)dx$?2011-10-06
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    No, Stewart doesn't make that distinction very clear. I am attempt to decipher and transcribe his writings right now.2011-10-06

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