Looking at an earlier post Finding the power series of a rational function, I am trying to get a closed formula for the n'th coefficient in the Taylor series of the rational function (1-x)/(1-2x-x^3). Is it possible to use any of the tricks in that post to not only obtain specific coefficients, but an expression for the n'th coefficient ?If T(x) is the Taylor polynomial I am looking at the equality (1-x) = (1-2x-x^3)*T(x) and differentiating, but I am not able to see a pattern giving me an explicit formula for the coefficients.
Coefficients for Taylor series of given rational function
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taylor-expansion
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0Thank you. That ought to make it doable for me. – 2011-01-17
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0You can add comments to your own questions and (I think) answers to your own questions by clicking the "add comment" link. – 2011-01-17
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0@user5944 @derman you seem to have one registered and one unregistered account. Please let one of the moderators know if you would like them merged. – 2011-01-17