How does one directly (by finding primitive) compute an integral which corresponds to the normal distribution:
$$\int_{a}^{b} e^{{-(x-a)^2}/{2s^2}} \,\mathrm{d}x$$
How does one directly (by finding primitive) compute an integral which corresponds to the normal distribution:
$$\int_{a}^{b} e^{{-(x-a)^2}/{2s^2}} \,\mathrm{d}x$$