A number when successively divided by $9$, $11$ and $13$ leaves remainders $8$, $9$ and $8$ respectively.
The answer is $881$, but how? Any clue about how this is solved?
A number when successively divided by $9$, $11$ and $13$ leaves remainders $8$, $9$ and $8$ respectively.
The answer is $881$, but how? Any clue about how this is solved?