If $G$ has no proper subgroup, prove that $G$ is cyclic of order $p$, where $p$ is a prime number.
I know that since $G $is a group with no proper subgroups, $g \in G$ is not just the identity. I don't know where to go from there.
If $G$ has no proper subgroup, prove that $G$ is cyclic of order $p$, where $p$ is a prime number.
I know that since $G $is a group with no proper subgroups, $g \in G$ is not just the identity. I don't know where to go from there.