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$\begingroup$

equation 1:

$-i\omega\underline \xi - 2i(\underline k \cdot \underline \Omega )\underline u = 0$

with:

$\underline \xi = i \underline k \times \underline u$

$\underline k \cdot \underline u = 0$

taking:

$i\underline k \times \text{(1)}$

derive:

$\omega = \pm 2\frac{(\underline k \cdot \underline \Omega )}{|\underline k|}$

I can get pretty close and can post my working if required - but I don't do anything complicated - any help = many thanks

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1 Answers 1