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Extras from my homework. The first one should be easier, but still hard enough.

1) $a_{n+3}-(3/2)a_{n+2}-a_{n+1}-(1/4)a_n=0$

2) $a_{n+3}-3a_{n+2}-3a_{n+1}+a_n=n^2+2^n$

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    looks like very good homework. It is slightly hard, but certainly worth the effort. (a spoiler: scale the negative numbers so you get 1 as sum, solve, scale back to original)2011-12-13
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    I've edited in some parentheses since $3/2a_{n+2}$ could otherwise be interpreted as $3/(2a_{n+2})$. Of course, if $3/(2a_{n+2})$ was what you actually meant, you'll have to re-edit.2011-12-13
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    I think the way this is going to work best is, you show us what you know, how far you get, where you get stuck, and we try to help you over the rough spots.2011-12-13
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    Well, they are extras for students who love math. I hate math :D I think in first one are some complex roots, second one is to hard. Frenkly, I posted this question because of bonus points and I am not sure if I want to be able solve equations like this on my own. So feel free to solve it for me, if you want, or let it go ;)2011-12-14

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