2
$\begingroup$

Sorry for this rather mundane question, but how would I go about solving the following. I know there is a straightforward method to it.

$-3< 1/x \leq 1$

  • 1
    Obviously $x\not=0$, or else $1/x$ is not defined. Now, consider the two cases $x>0$ and $x<0$. For $x>0$, the inequality $-3<1/x$ always holds. So all you need to solve is $1/x\le1$. Similarly, for $x<0$, you only need to solve $-3<1/x$.2011-09-30

3 Answers 3