How to express $2x-1$ in the form $x-a$ ? Isn't $x-1/2$ wrong?
And how to express $2x+3$ in the form x-a?
this is for using it in the remainder theorem:
when $f(x)$ is divided by $x-a$, the remainder is $f(a)$
How to express $2x-1$ in the form $x-a$ ? Isn't $x-1/2$ wrong?
And how to express $2x+3$ in the form x-a?
this is for using it in the remainder theorem:
when $f(x)$ is divided by $x-a$, the remainder is $f(a)$