1
$\begingroup$

How can you prove that for $n\geq1$, you have $n^n\geq e^{n-1}$? (no induction)

  • 0
    Have you tried differentiation? If that doesn't work, try series expansion of e.2011-03-26
  • 1
    You can write $n^n= e^z$ for some $z \in \mathbb{R}$ and then compare exponents.2011-03-26
  • 0
    what's wrong with induction?2011-03-26

3 Answers 3