Say I have some polynomial $p(x)$ and want to express its $n$th integral, is there a closed form for this?
Is there a closed form for the $n$th integral of a polynomial?
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calculus
integration
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5It doesn't have a unique $n^{th}$ integral; this is only well-defined up to a polynomial of degree $n-1$. – 2011-09-11
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0I don't see your point. Take for instance $p(x) = x$, so its degree is 1. We have the 2nd integral as $\frac{x^{2}}{6}$ however.. edit: that is, plus a constant – 2011-09-11
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4The $n^{\rm th}$ integral of $x^r$ is $$ \frac{r!}{(r+n)!} x^{r+n} \ \ (+ \ \text{arbitrary poly of degree } n-1). $$ You can then use linearity to add the integrals of individual terms. – 2011-09-11
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0On the other hand, $$\underbrace{\int_0^x\int_0^{t_{n-1}}\cdots\int_0^{t_1}}_{n} t^k\;\mathrm dt\cdots\mathrm dt_{n-2}\mathrm dt_{n-1}=\frac1{(n-1)!}\int_0^x t^k (x-t)^{n-1}\mathrm dt=\frac{k!}{(n+k)!}x^{n+k}$$ – 2011-09-11
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3Oh, now I see. I forgot to integrate the constant along with it – 2011-09-11
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0@Pedro You can answer your own question. – 2013-03-16