I'm very interested to know how I can factorise $a^{10} +a^5 +1$ in two factors with integer coefficients. I've tried a lot but I don't have any idea how do that.
Factoring $a^{10}+a^5+1$
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$\begingroup$
algebra-precalculus
polynomials
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0You can immediately get the answer using http://www.quickmath.com/webMathematica3/quickmath/algebra/factor/basic.jsp – 2011-03-02
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1You can cheat: http://www.wolframalpha.com/input/?i=factor%28a%5E10%2Ba%5E5%2B1%29. – 2011-03-02
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2Does this look like a geometric series? Base=1, ratio=$a^5$. – 2011-03-02