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Show that if an element of the odd part of the Clifford Algebra anticommutes with everything in the vector space, then it is 0.

Been having a really hard time making any progress with this one.

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    I don't think this is algebraic number theory. And put the question in the body, summary in the title2011-11-23
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    algebraic number theory do use clifford algebra(like quarterions,etc) sometimes, though most of the time you assume the ring to be commutative.2011-11-23
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    Algebraic number theory also uses topological spaces, yet a question about them should probably not have to be tagged number-theory...2012-08-06

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