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Is the information below correct?

Find the inverse Laplace transform of $$ F(s) = \frac{s}{s^2 + 4s + 13}$$

Soln: a) Complete the squares to simplify our denominator $$ s^2 + 4s + 13 = (s+2)^2 + 9 = (s+2)^2 + 3^2$$ $$\mathscr{L}^{-1}\left\{F(s)\right\} = \frac{s}{(s+2)^2 + 3^2}. $$ From the table we can deduce that this is $$\mathscr{L}^{-1}\left\{F(s)\right\} = e^{-2t} \cos(3t).$$

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    (+1) for showing your work, among other things. Don't forget to "accept" an answer when it's all said and done! You can also revisit old questions of yours and accept answers, if you're into the whole "closure" thing :)2011-07-20

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