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What is $\lim\limits_{x \to 0^{-}}x^{\frac{1}{2x}}$?

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    You've tried taking logarithms already?2011-05-06
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    I don't think it is even defined since $x \rightarrow 0^-$2011-05-06
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    @J.M: I have tried taking logarithms, but encountered the problem Sivaram mentioned above.2011-05-06
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    Yes, and since you're not supposed to have anything negative within the logarithm, then... ?2011-05-06

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