I'm working my way through the videos on the Khan Academy, and have a hit a road block. I can't understand why the following is true: $$\frac{6}{\quad\frac{6\sqrt{85}}{85}\quad} = \sqrt{85}$$
Fractions with radicals in the denominator
4
$\begingroup$
algebra-precalculus
arithmetic
fractions
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0I'm not even sure how to read this fraction. If you know some $\LaTeX$ please use this to enhance the equation; otherwise please at least use parenthesis to make the readability well-defined. – 2011-06-26
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0At the moment what you've written is $6/(6\sqrt{85}/85) = 6\cdot 85/(6\sqrt{85}) = 85/\sqrt{85} = \sqrt{85}$, which is clearly not equal to 6. Can you copy down the fraction exactly? – 2011-06-26
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0As it's currently written: $\dfrac{6}{6 \sqrt {85}} = \sqrt {85}$ is not true. But I am struggling to come up with what was really meant. – 2011-06-26