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The diagram shows the graph of $y=|mx+n|$

(i tried my best to do the same thing as my exercise book, actually 1 is propotional to 1 and 3 is propotional to 3, but 2 is not propotional to 2)

Find the value of $m$ and $n$.

Anyone can help me solve this problem? Thanks

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    I don't understand the question...2011-02-26
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    edited the question2011-02-26
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    Still don't understand the question. What problem you want to solve? What exercise book you refer to? What does the title mean? Do you want to find values m and n such that $|m x + n|$ fulfills what?2011-02-26
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    You should explain what it is that you don't understand more precisely. Also, the title does not make a lot of sense. Edit: Your rephrasing of the question is helpful. You should consider the meaning of the coefficients $m$ and $n$. Maybe you could ignore the absolute value for a moment and just focus on the line $y = mx + n$ itself. How does the line change if you fix one constant and change the other?2011-02-26
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    i've edited the questionn2011-02-26
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    @Stijn: that should have been a comment.2011-02-26
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    Rather than say "1 is propotional to 1 and 3 is propotional to 3, but 2 is not propotional to 2" it would be more accurate to say (1,1) and (3,3) are on the graph, but (2,2) is not. Being on the graph is quite different from being proportional2011-02-27

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