If $0<|w|<1/2$, then $2|w|/3<|\operatorname{Log}(1+w)|$ using power series and modulus inequalities.
How do you prove the following inequality concerning complex Logarithms?
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complex-analysis
inequality
logarithms
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0It doesn't appear true for $w=0$ – 2011-09-12
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0What's the power series for $\operatorname{Log}(1+w)$? (That's a hint, not a question:) – 2011-09-12