$$(-11a^2)(-4a^{-7})$$
Can someone reformat, $a$ is second set of parenthesis is to the $-7$ power.
Change to reciprocal so we get $$\left(\frac{1}{-4a}\right)^7 * \frac{11a}{1} = $$ confused
Answer should be $$\frac{44}{a^5}$$
Unless,
$$(-11a^2)(-4a^{-7}) = 44a^{-5} = \frac{1}{44a^5}$$
but I guess, only $a$ was moved to the bottom because 44 is not negative.
Confused.