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The goal of this problem is to solve the initial value problem

$$y' = -f(x)y;\quad y(0) = 1;$$

where $$f(x)= \begin{cases} 1,&\text{if }x\leq 2\\ \frac{3}{2},& \text {if } x>2. \end{cases} $$ Since $f$ is discontinuous, it is necessary to solve the above ODE separately in each of the intervals where $f$ is continuous.

(a) Determine the intervals where $f$ is continuous.

(b) Solve the equation in each of these intervals. Note that each of the solutions obtained will have a different constant of integration.

(c) Match the solutions at the points where $f$ is discontinuous, in order to make the solution $y$ continuous on $\Bbb R$. Note that in this case it is impossible to make $y'$ continuous at the points where $f$ is discontinuous.

I just don't understand what part (c) is asking, if anyone could help me with the concepts I would really appreciate it.

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