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Having trouble with one of my math homework problems. I need to find the least common denominator (LCD) to solve the problem. I'm not sure how to figure this out one. Thanks in advance.

$$ \frac{3}{j^2+6j} + \frac{2j}{j+6} - \frac{2}{3j} .$$

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    The first term you listed. Thank you. I actually forgot the J after the 6. For the denominator of the first term, it should be j^2+6j, sorry.2011-09-14
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    And the second should also be $\frac{2j}{j+6}$? And the third $\frac{2}{3j}$?2011-09-14
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    Thanks, that makes it much easier to read. It is now displayed exactly as the problem is. Thanks.2011-09-14
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    Mark: instead of just "not sure how to figure this one out", how about sharing what you've tried so far. We can help steer you in the right direction and/or point out missteps. You'd learn more than just reading someone else's solution too. :)2011-09-14
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    Here goes: note that if you take the LCD of the last two fractions, you get $3j^2+18j$. So...2011-09-14
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    Actually, you don't need to find the *least* common denominator to solve the problem: all you need is *a* common denominator, and the product of the denominators works fine. Of course, this means that you'll probably have to do some simplification at the end but it is much simpler to start.2011-09-14

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