I want to know if I can get some help with this proof. I tried, but I just cannot seem to get $2^{k}$. It states that,
For $k \in \mathbb{Z}_{\ge 0}$, $$\sum^{k}_{m=0}\binom{k}{m} = 2^k$$
Thank You.
I want to know if I can get some help with this proof. I tried, but I just cannot seem to get $2^{k}$. It states that,
For $k \in \mathbb{Z}_{\ge 0}$, $$\sum^{k}_{m=0}\binom{k}{m} = 2^k$$
Thank You.