I want a convincing proof of this...
$\nabla^2 (1/|r-r'|)$ = $-4\pi \delta^3 (r-r')$
(where r and r' are vectors and $\delta^3 (r-r')$ represents the 3-D delta function...)
I want a convincing proof of this...
$\nabla^2 (1/|r-r'|)$ = $-4\pi \delta^3 (r-r')$
(where r and r' are vectors and $\delta^3 (r-r')$ represents the 3-D delta function...)