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$\begingroup$

$$\dfrac{1}{2}\ln(x+7)-(2 \ln x+3 \ln y)$$

Our professor let's us solve this but i do not understand how $\ln$ works. He says it has same properties with $\log$ but i still don't get it. What's the difference of the two?

  • 8
    *ln* denotes the *natural log*, which has base $e$. Just "log" in this context denotes a log with base $10$. Google "mathematical constant e" for more info.2011-12-11
  • 5
    The formula is ambiguous. Do you mean $$\frac{1}{2}\ln(x+7)\text{ or }\frac{1}{2\ln(x+7)}$$in the first summand?2011-12-11
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    @MaX: How do you know which one was meant?2011-12-11
  • 7
    The difference is that $\ln$ is for children, and $\log$ is for grownups.2011-12-11
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    @Arturo:It was a guess on my side, but now i see your point, rolled back to the the OP's version.2011-12-12
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    @GerryMyerson : You be nice or I'll whack you across the knuckles with my slide rule.2015-11-03
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    honestly why isn't it nl x ?2018-03-21

3 Answers 3