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If we've got two functions $Y=4$ and $y= \sqrt x$ which limits an area with the $Y$-axis. What is the rotation volume of that particular area.

My thoughts about the question is that i put the two equations against each other: $4 = \sqrt x$, $x = 16$.

So my limits are 0 - 16 which we use in the integral,

$2\pi \int x(4- \sqrt x) dx $

But the answer is wrong? How should i think?

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    What answer did you get? Looks OK so far.2011-06-02
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    I got 2948,9! is this right?2011-06-02
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    No, I get a value less than 1/4 of that.2011-06-02
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    ok, i corrected some of my calculations, finally i got 643,39...? is this right?2011-06-02
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    Are you expected to report the exact value or a decimal approximation? If decimal, it is fine.2011-06-02
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    nothing is said in the question, the exact form is : (1024 pi)/5 sorry, can´t write comments!2011-06-02
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    No, it isn´t homework. It´s from my study book! just wanted it to be clarified which showed out to be wrong in my calculation! Many thanks to you all...2011-06-02

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