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How can we compute the localization of the ring $\mathbb{Z}/6\mathbb{Z}$ at the prime ideal $2\mathbb{Z}/\mathbb{6Z}$? (or how do we see that this localization is an integral domain)?

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    arent you inverting the zero divisor 3?2011-04-11
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    @yoyo: Yes, but $S$ containing a zerodivisor only implies that the canonical map $f:R\rightarrow S^{-1}R$ is not injective, as we would expect here. The map $f$ is only the zero map when $0\in S$.2011-04-11

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