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Ok well I have this basic problem in which there are grades (4 grades). There's an upcoming final that is weighted to be some fraction toward the final grade (2/3). I have to find what the final grade has to be to get an average grade of 80. and then 90. I completly forgot the procedure as to how to tackle this problem. Anybody have any hints/tricks for me to start me off?

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    If I am understanding the question correctly then perhaps thinking of it as two things weighing in on the final grade will help you: 2/3 the final grade is the score on the final and 1/3 is the average of the other 4 grades. So you would have 80(or 90) = 2/3(F) + 1/3(avg(other grades))2011-09-13
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    thanks! it was very helpful2011-09-13
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    @Ronnie.j no problem :)2011-09-13
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    @Deven Ware: you could enter that as an answer so it can be accepted. It would be good to make the fractions clear: 2F/3 so everybody knows F is not in the denominator. Better yet, use $\LaTeX$ by putting it in dollar signs: \frac{2F}{3} gives $\frac{2F}{3}$2011-09-13
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    @Ross Millikan : I can't seem to edit it now, systems not letting me and I figured it was simple enough that latex was not needed, but I suppose I'll make a habit of writing everything up with latex.2011-09-13
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    @Deven Ware: You can't edit comments after a little while. I think you can edit your own answers any time.2011-09-13

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