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How does one show that $I_n=\int\limits_0^1 (1-x^2)^ndx $ satisfies the recursion relation $I_n={2n\over 2n+1}I_{n-1}$? I don't think I have to explicitly evaluate the integral right?

Thanks.

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    @DidierPiau: Ah, well-spotted typo! Thanks!2011-11-03

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