What is the limit of the continued fraction whose partial denominators are the composites?
A continued fraction involving composite numbers
5
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elementary-number-theory
continued-fractions
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0The posting says "below", but it isn't there. Let's see how it looks here: $1+\cfrac{1}{4+\cfrac{1}{6+\cfrac{1}{8+\cfrac{1}{9+ \cfrac{1}{10+\cfrac{1}{12+\cfrac{1}{14+\cfrac{1}{15+\cdots}}}}}}}}$ – 2011-11-18
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0[This question](http://math.stackexchange.com/questions/63865) is the dual of this question. – 2011-11-18
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0Maybe I should have omitted "$1+{}$" at the beginning. – 2011-11-18