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I know that we take characteristic polynomial of forms like $\lambda^2 - \lambda - 2$ to find out the solution of ordinary differential equation of the form $e^{\lambda x}$ - conjugate ones can be slightly modified. The question is, there are other forms of solution, right? So, why do people just use superposition of natural exponentiation forms when other solutions are available? Or am I mistaken?

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    There are no more.2012-12-25

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Since we are talking about homogeneous systems of first order differential equations, the solutions always use exponentials, but you can have several variants of eigenvalues that modify how you write the linear combination of solutions.

When you have real, distinct eigenvalues, the solution is a linear combination of exponentials using the eigenvalues and eigenvectors. See these notes for examples of this type.

When you have complex eignevalues, you can write the solution as a linear combination of complex eigenvalues, or using Euler's formula, as $e^{(a + ib)t}$ = $e^{at}cos(bt)$ + $ie^{(at)}sin(bt)$. See these notes for examples of this type.

When you have eigenvalues with varying geometric and algebraic multiplicity (sometimes called defective eigenvalues), that is, repeated eigenvalues, things get more interesting, so you want to look up what those terms mean. See these notes for examples of this type.

However, like Andre replied, they are always a form of the exponential because of the type of system we are dealing with. However, when you get to nonlinear systems, things can change drastically.

Regards

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    @amWhy: I hope the links helped the OP, but no feedback! Thanks for the support2013-05-11