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I have a literal equation that needs to be solved for $\theta$:

$mg \sin(\theta) = \mu mg \cos(\theta)\left({ M+m \over m}\right) $

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    @jay [I wrote a tutorial / reference for the equation editor](http://meta.math.stackexchange.com/questions/5020/tex-latex-mathjax-basic-tutorial-and-quick-reference).2012-08-28

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A simple rearrangement shows that $\tan\theta = \mu\left(1+\frac{M}{m}\right)$ to obtain numerical values for the equation you'll need the ratio of the masses and the coefficient of friction, in which case you can simply take the arctangent.