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Can some one explain to me what is a curve integral of first kind and what is a curve integral of 2nd kind? I have to understand this for my calculus exam.

I know how to compute the area of the wall between the graph of f(x,y) and curve $\gamma$ on XoY plane in this case:

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The area is $\int f(x,y) \,ds$, where $\,ds = \sqrt {(\,dx)^2 + (\,dy)^2}$ and $x$ and $y$ get parametrized like this: $x = x(t)$ and $y = y(t)$

So my integral becomes (maybe not written 100% correctly): $\int f(x,y) \sqrt{(\,dx)^2 + (\,dy)^2}$

But we know that $x = x(t)$ and $y=y(t)$ the integral becomes: $\int f(x(t),y(t)) \sqrt{(\,dx)^2 + (\,dy)^2}$

Then: $\sqrt{(\,dx)^2 + (\,dy)^2} = \frac {\,dt}{\,dt} \sqrt{(\,dx)^2 + (\,dy)^2} = \frac {1}{\,dt}\sqrt{(\,dx)^2 + (\,dy)^2}\,dt = \sqrt{(\frac{\,dx}{\,dt})^2 + (\frac{\,dy}{\,dt})^2}\,dt$

And finaly the formula for the area: $\int f(x(t),y(t)) \sqrt{(\frac{\,dx(t)}{\,dt})^2 + (\frac{\,dy(t)}{\,dt})^2}\,dt$

Following this I have another question is this the first kind line integral? Is it the second kind line integral? Or it has nothing in common with first and second kind line integrals?

I played around with $f: R^2 \rightarrow R$ and $\gamma$ a parametrized path on XoY plane so a discussion with an $f: R^n \rightarrow R^m$ would be appreciated.

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    The way you calculate a 2nd kind integral, say of a (vector) function $\vec{F}(x,y)$ along a curve $\vec{r}(t)$, where $a\le t\le b$ is this: $\int_a^b \vec{F}(\vec{r}(t)) \cdot \overrightarrow{r'}(t)\, dt$. What we did is translate a 2nd-kind line integral into an ordinary integral. You are right that $\vec{r'}(t)$ is the particle's velocity. It can also be viewed as a tangent vector to the path, at $\vec{r}(t)$.2012-09-04

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Answer based on comments by Teddy

A line integral of the 1st kind, is the integral of a scalar ($\mathbb{R}^2 \to \mathbb{R}$, say) function, such as the one used in your question to calculate the area of a fence. Another interpretation is the mass of a wire with variable density $f(x,y,z)$.

A line integral of the 2nd kind, is the integral of a vector function ($\mathbb{R}^2 \to \mathbb{R}^2$), which you'd use to calculate e.g. the work done by a force acting along the line.

The way you calculate a 2nd kind integral, say of a (vector) function $\vec{F}(x,y)$ along a curve $\vec{r}(t)$, where $a\le t\le b$ is this: $\int_a^b \vec{F}(\vec{r}(t)) \cdot \overrightarrow{r'}(t)\, dt$. What we did is translate a 2nd-kind line integral into an ordinary integral. Here $\vec{r'}(t)$ is the particle's velocity. It can also be viewed as a tangent vector to the path, at $\vec{r}(t)$.