I am trying to solve a equation $(2^x)(3^{x-2}) = 4$ (the solution is $x = 2$)
My approach is to use the natural logarithm $\ln$ (that's suggested when googleing the problem)
So this is how it goes for me:
$\ln{2^x}\cdot\ln{3^{x-2}} = \ln{2^2}$
but I am unsure if using $\ln$ is correct or where to go from here.