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I have always been terrible with these, but how does $\frac{-36}{\sqrt{3^5}}$ equal $\frac{-4}{\sqrt{3}}$ ?

completely butchered the latex... I have -36/(root3)^(5) where the exponent is in the denominator. This equals -4/root3.

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    Note $(\sqrt3)^2=3$, and $a^5=a^2a^2a$.2012-09-27

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Hint: $\sqrt{3^{5}}=\sqrt{3^{4}\cdot3}=3^{2}\sqrt{3}=9\sqrt{3}$ . Also note $\frac{36}{9}=4$