I know how to convert $\sinh^{-1}{x}$ and $\cosh^{-1}{x}$ to $\ln{|x+\sqrt{x^2 \pm 1}|}$, but for some reason I am struggling to do the same for the following statement:
$\tanh^{-1}{\frac{x}{2}}$
Can someone please show me how to convert it to a $\ln$ form? thanks!