How to come from this equation to
$ \sum_{i=0}^n k = {n(n+1)\over 2} + (n+1) $
this equation:
$ \sum_{i=0}^n k = {(n+1)(n+2)\over 2} $
Thanks in advance for your answer!
How to come from this equation to
$ \sum_{i=0}^n k = {n(n+1)\over 2} + (n+1) $
this equation:
$ \sum_{i=0}^n k = {(n+1)(n+2)\over 2} $
Thanks in advance for your answer!
$\sum_{i=0}^{n}k=\frac{n(n+1)}{2}+(n+1)=\frac{n(n+1)}{2}+\frac{2(n+1)}{2}=\frac{n(n+1)+2(n+1)}{2}=\frac{(n+2)(n+1)}{2}$