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How can I calculate the following probability:

Throwing a die 6 times, what is the probability of having face no. 1 showing at least one time.

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    I corrected dice/die thingy, thanks for the input. @DanielMontealegre your comment made Alex Becker's answer even more clear.2012-03-01

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Consider the probability of having no 1 appear in each roll, which is $5/6$. Since the outcomes of each roll are independent, the probability of having no 1 appear in six rolls is $(5/6)^6$. Thus the probability of having a 1 appear at least once is $1-(5/6)^6=\frac{31031}{46656}$.

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    Great, thanks. Problem solved!2012-03-01