$A(-3,1), B(0,-5), P(X,Y)$
If $|AP| = 2|BP|$ prove that $x$ and $y$ satisfy the equation:
\begin{aligned} \ x^2+y^2-2x+14y+30 =0 \end{aligned}
I get as far as determining the co-ordinates like so
\begin{aligned} \ \sqrt{(x+3)^2+(y-1)^2}= 2\sqrt{(x)^2+(y+5)^2} \end{aligned}
To
\begin{aligned} \ x^2+y^2+2y+40-6x =0 \end{aligned}
Which gives me $(3, -1)$, this won't satisfy, is my method correct?