Write the following numbers as a sum of two squares:
$(a) 13\times17$ $13\times17=221$ $m=13=(3^2+2^2) \space \text{and} \space n=17=(4^2+1^2)$ $[(3)(4)+(2)(1)]^2+[(3)(1)-(4)(2)]^2=14^2+(-5)^2=221$
I had no problem solving this one. However, the next problem is giving me trouble because $19^{10}$ is such a large number.
$(b) 13\times19^{10}$
$13\times19^{10}=79703861351413$ I can only find this number using wolfram. My calculator wont display all the digits. Which is a problem.
$m=13=(3^2+2^2) \space \text{and} \space n=19^{10}=(c^2+d^2)$
Is there a easy / simple method I can use to find $c$ and $d$?