how I should find $\delta$ > 0 that if $|x - 1| < \delta$ then $|\frac{x^2-7}{2x+1} + 2| < 10$?
I got something like that $\frac{|x-1||x + 5|}{|2x+1|} < 10$ and I also proved in previous question that if $|x-1| < 1$ then $|x+5| < 7$ and $2x+1 > 1$.
if $|x-1|<1$ then I know that $|x - 1| < 1 \leq \delta$ then I can say that $\frac{|x-1||x + 5|}{|2x+1|} < 7\delta < 10$ but I don't know how to continue for here...