Basically what I have is that $x,y \in \mathbb{R}$ and that $3x + 2y \leq 5 $, so what I need to prove is that $x > 1 \rightarrow y < 1$
How would you prove this?
In some way i know that if I make $y \leq \frac{5-3x}{2}$, I would find an expression in which I certainly know that all the values that the variable $y$ is going to take will be less than $1$ because one of the premise is that $x > 1$, but I'm not sure if this is enough to make a correct proof.