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-Hi, everybody. This is a problem from an assignment dealing with, among other things, power series, liouville's theorem, the extended liouville theorem, the fundamental theorem of algebra, and analytic functions.

Sorry for not doing a proper post. Thanks for all the help!

We are asked to find the radius of convergence R of the power series expansion about z = 1 of the function

$ f(z) = \frac{1}{1 + z^2 + z^4 + z^6 + z^8 + z^{10}} $

in terms of real numbers and square roots only. (That's how the problem is phrased :-/).

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    Oops, actually I realized I should have stopped at an earlier step so that $|1-w_k| = \sqrt{2(1-cos(\frac{2kpi}{n})}$. R is the distance to the nearest singularity, which is the minimum of $|1-w_k|$. The minimum is obtained when k = 1, so we have R = $\sqrt{2 - \sqrt{3}}$. haha! thanks for all of the help everybody :D2012-10-15

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A full answer to the question as the question is phrased at the moment is $ R=\sqrt{2-\sqrt3}. $ Nota: If the question is rephrased to become more in line with the way the site is supposed to function, then the present answer might be rephrased to become more in line with the way the site is supposed to function (until then, why should it be?).

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The denominator factors like $(z^2+1)(z^2+z+1)(z^2-z+1)(z^4-z^2+1)$. The singular points are the roots of this polynomial. The closest distance from $1$ to the 10 roots is the radius of convergence.