I am trying to understand a solution to a problem. Here's the problem.
Abe will sell his calculator to the person to offer him at least \$130 for it. The offers are independent exponential random variables with mean $100. What's the expected number of offers Abe will receive?
The solution notes that the offers for the calculator are $C_x \sim Exponential(\frac{1}{100})$, which I can understand from the problem. It then says that the number of offers that are below \$130 has a geometric distribution with $p = e^{\frac{-130}{100}}.
Where did e^{\frac{-130}{100}}$ come from? I thought that the expected value for an exponential distribution was $\frac{1}{\lambda} = 100$.