A Circle is inscribed in a triangle $ABC$, where $AB=10 cm$, $BC=9 cm$ and $AC=7 cm$ . $X$, $Y$, $Z$ are points of contact of the sides $AC$, $BC$ and $AB$ with the circle respectively. $BZ=?$
In the first look, question looked simple to me. But I am not able to get to the answer. I found the In-radius using $rs = \sqrt{s(s-a)(s-b)(s-c)}$. But that is not helping me to find the required length.
In the above formula, r= indradius s=(a+b+c)/2 a,b,c -> Lengths of the sides of triangle
I would be glad to see the answer of this question. Any Hints or answers are welcome. Thanks.
Sandy