I'm not absolutely sure on how I can deal with this problem with this problem:
Find $ \dfrac{dy}{dx} $ if $ y = 2u^2 - 3u $ and $ u = 4x - 1 $
I am trying to use the chain rule on it.. $ \dfrac{dy}{dx} = \dfrac{dy}{du} \dfrac{du}{dx} $
My work so far: $ \dfrac{d}{du}(2u^2-3u) * \dfrac{d}{dx}(4x-1) = (4u-3)(4) $
However I am not absolutely sure I am doing it right.. and I don't have the answer in my book.
Thanks for help, it's appreciated !
EDIT: typos.