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Is there a closed form expression for $\text{n}^{\text{th}}$ coefficient of Maclaurin series of
$\ln(1-x+x^2)$

1 Answers 1

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Hint: $\ln(1-x+x^2)=\ln\left(\dfrac{1+x^3}{1+x}\right)$

Use (two times!) the expansion of $\ln(1+t)$ to conclude!

Hoping this helped,

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    @MartinGales: Glad it helped!2012-04-16