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The problem I have is to differentiate $ y = ln(x^4)$

Using the rule : $\frac{d[lnf(x)]}{dx}=\frac{f'(x)}{f(x)}$ My working is: $\frac{dy}{dx} = \frac{x^4ln(x)}{x^4}$ $=ln(x)$

but the book is giving the answer : $\frac{4}{x}$

Please help because I am confused

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    Caution: $\log x^4=4\log |x|\neq x^4\log x\;\;!$2012-11-27

2 Answers 2

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$f(x) = x^4$. Thus $f'(x) = 4x^3$. Plug into provided rule.

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    Note that the "rule" is merely an application of the [chain rule](http://en.wikipedia.org/wiki/Chain_rule).2012-11-27
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Following my comment and assuming $\,x>0\,$ to avoid the absolute value:

$y=\log x^4=4\log x\Longrightarrow y'=\frac{4}{x}= $

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    Thank you, another way which makes it easy to work out...2012-11-27