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Its given that $[Z]=3$ $[Z^{2}]=11$ $[Z^{3}]=41$

Then, what is the number of all possible values of $[Z^{6}]$ where $[\;\cdot\;]$ is floor function.

1 Answers 1

6

Hint: $ [Z^k]=b\quad\Longleftrightarrow\quad b\leq Z^k

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    sorry, my bad :(2012-08-08