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Which of the following subsets of $\mathbb{R}^2$ are compact?

  • (a) $\left\{ (x, y) : xy = 1 \right\} $
  • (b) $\left\{ (x, y) : x^{2/3} + y^{2/3} = 1 \right\}$
  • (c) $\left\{(x, y) : x^2 + y^2 < 1\right\}$

clearly a and c are not compact. not sure about b

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    http://en.wikipedia.org/wiki/Astroid2012-09-01

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Is the set bounded? For all $x\in\Bbb R$, $x^{2/3}\ge 0$, so if $x^{2/3}+y^{2/3}=1$, how big can $x$ and $y$ be?

Is it closed? That’s harder to answer rigorously, but a glance at the graph of the expression should give you a pretty good idea.

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    @Sriti: Yes, if one knows that fact about continuous functions, there’s an easy way to justify the conclusion.2013-08-21
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A subset of $\mathbb{R}^n$ is compact iff it is closed and bounded.

a) closed but unbounded so not compact.

b) closed and bounded.see the graph

c) Open set.