$\log N=\frac{1}{2}(\log24-\log0.375-6\log3)$ find value N.
I did it below step
$\log N=\frac{1}{2}(\log64-6\log3)$
$\log N=\frac{1}{2}(\log0.877)$
I don't know how continue further
the answer from book is
$N=\frac{2}{3}^3$
$N=\frac{8}{27}$
Thanks your help!