4
$\begingroup$

Where am I going wrong?

Find the difference quotient for: $f(x)=2-x-3x^2$

$\frac{[ 2-(x+h)-3(x+h)^2 ] - [ 2-x-3x^2 ]}{h}$

$\frac{2-x-h-3x^2-6hx-3h^2-2+x+3x^2}{h}$

$\frac{-3h^2-6hx-h}{h}$

$-3h-6x-1$

1 Answers 1

3

Well, nowhere. Everything is OK.

  • 0
    Ok, I thought they were the same, Thanks2012-05-30