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If I take any whole number and divide by 1000 twice then is it only mathematically possible to have a maximum of 6 numbers right of the decimal point.

Example

999 / 1000 / 1000 = 0.000999  58679 / 1000 / 1000 = 0.058679 

My maths teacher has set all of the students in our class the task of finding an exception to this rule, I think it cannot be done!

Thanks

  • 0
    The simplest answer, if your teacher didn't specify that the digits had to be non-zero: $1/10^6 = 0.000001000...$2012-06-12

1 Answers 1

4

I can see four cases:

  1. He is wrong
  2. He is lying
  3. It's a trick question (like $10^6/1000/1000 = 0.999\ldots$, or base-n numbers)
  4. He wants you to prove that there is no exception.

I hope it's no.4.