I'm finding in trouble trying to resolve this exercise. I have to calculate the convolution of two signals:
$y(t)=e^{-kt}u(t)*\frac{\sin\left(\frac{\pi t}{10}\right)}{(\pi t)} $
where $u(t)$ is Heavside function
well I applied the formula that says that the convolution of this two signal is equal to
$Y(f)=X(f)W(f)$
where $X(f)$ is the fourier transform of the first signal and $W(f)$ is the fourier transform of second signal
well fourier transform of $e^{-kt}u(t)$ is $X(f)=\frac{1}{k+j2\pi f}$. I have to make second signal as equals as possible to $\operatorname{sinc}\left(\frac{\pi t}{10}\right)$ so I do this operation: $\frac{\sin\left(\frac{\pi t}{10}\right)}{\left(\frac{\pi t}{10}\right)}{\left(\frac{1}{10}\right)}$. this is equal ${\left(\frac{1}{10}\right)}\operatorname{sinc}\left(\frac{\pi t}{10}\right)$
right or not?
Edit
If something is not clear please advice me