$\int_0^1 \sqrt{(\sqrt{5})^2+(2t)^2}\;dt$
Based on the formula $\int \sqrt{a^2+x^2}\;dx=\frac{1}{2}[x\sqrt{a^2+x^2}+a^2\log(x+\sqrt{a^2+x^2})]$
I just plug in above input into the formula above
However I can only find $3+\frac{5}{2}\log(5)$ but answers that I get from Mathematica is $\frac{3}{2}+\frac{5}{8}\log(5)$
i been trying to figuring out what I been doing wrong for days but I still can't find out what I been doing wrong.
Appreciate if someone can show what I'm been doing wrong