I am working on this question:
Suppose that $\Delta u\leqslant0$ in $\Omega$ and $u=f$ on $\partial\Omega$, and $\Delta v\leqslant0$ in $\Omega$ and $v=f$ on $\partial\Omega$. Prove that $v(x)\leqslant u(x)$ for $x\in\Omega$ using the maximum principle.
I do not want an answer to it. The context of it is partial differential equations, and I do not know what the symbols mean.
I assume that
$\Delta=\nabla^2=\frac{\partial}{\partial x}+\frac{\partial}{\partial y}+\frac{\partial}{\partial z}$
is the Laplace operator, $\Omega$ is some subset of $\mathbb{R}^3$, and I have no clue what $\partial\Omega$ is; maybe it is the surface of $\Omega$? Also, how could I go about answering this question? I mean, I am thinking in terms of three dimensions, but both $u$ and $v$ are functions of one variable.
I am so confused!