This is a rates of change question:
A rectangular water tank has a square base with sides of length $0.55m$. Water is poured into the tank so that the fluid volume in the tank increases at a constant rate of $0.2m^3$ per hour. How fast is the water leveraging in metres per hour?
I've worked out the volume of the water tank $V=0.55 ^3 =0.166375m ^3$. From the question, $dv/dt=0.2m^3$ p/hr but I do not know what to do next. Any help will be beneficial.