So, you need two things: $ 4 - x^2 - y^2 \geq 0 $ to get make the square root work, and also $ x-y > 0 $ to make the logarithm work.
You will be graphing two regions in the $xy$-plane, and your answer will be the area which is in both regions.
A good technique for graphing a region given by an inequality is to first replace the inequality by an equality. For the first region this means $ 4 - x^2 - y^2 = 0$ $ 4 = x^2 + y^2 $ Therefore, we're talking about the circle of radius two centered at the origin. The next question to answer: do we want the inside or outside of that circle? To determine that, we use a test point: pick any point not on the circle and plug it into the inequality. I'll choose $(x,y) = (5,0)$. Note that this point is on the outside of the circle. $ 4 - x^2 - y^2 \geq 0 $ $ 4 - 5^2 - 0^2 \geq 0 $ That's clearly false, so we do not want the outside of the circle. Our region is the inside of the circle. Shade that lightly on your drawing.
Now, do the line by the same algorithm.