I have given this: $ \frac{1}{8} \cot \left(\frac{t}{2}\right) \csc ^2\left(\frac{t}{2}\right) \csc (t) $
And I have to show that it is that: $\frac{1}{16} \csc ^4\left(\frac{t}{2}\right)$
I tried to use the doule angle formula on the $\sin(t)$, but I ended up with $\frac 14 \cot^2\left(\frac t2\right)$. Mathematica gets it right, but it does not tell me how it simplified it.
How do I do this?