I have been trying to evaluate this integral a few times. And my best attempt has been to rewrite is as a sum of linear combination of sine and cosine terms. Alas, this takes a couple of handwritten pages to accomplish. Is there any easier/faster/neater way to evaluate?
$ \int_{\pi/6}^{\pi/2} \sin(2x)^3\cos(3x)^2\,\mathrm{d}x=\left(\frac{3}{4}\right)^4 $
Thanks in advance =)