There is a question which states
The solid brick figure shown is made of small bricks of side 1. When the large brick is disassembled into its component small bricks , the total surface area of all small bricks is how much greater than surface area of larger brick
Here is how I am attempting it:
Surface Area of Large Brick = $6x^2=6(2)^2=24$
Surface Area of 1 small Brick = $6x^2=6(1)^2=6$
Total Small Bricks = 12 = So Total Surface Area = $72$
Difference = $72-24=48$
But the difference is suppose to be $40$. How ?
(EDIT : Image Edited)