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Trying to find the vertices of a ellipse.

This is what I got enter image description here

And so used WolframAlpha just to test it out, this is my third time using it. This is the solution that I got

enter image description here

So as you can see in the implicit plot it shows that in the positive y-axis it is 2.26? would be the answer?

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    I guess the vertices in this case will be the points of the ellipse in the graph2012-10-21

1 Answers 1

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Because the ellipse is centered at the origin, the verticies occur where one of the coordinates equals 0.

Setting $x=0$: $49y^2=251$ $y = \pm {\sqrt{251} \over 7}$

Setting $y=0$: $23x^2 = 251$ $x = \pm \sqrt{251 \over 23}$

Your question asks for the positive x intercept($y=0$). That's $(0,{\sqrt{251} \over 7})$.

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    I have no choice but to agree with you, lol. Tks for the clarification.2012-10-22