I have a question about the integral of $\ln x$.
When I try to calculate the integral of $\ln x$ from 0 to 1 I always get the following result.
- $x(\ln x -1)$ (integral of $\ln x$)
- $1(\ln 1 -1) - (0 (\ln 0 -1))$
But the second part of the calculation is indeterminate.
What am I doing wrong?
Thanks Joachim G.