before I ask for anything I must admit I'm working hard to understand this beautiful subject. Thanks in advance. $ f(x)= 2(x)^2+8x+5 $ Acoording to the graph of this function, there is a x-axis symmetry. The problem is I can not prove it algebraically. Thanks again.
Finding correct symmetry axis
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algebra-precalculus
symmetric-functions
3 Answers
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Do this $f(x) = 2(x^2 + 4x) + 5 = 2(x^2 + 4x + 4) + 5 - 8 = 2(x + 2)^2 - 3.$ Note that $f$ is insensitive to the sign of $x + 2$ so $f$ is symmetric about the line $x = -2$
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0Thanks, this forum is a great learning source. – 2012-10-23
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$f(x)=2\left(x^2+4x+\frac{5}{2}\right)=2((x+2)^2\pm...)$
So it is symmetric on $x=-2$ which is parallel to $y$-axis.