\[ \sqrt{a-b} + \sqrt{b-c} + \sqrt{c-d} + \sqrt{d-a} = K \] for some real constant $K$ and some real numbers $a$, $b$, $c$ and $d$. Find $K$.
Again i apologize for the syntax and appreciate anyhelp thanks!
\[ \sqrt{a-b} + \sqrt{b-c} + \sqrt{c-d} + \sqrt{d-a} = K \] for some real constant $K$ and some real numbers $a$, $b$, $c$ and $d$. Find $K$.
Again i apologize for the syntax and appreciate anyhelp thanks!
Here $a, b,c,d,K$ are real numbers.
$\sqrt{a-b} , \sqrt{b-c} , \sqrt{c-d} , \sqrt{d-a}$ are real numbers because K is real number.
So,$\sqrt{a-b}$ real numbers means $ a \geq b$ and rest of also same as thing as.
That is, $ a \geq b, b \geq c, c \geq d, d \geq a$
This implies $a=b=c=d$, The value of K should be zero.