$C_4 = \{e, a, a^2, a^3\}$
A normal subgroup of $C_4$ is $C_2 = \{e, a^2\}$
So I am wondering what the quotient group $G/N$ looks like in this case.
Ie. where $G = C_4$ and $N = C_2$.
The right (or left) cosets of $N$ are
$Ne = \{e, a^2\}$ and
$Na = \{a, a^3\}$
$G/N$ is the group formed by these cosets so I have it as = $\{ \{e, a^2\}, \{a, a^3\} \}$
Is that right...it seems weird having each element being a set of elements..?