I need to find the area of the region that is bounded by $y=x^2-4$ and $y=2x-1$
I think I solved it, but I don't know what the right answer is so I'm not sure!
I got:
$da = wl$ $=(x^2-4)-(2x-1)dy$ $=(x^2-2x-3)dy$ $\int{}da = \int{(x^2-2x-3)dy}$ $a = \frac{x^3}{3}-x^2-3x+c$