Let $x_1 > 0$ and
$ x_{n+1} = 1/2 (x_n + 2/x_n)= x^2n+2/2x_n, n\geq1.$
Does $\{x_{n+1}\}$ converge? If so, find its limit.
Hint: Prove first that if $a, b \geq 0$ ,then $ 2ab \leq a^2 + b^2. $
I don't see how the hint is suppose to help.
Let $x_1 > 0$ and
$ x_{n+1} = 1/2 (x_n + 2/x_n)= x^2n+2/2x_n, n\geq1.$
Does $\{x_{n+1}\}$ converge? If so, find its limit.
Hint: Prove first that if $a, b \geq 0$ ,then $ 2ab \leq a^2 + b^2. $
I don't see how the hint is suppose to help.
Suppose it converges, then both ${x_n}$ and ${x_{n+1}}$ approach the same limit, say $x$. This means (if I deciphered your expression correctly) $x = \frac{1}{2}\left( {x + \frac{2}{x}} \right)$ or $2{x^2} = {x^2} + 2$ so $x = \pm \sqrt 2.$ Since all terms are positive, the limit must be $\sqrt 2$.