I have this differential equation $y'=\frac{y(\sin t)}{t}$, $y(0)=2$, and $h=\frac{1}{4}$. The first set of values, the inital, are $(0,2)$. For the next iteration would it be $y_1=2+(\frac{1}{4})\left(\frac{2\cdot\sin(0)}{0}\right)$? I know you can't divide by zero, so what would should I do in this case?
Thank you.