A veterinarian has 5 dogs and 4 cats available for adoption. Four of the dogs are brown and 1 is gray.Three of the cats are browm and 1 is gray. Jena selects two animals at random. Find the probability that at least 1 is a cat given that at least 1 is gray.
Question on Conditional probability
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probability
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4What are your thoughts on the question? – 2012-09-26
1 Answers
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If I understood correctly we have to have 1 cat and 1 animal has to be gray. Lets count good possibilities p.
- We take gray cat. p = 8 (any animal other then gray cat)
- We do not take gray cat. So at least one has to be cat and we have to take the gray dog. So there is p = 3 (we have gray dog, we have to choose one brown cat, the gray cat is counted in option 1)
These two options are distinct. So all good p = 11 and the probability is 11/72
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0Although the answer misses the mark ("given that" indicates conditional probability), I upvoted it because this is about as much as the OP deserves. – 2012-09-27