4
$\begingroup$

I need to show

\[\left(\frac{y}{y-1}\right)^y = \left( 1 + \frac 1{y-1}\right)^y \]

I cannot understand how they made this step! Can someone explain how this works?

2 Answers 2

10

We have \[ \frac y{y-1} = \frac{y-1+1}{y-1} = \frac{y-1}{y-1} + \frac 1{y-1} = 1 + \frac 1{y-1}. \]

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    Thank you very much Martini! Perfect!2012-10-19
6

$ \frac{y}{y-1} = \frac{y-1+1}{y-1} = \frac{y-1}{y-1} + \frac{1}{y-1} = 1+ \frac{1}{y-1} $

There's the line of thought I use. You add and subtract one (adds up to zero, so it's allowed), then you rearrange everything to get the final result.

Edit: crud, not quick enough...

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    This is the same @martini did (+1). :)2012-10-19