If a and b are the roots of the equation $2x^2-px+7=0$ Then a-b is a root of ?
How do I transform the equation based on this condition?
2
$\begingroup$
algebra-precalculus
polynomials
quadratics
1 Answers
5
So, $a+b=\frac{p}{2}$ and $ab=\frac{7}{2}$
If $y=a-b=>y^2=(a+b)^2-4ab$
$=>y^2=(\frac{p}{2})^2-4 \frac{7}{2}$
So, a-b is a root of $4y^2-p^2+56=0$