Where am I going wrong?
Find the difference quotient for: $f(x)=2-x-3x^2$
$\frac{[ 2-(x+h)-3(x+h)^2 ] - [ 2-x-3x^2 ]}{h}$
$\frac{2-x-h-3x^2-6hx-3h^2-2+x+3x^2}{h}$
$\frac{-3h^2-6hx-h}{h}$
$-3h-6x-1$
Where am I going wrong?
Find the difference quotient for: $f(x)=2-x-3x^2$
$\frac{[ 2-(x+h)-3(x+h)^2 ] - [ 2-x-3x^2 ]}{h}$
$\frac{2-x-h-3x^2-6hx-3h^2-2+x+3x^2}{h}$
$\frac{-3h^2-6hx-h}{h}$
$-3h-6x-1$
Well, nowhere. Everything is OK.