I tried to identify a formula that is appropriate for computing the Laplace transform of $f(t)=\displaystyle\frac{\cos 2t-\cos 3t}{t}$ but I couldn't find one. Give me a suggestion please. Thanks, Alex.
Laplace transform of a signal over t
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laplace-transform
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0@B R and @ TenaliRaman Thank you very much! – 2012-04-25
1 Answers
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$\begin{align*} \int\limits_s^\infty G(u)\cdot\text du &=\int\limits_s^\infty\int\limits_0^\infty g(t)e^{-ut}\cdot\text dt\cdot\text du \\&=\int\limits_0^\infty g(t)\int\limits_s^\infty e^{-ut}\cdot\text du\cdot\text dt \\&=\int\limits_0^\infty g(t)\left.\frac{e^{-ut}}{-t}\right|_s^\infty \cdot\text dt \\&=\int\limits_0^\infty \frac{g(t)}te^{-st}\cdot\text dt \\&=\mathcal L\left\{\frac {g(t) }t \right\} \end{align*}$
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0$f(t)=\frac{g(t)}t$ – 2013-01-01