I don't know if $f$ is continuous. I believe that isn't necessarly continuous but I don't know some example. If it is continuous I don't know how to prove.
If $f\circ g$ is continuous and $g$ is continuous what about $f$?
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real-analysis
general-topology
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0If "what about f" means what about continuity of f then you have to put more conditions at least one of them must be g is onto but it is not enough.... – 2012-05-17
2 Answers
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For example take any $f$ and $g=0$.
For a less trivial example: take $f(x)=\left\{ \begin{array}{cc} 1 & x\in\mathbb{Q}\\ -1 & x\notin\mathbb{Q} \end{array}\right.$.
Take $g(x)=[x]$. Then $f(x),g(x)$ are both not continuous, while $f(g(x))=1$ is. (Of course you can take a constant function $g$ - in that case $g$ will be continuous)
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0@DennisGulko Thanks for non-trivial example and your effort to help me. – 2012-05-16
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If $g$ is a constant function, $f \circ g$ can be continuous while $f$ isn't necessarily so.
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2Sorry, I can't validate two answers. Both are correct in the same time. – 2012-05-16