I have found this question:
Suppose in a competition $11$ matches are to be played, each having one of $3$ distinct outcomes as possibilities. What is the number of ways one can predict the outcomes of all $11$ matches such that exactly $6$ of the predictions turn out to be correct.
My approach is: Any $6$ games(that will be predicted correctly) can be selected from $11$ games in $\binom{11}{6}$ ways and since each game has three possible results, there can be $\binom{11}{6}\cdot 3^5$ ways.
Please correct me if I am wrong.