I have been trying to figure this question out for a while now, it's in a past paper I'm studying for my Calculus exam tomorrow. But we don't get given the memo's. I have done simpler versions of this question where it was a straight line, but this really confused me. Please can you guys help me out, or if you don't like giving answers straight out, can you please push me in the right direction?
Determine at which values f(x) is continuous: f(x) = 2x if x <= 0 f(x) = sinx if 0 < x <= pi f(x) = (x-pi)^2 if x > pi
Any help would be appreciated. Thanks in advance.