An isosceles triangle $ABC$ has 2 given vertices, $A(3,2)$ and $C (7,14$). The slope of AB is $\dfrac{1}{2}$. What are the coordinates of B?
I could figure out that line AB = $\dfrac{1}{2}x + \dfrac{1}{2} $
I found that the length of AC = is $\sqrt{160}$
But I haven't got a clue as to finding the coordinates of B.. can someone give me a hint?