$r(t) = \langle 2t, t^2, \ln t \rangle.$
I know that to find arclength you do $L = \int_a^b \|r'(t)\| ~dt.$
I found $r'(t)$ to be $r'(t) = \left\langle 2, 2t, \dfrac{1}{t} \right\rangle$.
To find $\|r'(t)\|$ I did
$\sqrt{(2)^2 + (2t)^2 + \dfrac{1}{t^2}}$
but how do I integrate that?