Show that the functions $\{1 + 2t, 3 − 2t, −1 + 7t\}$ are linearly dependent by writing one of these functions as a linear combination of the other two
Show that the functions ${1 + 2t, 3 − 2t, −1 + 7t}$ are linearly dependent by writing one of these functions as a linear combination of the other two
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0Just a sidenote (and maybe not relevant for you): When saying that something are linearly dependent, you have to say "over what". In this case, your functions are linearly dependent over $\mathbb{R}$, the real numbers. – 2012-03-29
2 Answers
Choose one of the three functions, say $-1 + 7t$. If it can be written as a linear combination of the other two, then there exist constants $a$ and $b$ such that $-1+7t = a(1+2t) + b(3-2t)$
This has to hold for all values of $t$, so the coefficient of $t$ on the left must match that on the right; similarly, the coefficient of the units must match on both sides. This will give you a system of equations for $a$ and $b$.
The following is good if you have more functions.
We put these functions into a matrix, $M$ and do row and column manipulations as follow:
$M=\begin{pmatrix} 1 &2 \\ 3 &-2 \\ -1 & 7 \end{pmatrix}$
$\sim\begin{pmatrix} 1 &2 \\ 3 &-2 \\ 0 & 9 \end{pmatrix}$
$\sim\begin{pmatrix} 1 &2 \\ 3 &-2 \\ 0 & 1 \end{pmatrix}$
$\sim\begin{pmatrix} 1 &0 \\ 3 &-2 \\ 0 & 1 \end{pmatrix}$
We can see that, $R_2$ is linear combinations of $R_1$ and $R_3$, $R_2=3R_1-2R_3$