This is gamma function: $\Gamma (n) = \int_0^\infty x^{n-1}e^{-x}\,dx$ What will be Result if I add Imaginary Number to Exponential of Euler Gamma Function?
$? = \int_0^\infty x^{n-1}e^{-ix}\,dx$
where the $i^2=-1$
isn't it a new function!? it will and will not converge?