I am stuck at this question cant think of how to resolve this, sorry I did try to do working but can't think of any right solution. The question is
If the denominator is $9900$, then what is the corresponding numerator of the fraction with the recurring decimal $0.ab\overline{cd}$ when $a = 7$, $b = 6$, $c = 7$, $d = 6$? Don't forget that the denominator must be $9900$ and note that the bar is above $cd$ only.
Ok after some more googling, I came to know I have to do this:
Step 1, Substitute
$0.7676$
Step2, Solve
let $x = 0.7676$ --- (1)
$100x = 76.76$ --- (2)
then $(2) -(1)$
so answer will be $75.99$, correct?