In the triangle $ABC$ we have
$\tan{\frac{A}{2}}=\frac{1}{3}$
$b+c=3a$
Specify which of the following answers is correct:
$a) m(\angle B)=\frac{\pi}{2}$ or $m(\angle C)=\frac{\pi}{2}$
$b) m(\angle A)=m(\angle B)$
$c) m(\angle A)=\frac{\pi}{2}$
$d) m(\angle B)=\frac{\pi}{4}$ or $m(\angle C)=\frac{\pi}{4}$
$e) m(\angle A)=m(\angle C)$
$f) m(\angle A)=\frac{\pi}{3}$
I'm lost here. I don't know how I can use $\tan{\frac{A}{2}}=\frac{1}{3}$ so I get to an answer. Can someone give me a solution? I have many exercises involving the $\tan{\frac{A}{2}}$ function and I can't continue.
Thank you very much!