With $ω=se^{iφ}$, where $s≥0$ and φ∈ , solve the equation $z^n=ω$ in C where n is a natural number. How many solutions are there?
I have the solutions to this problem however, do not understand its steps.
I do not understand how $z=s^\frac 1n e^{(i\frac \phi n+\frac{2kpi}n)}$ where $k \in Z$.
Where is the $2k\pi$ coming from?
Any verification will help thank you