Is $2^\sqrt{2}$ irrational? Is it transcendental?
Deciding whether $2^{\sqrt2}$ is irrational/transcendental
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number-theory
transcendental-numbers
rationality-testing
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4@J.M.: As far as I understand it the Hilber's problem is to decide wheter it is trascendental, not to decide whether it is irrational. – 2012-07-22
1 Answers
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According to Gel'fond's theorem, if $\alpha$ and $\beta$ are algebraic numbers (which $2$ and $\sqrt 2$ are) and $\beta$ is irrational, then $\alpha^\beta$ is transcendental, except in the trivial cases when $\alpha$ is 0 or 1.
Wikipedia's article about the constant $2^{\sqrt 2}$ says that it was first proved to be transcendental in 1930, by Kuzmin.