I’ll use $d(x,y)$ for the distance between $x$ and $y$. To show that $d$ is a metric, you must show the following four things:
$d$ is non-negative: For all DNA molecules $x$ and $y$, $d(x,y)\ge 0$.
$d$ separates points: $d(x,y)=0$ if and only if $x=y$.
$d$ is symmetric: For all DNA molecules $x$ and $y$, $d(x,y)=d(y,x)$.
$d$ satisfies the triangle inequality: For all DNA molecules $x,y$, and $z$, $d(x,y)\le d(x,z)+d(z,y)$.
You should have absolutely no trouble verifying (1)-(3): they are trivial consequences of the definition of $d(x,y)$. The only one that requires some work is the triangle inequality. Here’s a suggestion.
Start with three arbitrary DNA molecules $x,y$, and $z$. Let $D_{xy}$ be the set of positions at which $x$ and $y$ differ, i.e., $D_{xy}=\{k:x_k\ne y_k\}$. Similarly, let $D_{xz}$ be the set of positions at which $x$ and $z$ differ, and let $D_{yz}$ be the set of positions at which $y$ and $z$ differ. By definition $d(x,y)$ is just $|D_{xy}|$, the number of elements in $D_{xy}$, and similarly for the other two pairs. Thus, you want to show that $|D_{xy}|\le|D_{xz}|+|D_{yz}|$.
Play with some examples for smallish $N$ and try to see how the sets $D_{xy},D_{xz}$, and $D_{yz}$ are related. For instance, if a position $k$ is in both $D_{xz}$ and $D_{yz}$, is it in $D_{xy}$? To say the same thing in different words, if $x$ and $z$ differ in position $k$, and $y$ and $z$ differ in position $k$, how do $x$ and $y$ compare in position $k$? Then go on to consider the various other possibilities.