Hi I have a simple algebra question which i can work out like the following $\begin{align} x - 8 & = x/3 + 1/6 \\ 6(x - 8) & = 6(x/3 + 1/6) \\ 6x - 48 & = 6x/3 + 6/6 \\ 6x - 48 & = 2x + 1 \\ 6x & = 2x + 49 \\ 4x & = 49 \\ x & = 49/4 \end{align}$
However, if I were to first remove the $8$ from the right hand side: $\begin{align} x - 8 & = x/3 + 1/6 \\ x & = x/3 + 49/6 \\ 3x & = x + 49/6 \\ 2x & = 49/6 \\ \end{align}$ How do I go from $2x = 49/6$ to $x = 49/4$?
I'm pretty confused so any guidance would be appreciated.