I am a new student of basic Mathematics and I am learning number systems, so this is a basic question. This exercise gives me the following duodecimal number:
9AX (where A=11, X=10)
And it requires to be converted to binary, octal and decimal. Of course I am doing this by hand so the answer could not be using WolframAlpha...
First, I am dividing the number to get the binary form, getting: (10011101001). Then, I group them in groups of four: (1001 1101 0010). Then, in groups of three: (100 111 010 010). This gives the octal number (4722). Final decimal number would be (2514).
My results are wrong according to the answer sheet. It should be (1011001010)2, (2625)8 and (1429)10.
Can you tell me what am I doing wrong? Thank you!