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I'm having a little trouble figuring out how to translate $ax^3+bx^2+cx+d=y$ by vector $(1,1)$ using only algebra. If possible could someone give me a hand?

An example:

Translate $f(x)=2x^3–3x^2+x+1$ by vector $(1,-1)$

(also, it's a vector, not a coordinate! sorry, I suck at MathJaX :(..)

Thank you! Any help is greatly appreciated :)

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    Thanks for clarifying. I think I've gotten the question the way you intended it. Check out the markup I used by clicking the timestamp next to my "edited" thing above.2012-09-21

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If you are trying to translate the graph of the function in the plane with the vector $(1,-1)$, then I can offer a hint in that direction. That would suggest you are moving the graph down one unit and right one unit.

From basic study of functions, we know that $f(x)+c$ moves the graph up by $c$ if $c>0$ and down by $c$ if $c<0$. Secondly, $f(x+c)$ moves the graph left by $c$ if $c>0$ and right by $c$ if $c<0$.

So, it looks like you need to compute $f(x-1)-1$, for your function $f(x)$.