1
$\begingroup$

Solve for $d$

$2x-2yd=y+xd$ $2(x-yd)=y+xd$ $2(x-yd)-y=xd$ $\frac{2(x-yd)-y}{x}=d$ Now I think this is wrong considering I have a $d$ on the other side and I would have to reverse my work and end up at the beginning. Any small pointers or tips? Thanks!

  • 0
    I re-wrote everything like I always do! I'm a good student!2012-07-16

1 Answers 1

2

(When I said "... write up your work in an answer", I meant like THIS!)

$2x−2yd=y+xd$ $2x - y = 2yd + xd$ $2x - y = d(2y + x)$ $\dfrac{2x-y}{2y+x} = d$

(You can formally "accept" any answer by clicking the check mark in the upper left hand corner. If you'd like to wait a few hours/days for a better answer to come along, or write your own, feel free. )