I have the following fraction:
$\frac{a^3-8}{a^2+2a+4}$
Because the numerator is the difference of two cubes, I've factored it like this: $(a-2)(a^2+8a+64)$.
The denumerator does not have natural roots, it would be factored in the following way: $((x-(1+(i)\sqrt{3})(x-(1-(i)\sqrt{3}))$.
My question is: can I simplify this fraction in another way without using complex numbers?