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I have the following conformal mapping:

enter image description here

I need to find $\lambda = f(\zeta)$ and its reverse. Zeros on the figure are given, the axis are oriented as usual. The resulting distance between the line and the circle does not matter.

I know how to map the left arrangement to a circle and a line:

$f(\zeta) = -i \frac{\zeta + iA}{\zeta - iA}$

but how do I make the bottom circle transform into a circle with a unit radius?

Unfortunately it's not a homework so you may give an answer as is, should it be easier.

2 Answers 2

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It turned out really easy, to transform a line and a circle to a line and a unit circle in the arrangement shown above one only has to divide by the radius of the circle.

So the final transform is:

$\lambda(\zeta) = -i \frac{\zeta + iA}{\zeta - iA} \frac{(H+A)^2-a^2}{2Aa}$

Gnuplot for you to try ($\text{Eta} = \lambda$):

set terminal postscript enhanced set output "Plot.ps" set parametric  set samples 100 set isosamples 10  set nokey  set size ratio -1 set xrange [-3 : 3] set yrange [-10 : 2] set trange [0: 2*pi]  Zeta(t) = A*exp(t*{0,1}) Eta(t) = (-{0,1} * (Zeta(t) + {0,1} * A) / (Zeta(t) - {0,1} * A)) * ((H+A)**2-a**2)/(2*A*a)  zeta(t) = {0,-1} * H + a*exp(t*{0,1}) eta(t) = -{0,1} * (zeta(t) + {0,1} * A) / (zeta(t) - {0,1} * A) * ((H+A)**2-a**2)/(2*A*a)  A = 1 a = 0.2 H = 2 set multiplot plot real(Zeta(t)),imag(Zeta(t)) lt 3 ,\      real(Eta(t)),imag(Eta(t))   lt 1 ,\      real(zeta(t)),imag(zeta(t)) lt 3 ,\      real(eta(t)),imag(eta(t))   lt 1 
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We can think of the two circles in the Riemann Sphere opposite to each other. Then we need a scaling transformation to change the original circle into the equator, and the second circle must be still a circle. Now the equator of the Riemann Sphere is the $x$-axis in the complex plane. For two circles in the general position some rotation, etc should be required. It seems to me the situation is rigid enough that you cannot expect a transformation turning the second circle into unit radius.

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    The scaling transformation will apply to both circles in the same time, so it is impossible to change one circle into the equator while still restricting the other circle's radius. I do not mean it cannot exist, only that a scaling+rotation argument is not suffice.2012-12-09