Consider a transcendental equation $f(x)=c$ , where $c$ is a constant and $f(x)$ is a transcendental function whose the radius of convergence of its taylor series is $\infty$ , once it has solutions, does it should have infinitely many solutions (include complex solutions)?
properties about number of solutions of transcendental equations
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algebra-precalculus
2 Answers
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I think this gives the picture:
If $f$ is an entire function that is not a polynomial then $f$ assumes every complex value, with one exception, an infinite number of times.
(Conway's book on complex analysis)
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0This is the Great Picard's Theorem. – 2012-05-30
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Not at all: the equation $e^x=\sum_{n=1}^\infty\frac{x^n}{n!}=c$ has one unique solution for each and every $\,\,c>0\,$
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0Either I missed the "including complex solutions" or that wass added later. Thanks – 2012-05-30