The natural logarithm is the logarithm to the base $e$, where $e$ is an irrational and transcendental constant. $e=\lim_{n\to \infty}\left(1+\frac {1}{n}\right)^n.$
$\ln a=\log_{e} a.$
I know that $\ln {(AB)}=\ln {(A}) + \ln {(B)}$ and $\ln {(A^B)}=B \ln {(A)}$.
Is there any difference between $\ln {(AB)}$ and $\ln {(A\cdot B)}$ ?
Is there any other way to solve $\ln {(A+B)}$ just like $\ln {(AB)}$ ?