Given an integer $n\geq 1$, it is known that there are only finitely many finite groups with exactly $n$ conjugacy classes.
Question: For $n\geq 3$, does there exists a finite non-abelian group, with exactly $n$ conjugacy classes?
Given an integer $n\geq 1$, it is known that there are only finitely many finite groups with exactly $n$ conjugacy classes.
Question: For $n\geq 3$, does there exists a finite non-abelian group, with exactly $n$ conjugacy classes?
For $k$ even the number of conjugacy classes of the dihedral group $D_k$ of order $2k$ is $(k+6)/2$. Hence take $k=2n-6$. If $n=3$, then take $S_3$,