Find the equation in polar coordinate form for a straight line through the points with polar coordinates $(4,0)$ and $(4,π/3)$.
Here's my steps:
1.Write the two points in cartesian coordinates: the two points are $(4,0)$ and $(2,4)$.
2.Find the cartesian equation of the line through $(4,0)$ and $(2,4)$: $y=-2x+8$
3.Replace $y$ with $rsin(ø)$ and $x$ with $rcos(ø)$.
so I get $rsin(ø)=-2rcos(ø)+8$ ->$r(sin(ø)+2cos(ø))=8$
The answer in my book is $rsin(ø+π/3)=2√3$
which can be written in the form of $√3y=4√3-x$
Can someone point out where I got wrong?