Given is a line with parametric equation:
$ x = 2 \lambda $
$ y = 1-\lambda $
Find out for which values of $\lambda$ the line is inside the circle of $x^2+4x+y^2-6x+5=0$
My attempt at solving this:
$x^2+4x+y^2-6x+5=0$
$x^2-2x+y^2+5=0$
$ (x-1)^2 -1 + y^2+5=0$
$ (x-1)^2 + y^2 =-4$
And that's where I'm stuck, this isn't correct. Can anyone point my in the right direction?