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$ \arctan\left(\frac{x}{\sqrt{a^2-x^2}}\right)$

Hi, I am not able to solve this problem from last 1 hour. Please help me to solve this question. As I can solve simple inverse trigonometric functions.

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    Set $x = a \sin(\phi)$, and simplify the argument of the $\arctan$. Are you assuming 0?2012-08-23

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Think geometrically. What is the $\tan(\phi)$ ?

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    @Sasha : You're right: I'm accustomed to pictures in which the "opposite" side is vertical and the "adjacent" side horizontal.2012-08-23