The maximum is 191.67 and the minimum -86.59 (though presumably the minimum could in theory go down as far as -100). So one possible linear transformation might be to have the top of the graph representing +200 and the bottom -100 using $f(x) = \frac{x+100}{3}$ which would give points to plot at
28.07, 19.5567, 4.47, 19.4433, 39.2167, 55.5567, 97.2233, 43.75, 41.4633, 33.3333
You can round these if you are restricted to integer values. If your graph looks upside down, then subtract all these values from 100.
More generally, if $M$ is the maximum or some convenient number above it and $m$ the minimum or some convenient number below it then you can use $f(x)=100 \times \frac{x-m}{M-m}$ or if you want it the other way up $f(x)=100 \times \frac{M-x}{M-m}.$