Number of ways in which $38808$ can be expressed as a product of $2$ coprime factors ?
the answer given is $8$ ways, what I did was,
$38808 = 2^3 \times 3^2 \times 7^2 \times 11$
so the number of ways of expressing $38808$ as product of $2$ co-prime factors should be
$8 \cdot (9.49.11)$ $9 \cdot (8.49.11)$ $49 \cdot (9.8.11)$ $11 \cdot (9.49.8)$
hence $4$, but the answer is $8$, am i missing some other co-prime factor pairs?