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Here I am stuck in solving Fourier transform and the funny part is that I am stuck in the basics, in the complex part. I hope someone can help me solve this part.

$ 3 + 3 ( \cos \frac{4\pi}3 + j \sin \frac{4\pi}3 ) - 6 ( \cos\frac{4\pi}3 - j \sin \frac{4\pi}3 ) \over -16 \pi^2$

If anybody is intrested in the question let me know.

Fourier transform:

another question is: how can I find the Fourier transform of $f(t) = e^{3t} ( H(t+2) - H(t) )$

I will highly appreciate the steps of the answers.

peace..

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    given a periodic function with period 3 : f(t) = (0 if -1<= t < 0) (t if 0<= t < 1) (2-t if 1<= t < 2)2012-05-28

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