Local football association has $10$ teams. Team A has $40\%$ chance to score a win in the game against better ranking opponent, and $75\%$ against worse ranking opponent. If team A is currently $4$-th on the ranking list, define probability that A will win in the next game.
So I have done the following here $0.4 \cdot 0.3$ ($3$ out of $10$ are better ranking opponents)+ $0.75 \cdot 0.6$ ($6$ are worse ranking opponents) = $\frac{1}{12} + \frac{3}{24} = \frac{5}{24}$.
I am not sure whether or not this is correct, but I plead you to elaborate this claim of mine.