When finding the norm of the vector:
Find $\|2w-2y\|$ such that $w=(1/2,3,1)$ and $y=(0,-1,3/2)$.
answer:
$\begin{align*} &2(1/2,3,1)= (1,6,2)\\ &2(0,-1,3/2) =(0,-2,3)\\ &(1,6,2)- (0,-2,3) = (1,8,-1)\\ &\sqrt{ 1^2 +8^2+(-1)^2}=\sqrt{66}= 8.124 \end{align*}$
Is this the correct way of doing it?
Thanks