The diagram can be viewed from this picture.
In the diagram the quadrilateral ABCD has point M on AB and point N on DC. We are given that $\frac{AM}{AB}=\frac{NC}{DC}$. Also we are given that the line segments AN and DM intersect at P, and MC and NB intersect at Q. How do we prove that the area of quadrilateral MNPQ equals the sum of the areas of triangle APD and triangle BQC.
My progress: The only thing that stands out is that the whole entire problem is most likely based on taking ratio of areas. I've played around with this for like 30 minutes to an hour and got nothing. No lines are parallel so I dont see what else can be done.
Thanks!!