When solving
$\ln(x^2+1) = \ln(x) + 2$
I'm getting stuck at
$e^2 = \dfrac{x^2+1}{x}$
How do I isolate $x$?
When solving
$\ln(x^2+1) = \ln(x) + 2$
I'm getting stuck at
$e^2 = \dfrac{x^2+1}{x}$
How do I isolate $x$?
$e^2=\frac{x^2+1}{x}\Longleftrightarrow x^2-e^2x+1=0$
and you have a simple quadratic to solve.