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Use logarithmic identities to simply the following:

$lg(a^2+b^2)^2$

I started with

\begin{eqnarray} lg(a^2+b^2)^2&=&2 \cdot lg(a^2+b^2) \\ \end{eqnarray}

I think it's not the final result, but I don't know how to proceed. Any hints would be helpful.

  • 0
    What about $4\lg c$, since $a^2+b^2=c^2$?2012-09-04

1 Answers 1

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$\lg(a^2+b^2)^2=2 \cdot \lg(a^2+b^2)=2 \biggr( \lg(a+ib)+\lg(a-ib) \biggr) $

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    one might use $ a^2+b^2=c^2\;$...2012-09-04