My book says Find the doubling constant for the exponential function: $1.05^x$
I'm not sure how to work this out, and I'm very sorry if this question is stupid, or too easy for this community.
My book says Find the doubling constant for the exponential function: $1.05^x$
I'm not sure how to work this out, and I'm very sorry if this question is stupid, or too easy for this community.
Assuming that "doubling constant" means "the value of $x$ for which $1.05^x = 2$" (I have not met the precise terminology before), then you need take logs of both sides:
$\log(1.05^x) = \log2$ then $x\log1.05 = \log2$ so that $x = \frac{\log 2}{\log 1.05} = 14.207$