Could I have some help for this question?
$\int \frac {x^4}{x^4 +5x^2 +4} \, dx$
I've reduced the equation to...
$\int \frac {1}{1 + 5x^{-2} + 4x^{-4}} \, dx$
But I'm stuck after this step. Could I have some help for this question?
Could I have some help for this question?
$\int \frac {x^4}{x^4 +5x^2 +4} \, dx$
I've reduced the equation to...
$\int \frac {1}{1 + 5x^{-2} + 4x^{-4}} \, dx$
But I'm stuck after this step. Could I have some help for this question?
Hint:
Using partial fraction, you can write the integrand as
$\frac {x^4}{x^4 +5x^2 +4}= 1+\frac{1}{3(x^2+1)} - \frac{16}{3(x^2+4)}.$
Using the fact that $x^4+5x^2+4=(x^2+1)(x^2+4)$, change the initial integrand to a form only involving $\frac{1}{x^2+a}$.