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I can certainly show that the eigenvalues of some scalar multiplied by the identity are all equal and that said matrix is normal but how would I go about beginning a proof that a normal matrix with all equal eigenvalues implies it can only be $A = cI$ where c is some constant?

Feeling like I missed something rather obvious here...

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    Know any theorems that hold Specially for normal matrices?2012-12-06

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A normal matrix is diagonalizable and hence $A = X \Lambda X^{-1}$ Since the eigenvalues are all equal to $c$, we get that $\Lambda = c I$. Hence, $A = X \Lambda X^{-1} = X \left(c I \right) X^{-1} = c XX^{-1} = cI$

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    @coward Care to comment on the down-vote?2012-12-06