Can anyone help me solve this equation? $5.4b-14=8b+38$
I got $b=15$ remainder $5$
but I am not sure if this is correct.
Can anyone help me solve this equation? $5.4b-14=8b+38$
I got $b=15$ remainder $5$
but I am not sure if this is correct.
That isn't correct. I'm not sure why you expressed your answer as "$15$ remainder $5$"..
Here's one way to solve it. I suspect you made a sign error somewhere.
You start with $ {5.4 b} -14 = {8b}+38$ Now subtract $5.4b$ from both sides $ {5.4 b} -14 -5.4b= {8b}+38-5.4b. $ Simplify $ -14 = {2.6b}+38. $ Now subtract $38$ from both sides to obtain $ -52=2.6b, $ or $ 2.6b=-52. $ Finally, divide both sides by $2.6$ and simplify $\eqalign{ b&={-52\over2.6}\cr &={-52\cdot 10\over 26}\cr &=-20. } $
Note you can check your answer: $ 5.4\cdot(-20)-14=-108-14=-122, \ \ \text{and} \ \ 8(-20)+38=-160+38=-122. $
$5.4 b-14 = 8 b+38$ ${}{}{}{}$ | +14 | -8b
$-2.6 b = 52$ | /(-2.6)
$b = -20$
(In case $b$ is just a normal variable. If $b$ means something else here, disregard this answer.)