the circle group is the multiplicative group of all complex numbers of absolute value 1. How can i show that this group is isomorphic with $\mathbb R/ \mathbb Z$. Any hints for the right map is great.
How to show that the circle group T is isomorphic to $\mathbb R/ \mathbb Z$
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$\begingroup$
group-theory
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0See also http://math.stackexchange.com/questions/274841/show-that-mathbbr-mathbbz-is-isomorphic-to-ei-theta-0-le-theta – 2016-10-31
2 Answers
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Hint: The complex exponent map.
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The map $\phi\colon\Bbb R\to T$ given by $\phi(t)=e^{2\pi it}$ is a group morphism. Hence we can apply first isomorphism theorem.