If you have a continuous stochastic process, then how is the hitting time for a closed set different from the hitting time of an open set when we're trying to show it is a stopping time?
Hitting times of closed vs. open sets
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stochastic-processes
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0[See the related discussion here.](http://math.stackexchange.com/questions/111$27$3/hitting-open-sets) Please tell if it is what you wanted - or your question is more specific – 2012-02-22
1 Answers
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Some examples to consider:
with a standard Wiener process, the hitting time for non-negative values (closed) is zero, but for positive values (open) need not be.
for a stochastic process restricted to a corridor, there may be a hitting time for hitting the boundaries of the corridor (closed), but not for passing beyond them (open).