Permutations and combinations completely melt my brain so I hope someone could verify I'm correct here:
I want to distribute ten $1 coins to six employees so that no employee gets more than 2 dollars. It's also possible some employees get nothing.
As far as I can tell there are 2 possible distribution methods:
2 2 2 2 2 0
and
2 2 2 2 1 1
So that should be C(6,1) + C(6,2) = 21
Is that correct, or am I missing something?