Given:
${AA}\times{BC}=BDDB$
Find $BDDB$:
- $1221$
- $3663$
- $4884$
- $2112$
The way I solved it:
First step - expansion & dividing by constant ($11$): $AA\times{BC}$=$11A\times{BC}$
- $1221$ => $1221\div11$ => $111$
- $3663$ => $3663\div11$ => $333$
- $4884$ => $4884\div11$ => $444$
- $2112$ => $2112\div11$ => $192$
Second step - each result is now equal to $A\times{BC}$. We're choosing multipliers $A$ and $BC$ manually and in accordance with initial condition. It takes a lot of time to pick up a number and check whether it can be a multiplier.
That way I get two pairs:
$22*96$=$2112$
$99*37$=$3663$
Of course $99*37$=$3663$ is the right one.
Is there more efficient way to do this? Am I missing something?