I wish I could provide an image but I'll explain the best way I can.
There is a triangle that is not a $90^\circ$ triangle. It has two sides measured at 8 and 6 (units not specified). The other side is $x$. There are no angles whose measures are given. How do I find $x$? We are doing a topic on law of sines.
Law of cosines
$\displaystyle \large a^2 = b^2 + c^2 - 2bc \space \cos A$
$\displaystyle \large x^2 = 6^2 + 8^2 - 2(6)(8) \space \cos A$
x = Sqrt[4 Cos[A] ]
x = 2 Sqrt[ Cos[A] ]
$\displaystyle \large x^2 = -96\space \cos A + 100$
$\displaystyle \large x = \sqrt{100-96\space \cos A}$