Please, help me to solve this equation. No advanced math should be needed.
$ 3x^2 - 4x + \sqrt{3x^2 - 4x - 6} = 18 $
I'm clueless. It should be simple.
Please, help me to solve this equation. No advanced math should be needed.
$ 3x^2 - 4x + \sqrt{3x^2 - 4x - 6} = 18 $
I'm clueless. It should be simple.
Put $u = 3x^2 - 4x$. Then the equation becomes $ u + \sqrt{u - 6} = 18.$ Once you solve for $u$ in the auxillary equation, you are left with a quadratic.
No advanced math is needed.
Hint : set $u:= \sqrt{3 x^2-4x-6}$ then your equation becomes $u^2+6+u=18$ or $u^2+u-12=0$