In how many ways can 4 girls and 2 boys sit at a movie theater row with 6 seats if a girl must be seated at each end.
How to solve this permutation math problem?
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permutations
2 Answers
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Step 1: Pick a girl and seat her at the left end, 4 ways.
Step 2: Pick a girl from the remaining 3 and set her at the right end, 3 ways.
Step 3: Four people remain; assign them to the remaining 4 seats: 4! ways.
Now multiply and get 12*24 = 288 possible seatings.
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0thanks $f$or the help also what does 5!.3! mean in permutations. – 2012-07-08
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If a girl must be at either end, then the only seat options for the boys are the middle 4 seats. The number of ways of assigning two of the middle 4 seats to the 2 boys is ${}_4P_2=4\times 3=12.$
Now we have to choose where the girls sit. The number of ways of assigning the remaining 4 seats to the 4 girls is ${}_4P_4=4\times 3\times 2\times 1= 24.$
Finally, multiply these results to get $12\times 24=288$ different seating arrangements where girls are on either end.