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I have an answer to a problem that I am working on but I have no idea how to rationalize the denominator because I have never worked with this type of problem before. The problem is:
$\frac{\sqrt{2-\sqrt{2}}}{\sqrt{2+\sqrt{2}}}$.

I know that I am supposed to multiply the entire fraction by the denominator but I do not know how it distributes over. How would I go about simplifying these types of problems?

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Note that you could just rewrite this as: $\sqrt{\frac{2 - \sqrt{2}}{2 + \sqrt{2}}}$

Now use your regular techniques for rationalizing what's under the radical sign, get an answer, and put it back under the radical sign!

I should note, though, that the final expression you end up with in this way can still be simplified further, but that requires a bit of trickery.

In particular, you end up with $\sqrt{3 - 2 \sqrt{2}}$. Can this be simplified further? In other words, is there anything you can square to get $3 - 2\sqrt{2}$?

If so, you might imagine it'd be something like $(a + b\sqrt{2})^2$.

But this expression is equal to $a^2 + 2b^2 + 2ab\sqrt{2}$.

We now want: $a^2 + 2b^2 = 3$ and $2ab = -2$.

With two variables and two equations, we can solve for $a$ and $b$, and we find:

$a = 1, b = -1$; or $a = -1, b = 1$.

Thus, the two square roots are: $1 - \sqrt{2}$ and $-1 + \sqrt{2}$.

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    the denominator becomes $(2 + \sqrt{2})(2 - \sqrt{2})$. Yeah, use FOIL and see what you get!2012-11-05