I'm stuck here with some numerical rebus -
Given: $A^2=BC, A^3=CA$
Find: $A+B+C$
- $13$
- $12$
- $11$
- $10$
(only one correct solution)
Note that letters represent digits.
I can't think of any idea to solve this one, and according to the book from which this question was taken, it is possible to solve in one minute. I will appreciate any idea.