I feel like I am missing a key piece of intuition in trying to understand this. I have just recently started using Stoke's theorem and I struggle to see what the boundary curve of surfaces are. In some cases it is easy... like a hemisphere for example. But what about the boundary curve of the surface given below
Could someone explain what this boundary curve of the surface below and just some basics of how to find it. I have read and re-read my book but all of the examples in there are things like a hemisphere.
Wait so i'm not so sure it is a torus anymore, it's been a long day, the surface is given by: $x=[1+u\cos (t)]\cos (2t), \quad y=[1+u\cos (t)]\sin (2t), \quad z=u\sin (t)$ $- \frac{1}{2} \le u \le \frac{1}{2} \quad , 0 \le t \le \pi$
Thanks :-)