1
$\begingroup$

I have the following problem: $100*\left\{24+100*[1001-4*(25*6+25*4)]\right\}$

I'm very frustrated that I can't solve exercises like this. I have read about PEMDAS and followed the steps but somehow I am making a mistake because the result I get is not correct.(looked at answers in the book).

Can someone provide the steps in order to solve correctly this problem?

  • 0
    @GEdgar: I would not say that I "did it for him"; I explained what steps he needs to take, but did not take them.2012-06-23

2 Answers 2

1

First, do the innermost products, $25*6$ and $25*4$. Then add them. Then multiply the result by $4$. Then subtract this from $1001$. Then multiply the answer by $100$. Then add $24$. Then multiply the result of that by $100$.

Or:

  1. You will need to multiply $100$ by the result of what is in curly brackets;

    • What is in curly brackets requires you to add $24$ to the result of multiplying $100$ by the answer you get from inside the square brackets;

      -What is inside the square brackets requires you to start with $1001$, and subtract the result of multiplying $4$ by the result of what you have inside the round parentheses.

      • To compute what is inside the round parentheses, you first do the products ($25$ times $6$ and $25$ times $4$), and add them.

Now "unfold" that to get the answer.

  • 0
    I totally got it now! Thank you so much!2012-06-23
2

$\newcommand{\myemph}[1]{{\color{red}{\bf #1}}}$ $100*\left\{24+100*[1001-4*(\myemph{25*6}+\myemph{25*4})]\right\}$ $100*\left\{24+100*[1001-4*(\myemph{150+100})]\right\}$ $100*\left\{24+100*[1001-\myemph{4*(250)}]\right\}$ $100*\left\{24+100*[\myemph{1001-1000}]\right\}$ $100*\left\{24+\myemph{100*[1]}\right\}$ $100*\left\{\myemph{24+100}\right\}$ $\myemph{100*\left\{124\right\}}$ $\fbox{12400}$