$ x = 1/2, v[2,−2], t = 3, P(1, 2)$ x = speed, v = orientation, t = time, p is a point.
I tried this : $((2, -2) - (1,2)) \sqrt{1^2 + 4^2} $
I got my <1,4> from $(2-1, 2-(-2))$ , which is my directional vector. Right ?
which is equal to $ (1, -4) \sqrt{17} $
my final answer is : $(1,2) + 1/2((1,-4)\sqrt {17})$ Is it ok ?
Then I'm asked : what would be the equation if it was 'unit speed' instead of m/sec
Not sure what to do.
Thanks