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$x(t)= A+ A_1\sin (2 \pi f t + \theta ) + A_2\cos (2 \pi f_1 t + \theta )$ I want to find the Fourier transform $|\mathcal{F}[x(t)]|^2$ . Is this possible by hand? I can find the Fourier transform but then raise to power seems difficult.Is there any shortcut for this ?

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    @Pragabhava yes but the real part :)2012-10-03

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Try using convolution rule (specific for this case): $\mathcal{F}[x(t)]\cdot\mathcal{F}[x(t)]=\frac{1}{2\pi}\mathcal{F}[x(t)\ast x(t)]$.