I'll help you get started.
Start with a Cauchy sequence $(f_n)$ in $l^{\infty}(X,N)$. Then for any $\epsilon>0$ we have $N>0$ such that for any $n,m\geq N$ we have $\sup_{x\in X}n(f_n(x),f_m(x))<\epsilon$. Consequentially, the sequence $(f_n(x))$ is Cauchy in $N$ for any $x\in X$ (Why?) and converges, say to $y$. We have to find an $f\in l^{\infty}(X,N)$ such that $f(x)=y$. Well, we have a natural candidate, namely the function whose value at $x$ is the limit of the sequence $(f_n(x))$ in $N$. Now just check that $f$ is bounded and that the sequence $(f_n)$ converges to $f$ and you are done.