Let A be 4 X 4 matrix with eigenvalues -5, -2, 1, 4. Which of the following option is an eigenvalue of $\begin{bmatrix}A & I\\I & A\end{bmatrix}$, where I is 4 X 4 identity matrix?
options: (A) -5 (B) -7 (C) 2 (D) 1
Let A be 4 X 4 matrix with eigenvalues -5, -2, 1, 4. Which of the following option is an eigenvalue of $\begin{bmatrix}A & I\\I & A\end{bmatrix}$, where I is 4 X 4 identity matrix?
options: (A) -5 (B) -7 (C) 2 (D) 1
Hint: Suppose that $x=[x_1,x_2,x_3,x_4]^T$ is an eigenvector of $A$ corresponding to an eigenvalue $\lambda$, and let $y=[x_1,x_2,x_3,x_4,x_1,x_2,x_3,x_4]^T$. What can you say, then, about $\left[\begin{array}{cc}A&I\\I&A\end{array}\right]y?$
Edit: It may be that your difficulty lies in the fact that you're thinking of it as a matrix of matrices in the first place. That isn't really what is going on, but if that's how you're thinking of it, then instead consider $y$ as a "vector of vectors". So, $x$ is an eigenvector of $A$ corresponding to one of its eigenvalues, $\lambda$, then $y=\left[\begin{array}{c}x\\x\end{array}\right]$. Now simply doing matrix multiplication, we have $\left[\begin{array}{cc}A&I\\I&A\end{array}\right]y=\left[\begin{array}{cc}A&I\\I&A\end{array}\right]\left[\begin{array}{c}x\\x\end{array}\right]=\left[\begin{array}{c}Ax+Ix\\Ix+Ax\end{array}\right]=\left[\begin{array}{c}\lambda x+x\\x+\lambda x\end{array}\right]=(\lambda+1)\left[\begin{array}{c}x\\x\end{array}\right]=(\lambda+1)y.$ Thus, whenever $\lambda$ is an eigenvalue of $A$, we automatically have $\lambda+1$ as an eigenvalue of $\left[\begin{array}{cc}A&I\\I&A\end{array}\right]$. Thus, only one of the options given is necessarily an eigenvalue of the matrix of matrices.