A Woodall number is an integer of the form $n 2^{n}-1$.
A Woodall prime is an integer that is both a prime and a Woodall number.
Let $p$ be a prime of the form 1 mod 4.
Then $p 2^{p} -1$ is never a ( Woodall ) prime.
How to prove this ?
A Woodall number is an integer of the form $n 2^{n}-1$.
A Woodall prime is an integer that is both a prime and a Woodall number.
Let $p$ be a prime of the form 1 mod 4.
Then $p 2^{p} -1$ is never a ( Woodall ) prime.
How to prove this ?