Solve for $d$
$2x-2yd=y+xd$ $2(x-yd)=y+xd$ $2(x-yd)-y=xd$ $\frac{2(x-yd)-y}{x}=d$ Now I think this is wrong considering I have a $d$ on the other side and I would have to reverse my work and end up at the beginning. Any small pointers or tips? Thanks!