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How do I compute a tan limit with a fraction?

$\lim_{h\rightarrow 0}\frac{\tan(-\frac{\pi}{4})+1}{h}$

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    Was this really the question, or was it $\lim_{h\rightarrow 0}\frac{\tan(-\frac{\pi}{4}+h)+1}{h}$?2012-06-25

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Since $ \tan(- \pi /4 ) + 1 = 0$, we have

$ \lim_{h \rightarrow 0} \frac{\tan \left ( \frac{- \pi}{4} \right ) + 1}{h} = \lim_{h \rightarrow 0} \frac{0}{h} = \lim_{x \rightarrow 0} 0 = 0 $