I need to solve the following equation for $v(x)$: $\int_0^tv(x)(x+1)dx=f(t)$ I am given the function $f(t)$. I've done this so far:
If we derive both sides by $t$, we get $v(t)(t+1)=f'(t)$ and $\bar{v}(t)=\frac{f'(t)}{t+1}$. The problem is that I am still off by a constant, i.e., the above only guarantees that : $\int_0^t\bar{v}(x)(x+1)dx+c=f(t)$ which is not enough for me.