In this whole post beginning with the second paragraph, by "tensor product" I will mean the operation done on Von Neumann algebras where one applies the homomorphism from here Tensor products of maps to the algebraic tensor product of the Von Neumann algebras, and then takes the WO closure in the space $B(H \otimes H)$ where that "$\otimes$" is the tensor product of Hilbert spaces in the Hilbert sense.
As part of the proof of some equalities relating the commutant of a tensor product to the tensor product of commutants, I am asked to prove "directly" that if $C(H)$ denotes the scalar operators on $H$, then $(B(H) \otimes C(H))'=C(H) \otimes B(H)$ I am having trouble proving that the left side is included in the right side. Help please!