Given $a,b,c > 0$ and $a > b + c$ , is it true that $a^2 > b^2 + c^2$?
Im tried proving it. I followed the below steps and not sure whether im right or wrong?
Squaring on both sides
$\implies a^2 > (b+c)^2$
$\implies a^2 > b^2 + c^2 + 2*b*c$
since $b,c > 0 $, we have $2*b*c > 0$, then
$\implies a^2 > b^2 + c^2$ Q.E.D