How do I solve the infinite product of $\prod_{n=2}^\infty\frac{n^3-1}{n^3+1}?$
I know that I have to factorise to $\frac{(n-1)(n^2+n+1)}{(n+1)(n^2-n+1)},$
but how do I do the partial product?
Thanks a lot in advance.
If I'm not mistaken the Answer is 2/3