$E_1 = Ch_1^\alpha$
How can I solve for the exponent alpha?
Is it just $\frac{\frac{E_1}{C}}{ln(\alpha)}$?
$E_1 = Ch_1^\alpha$
How can I solve for the exponent alpha?
Is it just $\frac{\frac{E_1}{C}}{ln(\alpha)}$?
You get
$h_1^\alpha = \frac{E_1}{C}$
Tking the log, you get
$\alpha \ln(h_1) = \ln \frac{E_1}{C}$
You can easily get $\alpha$ from here. Your answer is almost right, unfortunately, almost right also means wrong ;)