If I have two complicated logarithmic functions, say $\sqrt{\log n}$ and $\log(n(\log n)^3)$, and I have to compare them in terms of their asymptotic order. How do I do that? Do I have to create graphs, or is there another definitive way of doing that?
Comparing asymptotic order of logarithmic functions
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asymptotics
1 Answers
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Using elementary properties of the logarithm we find out that $\log(n \log^3 n) = \log n + 3\log\log n = O(\log n), $ whereas $\sqrt{\log n} = o(\log n)$. So $\sqrt{\log n}$ grows more slowly.
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0From $\log n = o(n)$ it follows that $\log\log m = o(\log m)$ (substitute $n = \log m$). That $\log n = o(n)$ can be shown using l'Hopital's rule. – 2012-09-21