Solve for $x$: $ 2^{2x+1} - (17)2^x + 8 = 0 $
I have the answers: -1, 3
I tried a few different transformations, but couldn't get a clear answer. I suspect that I am overlooking a property of log that would be useful.
Edit: using a u substitution for $2^x$, I was able to factor the quadratic into:
$(2u-1)(u-8)$
$2^x = 1/2$
$2^x = 8$
$x = -1, 3$