I am working through a suggested exercise
"If $n$ is an integer, $\frac{n}{n+1}$ is not an integer" - I can prove this is false, and I can prove the converse is false, and I can prove the contrapositive is false.
Now the question asks to show the negation and prove it true or false. Since the original is false by counter example $n=0$, I'm assuming the negation should prove true.
The negation of $p \implies q$ is $p \wedge ¬q$, so the negation in this case should be
"$n$ is an integer and $\frac{n}{n+1}$ is an integer" right?
This can be true ($n=0$) or false ($n=1$). So is the statement true or not? I assume not, so then the original is false AND the negation is false? getting very confused