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So, a 45 degree angle in the unit circle has a tan value of 1. Does that mean the slope of a tangent line from that point is also 1? Or is something different entirely?

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Have a look at this drawing from Wikipedia: Unit Circle Definitions of Trigonometric Functions.

When viewed this way, the tangent function actually represents the slope of a line perpendicular to the tangent line of that point (i.e. the slope of the radius that touches the angle point).

However, you can actually see that the "tangent line", consisting the values of the tangents, is the actual tangent line of the circle at the point from which the angles are measured, and I would guess that this is the source of the name.

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    Interesting! Never thought of that... like "tangible".[Here](http://www.algebralab.org/lessons/lesson.aspx?file=Trigonometry_TrigNameOrigins.xml) is an (unsourced) description of origins of the names of the trigonometric functions.2012-12-27
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Yes and no, resp.: yes, any line in the plane that forms an angle of $\,45^\circ\,$ with the positive direction of the $\,x-$axis has a slope of $\,\tan 45^\circ=1\,$, and no: it isn't something different.

It is not completely clear though what you mean by "tangent line"...perhaps you meant "tangent line at some point on the graph of a (derivable) function"?

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    Forget the comments: take a peek at the diagram drawn in the link the OP sent.2012-12-27