I would like to know if its possible to pull $a$ out of the following equation without multiplying $b$ by $(x-y)$
$ \frac{ 2a(x^2 - y^2)}{x - y} = b $
Its part of a more complex problem I'm stuck on.
Cheers
I would like to know if its possible to pull $a$ out of the following equation without multiplying $b$ by $(x-y)$
$ \frac{ 2a(x^2 - y^2)}{x - y} = b $
Its part of a more complex problem I'm stuck on.
Cheers
Yes indeed, you have the identity $ x^2 - y^2 = (x-y)(x+y) $ So, $\dfrac{2a (x^2-y^2)}{x-y}=b \Leftrightarrow 2a(x+y)=b $