There is a question:
What is the number of canonical expressions that can be developed over a 3-valued boolean algebra?
I was trying to solve this. Canonical expression is the combination of minterms. In a 3 valued boolean algebra, the number of minterms is 2 to the power of 3 i.e 8.. so there are 8 minterms. But how do i proceed further? is it using permutation ?