This is what I have, but I am not sure if I am on right track, or if more work needs to be done:
Rearranging the given D.E. I have:
$ v = \frac{1}{x^2} = \frac{x}{2x-x'}$
so:
$ v' = -\frac{2}{x^3} = -\frac{2}{2x-x'}$
Substituting for x', I have:
$v' = \frac{2}{x^3} = \frac{2v}{x}$
Is this sufficient? Or do I need to elminate x from the equation completely? Is there more work to be done?
Thanks in advance!!!