To find a asymptote its either b2/a2 or a2/b2 depending on the way the equation is written.
With the problem
$\frac{(x+1)^2}{16} - \frac{(y-2)^2}{9} = 1$
The solutions the sheet I have is giving me is $3/4x - 3/4$ and $3/4 x + 5/4$
I thought it was just supposed to be $\pm 3/4x$.