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Let $\mathbb{P}$ is a set primes numbers, $\pi \subseteq P$ and $\pi ^{\prime }=P-\pi $

Let $G$ abelian and $O_{\pi }\left( G\right) =\left\langle N~;~N\trianglelefteq G\text{ and }% N\text{ is }\pi \text{-subgroup}\right\rangle $

Is it true that $O_{\pi^{\prime } }\left( G\right) =1\Longrightarrow G$ is $\pi -$group?

I think so, because every subgroup is normal in $G$.

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    You can relax your condition of$G$being abelian to G being *$\pi$-separable* (that is G has a normal series with each factor either a $\pi$- or $\pi$'-group.2012-08-15

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