How do I find the Maclaurin Series for $x^3 \sin{2x}$? If I start differenciating, I get 2 terms like $2x^3 \cos{2x} + \sin{2x}\cdot 3x^2$ then 4 for the next one. Is this the right way to go?
I just need to find $f^{(2012)}(0)$ of $f(x)= x^3\cdot \sin{2x}$