$f(x) = 2-4\cos(2x-\frac{1}{3}\pi)$
How do you get this function from as standard function?
My answer:
$ y = \cos x $
↓ Multiply with the x-axis, -4
$y=-4\cos x$
↓ Multiply with the y-axis, 0.5
$y=-4\cos 2x $
↓ Translation $(\frac{1}{6}\pi, 2)$
$f(x) = 2-4\cos(2x-\frac{1}{3}\pi)$
Is this answer correct? The only part I am really concerned about is the final translation, with the $(\frac{1}{6}\pi)$ instead of $(\frac{1}{3}\pi)$.