I have the following equation: $\sin^{-1}\left(\frac{x-1}{2}\right)$
Is it ok to solve like this:
$y=\sin^{-1}(z)$, $z=\frac{x-1}{2}$
$\frac{dy}{dz} = \frac{1}{\sqrt{1-z^2}}$ and $\frac{dz}{dx}=\frac{2-(x-1)}{4}$
$\frac{dy}{dx}=\frac{dy}{dz}\frac{dz}{dx}$.
Here I do not know what to do more. Please tell me if I am doing the things above correct, and how to finalize the answer. Thanks.