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I would like to know if its possible to pull $a$ out of the following equation without multiplying $b$ by $(x-y)$

$ \frac{ 2a(x^2 - y^2)}{x - y} = b $

Its part of a more complex problem I'm stuck on.

Cheers

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    If by "pull $a$ out" you mean, "solve $2a(x^2+y^2)/(x+y)=b$ for $a$" then the answer is no.2012-07-09

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Yes indeed, you have the identity $ x^2 - y^2 = (x-y)(x+y) $ So, $\dfrac{2a (x^2-y^2)}{x-y}=b \Leftrightarrow 2a(x+y)=b $