There's 1 box with 10 balls:
3 white 2 black 5 blue
2 balls are removed the box randomly, and the first one is not replaced.
What is the probability of getting at least 1 white ball?
Here's what I cooked up:
The probability of getting at least 1 white ball equals the sum of the probabilities of getting a white ball first and getting a white ball second. The probability of getting a white ball on the first one is 3/10. The probability of getting a white ball on the second one is 2/9.
So the probability would be:
3/10 + 2/9 = 47/90
I'm solving this on a book which says the answer is 8/15.
So, my answer is 0.52222..., and their answer is 0.5333...
Am I doing anything wrong?
Thanks in advance.