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I'm trying to solve a second order differential equation and I got a recurrence. Can someone help to solve $n(n-1+q)a_{n}-a_{n-3}+e\cdot a_{n-2}=0$ where $q$, $e$, and $a_{0}$ are some real numbers with $a_{1}=0$ and $a_{2}=-e\cdot a_{0}/(2(1+q))$.

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    Usually, what you get out of such an exercise is the differential equation you started with...2013-05-08

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