The expression: $\ln(a+b) + \ln(a−b) − 9 \ln c$
My answer: $\ln[(a+b)(a-b)] / c^9$
...I'm guessing I should have multiplied $(a+b)(a-b)$ out? Or am I completely off? Help?
The expression: $\ln(a+b) + \ln(a−b) − 9 \ln c$
My answer: $\ln[(a+b)(a-b)] / c^9$
...I'm guessing I should have multiplied $(a+b)(a-b)$ out? Or am I completely off? Help?
You are close. The numerator is fine, but the denominator should be within the square brackets.