the function f defined by $f(x)=(x^3+1)/3$ has three fixed points say α,β,γ where $-2<α<-1$, $0<β<1$, $1<γ<2$. For arbitrarily chosen $x_{1}$, define ${x_{n}}$ by setting $x_{n+1}=f(x_{n})$ If $α
I think I must prove three things, but not sure:
1: if $α
2: if $α
3: if $β
could you please help me?