4
$\begingroup$

$p:E \rightarrow B$ is a fibration and $F$ is its fibre and $F_p$ its homotopy fibre. If $i:F \rightarrow F_p$ is the inclusion, is there a homotopy inverse $r$ of $i$ such that $r \circ i = id$?

  • 0
    I think in some cases it does. For example when $(F_p,F)$ satisfies homotopy extension property, $F$ is the deformation retract of $F_p$.2012-08-31

0 Answers 0