I wanted to know if I was thinking about this problem right and set it up correctly. It's been a while since I had to do math like this. The radius of the hydrogen atom is $0.529\times10^{−10}m$ and the radius of the nucleus is $1.2\times10^{−15}m$.
I have a ball bearing with a radius of $1.5mm (1.5\times10^{-3}m)$.
Using the ball bearing as the nucleus what would be the radius of the model?
My work/answer all values are in m(meters):
$1.5\times10^{-3} = x(1.2\times10^{-15})\\ x = \frac{1.5\times10^{-3}}{1.2\times10^{-15}} = 1.25\times10^{12}\\ r = x(0.529\times10^{-10}) = (1.25\times10^{12}) \times (0.529\times10^{-10}) = 66.125m$