I have a stupid question: assume $X \subset P:=\mathbb{P}^{N_1}\times \mathbb{P}^{N_2} $ closed, irreducible, Cohen-Macaulay, not a product of two varieties and non degenerate, meaning that it is not contained in any hyperplane $H\times K$ where $H$ is an hyperplane in the first factor and $K$ an hyperplane in the second. Is there a lower bound depending on $N_1$ and $N_2$ for the degree of $X$ in terms of the dimension of $P$?
relations between degree and dimension
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algebraic-geometry
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0If $H$ and $K$ are hyperplanes, then $H \times K$ is not a hyperplane in the Segre embedding of $P^{N_1} \times P^{N_2}$, nor is it necessarily contained in one. – 2012-05-07
1 Answers
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No - there are plane curves of arbitrarily high degree. (Take $N_1 = 2, N_2 = 0$.)
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0You need an assumption on $\dim X$ and not just $\dim P$. There are non-degenerate conic hypersurfaces of every dimension. – 2012-05-07