Throwing two dice what are my chances of getting ten?
I would say that probability $\frac{1}{6}$ because I can get ten with
$6 + 4$
or
$5 + 5.$
Is my idea correct?
Throwing two dice what are my chances of getting ten?
I would say that probability $\frac{1}{6}$ because I can get ten with
$6 + 4$
or
$5 + 5.$
Is my idea correct?
No. Since any die can give a number between $1$ and $6$, you have $36$ possible outcomes (do you see why? I think this is another reason for your mistake).
Three couples $(a,b)$ of values sum up to $10$ (you forgot to mention $4+6$).
So your probability is $\dfrac1{12}$.