So I'm stuck on the following problem:
Write the equation of the plane tangent to
$z = f(x,y) = (x^2+y^3-8)^{1\over4}$ at $(5,4,3)$
I know how to find the equation of the plane but usually the $z$ is part of the function. I was wondering if all I had to do was subtract the $z$ and set the whole thing to zero or do I do this as is.
I tried that and this is the answer that I got: $ {5\over54}\left(x-5\right)+{4\over9}\left(y-4\right)-\left(z-3\right) = 0$ is that right?