Btw, please don't give me the answer. I just wanna know how to raise a logarithm to its cube cause I'm stuck in this part, but don't solve it for me.
$\log \sqrt[3]x = \sqrt[3]{\log x}$ I tried different ways but. When I input the values in my calculator, it just doesn't match.
My answer: is it right? $1/3\log x =\sqrt[3]{\log x}$ $\log x = 3\sqrt[3]{\log x}$ $a = 3\sqrt[3]{\log x}$ $a^3 = \log x^{27} $ $\log x^3 = \log x^{27}$ $\log x^{24} = 0$ $ x = \sqrt[24]{1}$ $ x = 1$