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Let $u,v$ unit vectors in $C^n$ so $||u+v||=\sqrt{2}$. Need to prove that $=bi$ for any b real number.

Please help me Im not sure if I even open $||u+v||=\sqrt{2}$ .

1 Answers 1

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Square both sides. You get

$||u+v||^2 = ||u||^2+||v||^2 + 2Re() = 2 $

Therefore $Re() = 0.$ Thus $$ must be imaginary, if not 0.