Let triangle $ABC, BC=a,AB=c,AC=b$. Know that the bisector of $ACB$ perpendicular with the line $OG$, with $O$ is inscribed circle center and $G$ is center of $ABC$. Prove that: $\frac{2ab}{a+b}=\frac{a+b+c}{3}$
In a triangle $ABC$ with $BC=a,AB=c,AC=b$; the bisector of $ACB$ perpendicular with the line $OG$
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geometry
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0G is the centroid(http://www.jimloy.com/geometry/centers.htm) – 2012-09-23
1 Answers
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I suppose the home work is finished and this answer is for reference.