I am not sure where I am going wrong, I will admit I do not fully understand all the equations but I do feel like I have a pretty good grasp on them.
This is from Stewart Calculus 7e pg 613 #3
"The pacific halibut fishery has been modeled by the differential $\frac{dy}{dt} = ky \left(1 - \frac{y}{M}\right)$where $y(t)$ is the biomass (the total mass of the members of the population) in kilograms at time t (measured in years), the carrying capacity is estimated to be $M = 8 * 10^7 kg$ and $k = .071$ per year.
a) if $y(0) = 2 \cdot 10^7 kg$ find the biomass a year later.
b) How long will it take for the biomass to reach $4 \cdot 10^7 kg$?"
First I start by putting in the given information into the logistic equation. $\frac{dy}{dt} = .071y\left(1 - \frac{y}{8*10^7}\right)$
Starting with $a$ I need to find $y$ when $t$ is $0$ so I use another equation from the book. I find that $A = 3$ $A = \frac{M - y_0}{y_0}$ Where I am assuming $y_0$ is the initial value. $y(0) = 2 \cdot 10^7$
$A = \frac{(8 \cdot 10^7) - (2 \cdot 10^7)}{ 2 \cdot 10^7}$
This comes out to 3 so I put it in the other equation that solves for $y(t)$
$y(t) = \frac{M}{1+ Ae^{-kt}}$
$y(1) = \frac{(8 \cdot 10^7) }{1+ 3e^{-.071}}$
This comes out to $21083781.89$ which I know is wrong, going through my work it all seems to be correct, I am not sure where I have gone wrong.