I am having some trouble with the following exercise:
I need to determine if the following serie converges or diverges using only the limit comparison test:
$\sum_{n=1}^{\infty} \frac{n}{(4n-3)(4n-1)}$
Please help.
Thank you in advance
I am having some trouble with the following exercise:
I need to determine if the following serie converges or diverges using only the limit comparison test:
$\sum_{n=1}^{\infty} \frac{n}{(4n-3)(4n-1)}$
Please help.
Thank you in advance
$\lim_{n\to\infty}\frac{\frac{n}{(4n-3)(4n-1)}}{\frac{1}{n}}=\lim_{n\to\infty}\frac{n^2}{16n^2-16n+3}=\frac{1}{16}\Longrightarrow$
since the harmonic series diverges so does our series.