$ \lim_{n\to \infty} \left(2+\frac{1}{n}\right)^{n} = ? $
I don't know even how to start this.
$ \lim_{n\to \infty} \left(2+\frac{1}{n}\right)^{n} = ? $
I don't know even how to start this.
$\left(2+\frac{1}{n}\right)^n=\left(1+\left[1+\frac{1}{n}\right]\right)^n=\sum_{k=0}^n\binom{n}{k}\left[1+\frac{1}{n}\right]^k\geq\frac{n(n-1)}{2}\left(1+\frac{1}{n}\right)^2\xrightarrow [n\to\infty]{}\infty$
Since $2+1/n > 2 $ for all $n$, we have $(2+1/n)^n > 2^n$ for each $n$, so the sequence tends to infinity.
Just look at it. It blows up.${}{}{}{}{}{}$
And fast! It's bigger than $2^n$.