I must solve following inequation:
$\frac{x-3}{1-2x}<0$
Now the text says that I have to solve the inequation "direct" without solving the according equations.
What does that mean?
I would say that I have to multiply by $(1-2x)$ then I get
$x-3<0$ and
$L_1 = [x \le 2]$
$L_2 = [x >0] $
but I have the feeling that I'm doing something wrong. Especially I don't understand what the paragraph about solving the inequation "direct" means. Could someone maybe explain that to me?