There's a triangle $XYZ$, where $X, Y, Z$ are the angles and $x, y, z$ are the sides opposite to the angles respectively.
Given that $2X = 3Y$ and $x = 2z$, then find the possible value of $∠Z$.
I used the sine law, $\frac{\sin X}{x} = \frac{\sin Y}{y} = \frac{\sin Z}{z}$ and I got the following relation: $\frac{\sin X}{\sin Z} = 2 = \frac{\sin(2X/3)}{y}$
But I'm unable to solve further and get the value of $Z$. Please help.