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I have to solve the following,

$\int \frac{8\sin(2x)}{\sin(x)}dx$

but I'm not sure where to begin. I thought of the anti derivative been something like -4cos(2x) but that doesn't take care of the sin in the denominator. Thanks ahead of time.

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    Do you know an identity involving $\sin2x$?2012-11-28

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Hint: You can use the following trigonometric identity: $\sin(2x) = 2\sin(x)\cos(x)$