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I'm trying to prove that for any simple graph $G=(|E|,|V|, f)$

$|E| \leq (|V| - k + 1)(|V| - k) /2$

Where |E| - number of edges, |V| - number of vertices, and k - number of components.

Attempt at solution:

$ν(G) = |E| - |V| + k(G) \geq 0$

$|E| \geq |V| - k$

$|E| + 1 \geq |V| - k + 1$

$(|E| + 1) (|V| -k) \geq (|V| - k + 1) (|V| -k)$

$(|E| + 1) (|V| -k) /2 \geq(|V| - k + 1) (|V| -k) /2$

I know, that $(|V| -k) /2$ is always a positive number and if we remove it, we will lessen the left side. If we remove $+1$, we will lessen it even more. However, there is no guarantee, that we will lessen it enough to turn the sign the other way.

I really hope someone could help me.

  • 0
    Would you like to type up your full solution and answer your own question?2012-03-14

0 Answers 0