Why is the following not possible?
$\frac{2x-1}{2x}\neq4x-2$
And the following method not correct?
$\bigg(\frac{2x-1}{2x} + \frac{1}{1}\bigg)-1\equiv\frac{2x-1}{2x}$
Cross multiplying:
$\big(1[2x-1]+1[2x]\big)-1$
With the result:
$2x-1+2x-1=4x-2$
My question, essentially is, is the following possible:
$\frac{a}{b}+\frac{c}{d}\equiv ad+bc?$
I know it is true for the following:
$\frac{a}{b}=\frac{c}{d}\equiv ad=bc$