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I know theres a summation series for basic $a^x$. Like $2^{x-1}$ is summed by $2^x-1$. Then how would you sum $5\times2^{x-1}$?

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    Hint: Distributive law2012-10-05

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You would distribute out the $5$ and get $\sum_{i=1}^x 5\cdot 2^{i-1}=5\sum_{1=1}^x 2^{i-1}=5( 2^x-1)$

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    @GerryMyerson: I thought of that after I went to bed. My only excuse is that I followed OP's notation. Fixed and thanks.2012-10-05