You roll a dice $6$ times. What is the probability of rolling at least one $5$ AND at least one $6$?
The answer in the book is $1 - (5/6)^6 - (5/6)^6 + (4/6)^6$. Would someone please explain why that is?
$(1 - (5/6)^6 - (5/6)^6)$ : This is the probability of rolling a $5$ OR $6$ for six rolls of the dice. Correct?
What is $(+ (4/6)^6)$? Isn't that the probability of not rolling a $5$ or $6$? Why do I need to add it.