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$\begingroup$

Possible Duplicate:
Partial latin square with $\le n-1$ filled cells

http://ajc.maths.uq.edu.au/pdf/22/ocr-ajc-v22-p247.pdf

Could someone please further explain the inductive step here in Theorem 5 in more explicit terms, or write the proof in explicit terms? I'm afraid I don't see how the inductive step makes sense for the completion of a Latin square.

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    And I’ve posted an answer there.2012-07-14

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