Let $x$ be a positive scalar variable. Its time derivative satisfies $|\dot{x}(t)|\le \exp\left\{-\int_{0}^t\frac{1}{x(\tau)}\mathrm{d} \tau\right\}$ where $|\cdot|$ denotes the absolute value. From the above inequality, can we say $x(t)$ with $t\in[0,+\infty)$ has a finite upper bound? No need to compute an exact upper bound. It is sufficient to show there exists a finite upper bound. I know if $|\dot{x}(t)|\le \exp\left\{-kt\right\}$, then $x(t)=\int_{0}^t \dot{x} \mathrm{d}\tau$ will have an upper bound $1/k$.
Does this variable have an upper bound?
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real-analysis
integration
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0@DavideGiraudo: Thanks for the comment. I have posted an answer below to refer to the answer given in mathoverflow. – 2012-09-09
1 Answers
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This problem is solved in Mathoverflow.