If we have an increasing sequence of sets, $A_n \subset A_{n+1}$, prove that the limit of this sequence not only exists but is the union of the sets. i.e. $ A_n \uparrow\cup_{n=1}^{\infty}A_n$.
Prove the limit of monotone increasing set is the union of sets?
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elementary-set-theory
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2The first thing to do is to make sure you know the definition of a limit of a sequence of sets. – 2012-09-30
1 Answers
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How is the limit (for sequence of sets) is defined?
Following the definition I studied, $\exists\lim A_i \iff \limsup A_i = \liminf A_i$, where $\limsup_n A_n := \bigcap_{n=0}^\infty \bigcup_{k=n}^\infty A_k$ $\liminf_n A_n := \bigcup_{n=0}^\infty \bigcap_{k=n}^\infty A_k$
Now, if $A_n$ is monotonic ($A_n\subseteq A_{n+1}$), try to evaluate these, and you will get their union in both cases.