I guess this is a really dumb question, but i've been trying quite a lot and I can't figure out how to determine the solutinons.
I need to determine the values of two angles and they don't seem to be ok. But I do know for sure that the values are right. The equation is as it follows:
$\begin{align*} &\sin(\alpha)=1/3\;;\\ &\cos(\alpha)\cos(\beta)=0\;;\text{ and}\\ &\cos(\alpha)\sin(\beta)=0.94280899908173\;. \end{align*}$
Because if $\sin(\alpha)$ is not $1$, neither will $\cos(\alpha)$ be $0$. Also means that $\cos(\beta)$ is $0$, resulting that $\sin(\beta)$ is $1$. Determined by calculus that $\cos(\alpha)$ is not $0.94280899908173$, I seem to be in a real trouble..