I have
$\cos \frac{1234 \pi}{5} + i \cdot \sin \frac{1234 \pi}{5}$
I believe I can simplify the $1234$ further, but how?
I have
$\cos \frac{1234 \pi}{5} + i \cdot \sin \frac{1234 \pi}{5}$
I believe I can simplify the $1234$ further, but how?
$\frac{1234\pi}5 = 246\pi + \frac{4\pi}5$
To complement mrf, we can say that $cos(\frac{1234 \pi}{5})=cos(\frac{4 \pi}{5}$). Because there are the periodic identities which stays that:
$\sin( \theta+ 2 \pi n)= \sin \theta $
$\cos( \theta+ 2 \pi n)= \cos \theta \qquad n \in \mathbb{Z}$
This happens because the period of sine and cosine funtions is $2 \pi$.