First let $(G, \circ)$ be a group and let $S = G$. Then let $g,h \in G$ and $s \in S$.
I'm confused by the meaning of the statement "$G$ acts on itself by right multiplication". (Specifically, I'm being asked to show "G acts on itself by right multiplication" without any context). It seems to me this could mean two things:
(1) The function $G \times S \rightarrow S$ s.t. $gs = s \circ g^{-1}$ forms a left group action on G.
(2) The function $S \times G \rightarrow S$ s.t. $sg = s \circ g$ forms a right group action on G.
Is there a standard meaning to this question or should I ask my instructor?