I want to let fall a perpendicular from a point A in space being given by $A_x, A_y$ and $A_z$ on a plane being given by two vectors $B$ and $C$.
Ultimately I want to determine the foot x0 of the perpendicular. Note: This is not the question, this is the introduction. Here the questions follow.
I found
$x_0 = p \vec+ t_0*n$
while
$t_0 = \frac{(d - n*p)}{n^2}$
what is d in my case?
Is the vector n squared the same as:
$n^2_x = n_x*n_x$ $n^2_y = n_y*n_y$ $n^2_z = n_z*n_z$
Is the $\mathrm{Vector}_n * \mathrm{Vector}_p$ the same as $(np = \mathrm{Vector}_n * \mathrm{Vector}_p)$?
$ np_x = n_x*p_x$ $ np_y = n_y*p_y$ $np_z = n_z*p_z$
Thanks go to the one who formatted it. As you are at it, can you put arrows over the appropriate p and n vectors? Then you can remove this phrase.