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Here is a picture of a Möbius strip, made out of some thick green paper:

Möbius strip

I want to know either an explicit parametrization, or a description of a process to find the shape formed by this strip, as it appears in the picture. Now before you jump up and declare, "That's easy! It's just $\left(\left[1+u \cos \frac \theta2\right]\cos \theta,\left[1+u\cos\frac \theta2\right]\sin \theta,u\sin \frac \theta2\right)$ for $u\in\left[-\frac12\!,\frac12\right]$, $\theta\in[0,2\pi)$!" Understand that this parametrization misses some features of the picture; specifically, if you draw a line down the center of the strip, you get a circle, but the one in the picture is a kidney-bean shape, and non-planar. What equations would I need to solve to get a "minimum-energy" curve of a piece of planar paper which is being topologically constrained like this? Is it even true that the surface has zero curvature? (When I "reasonably" bend a piece of paper into a smooth shape, will it have zero curvature across the entire surface, or does some of paper's resistance correspond to my imparting non-zero curvature to the surface?)

This question is thus primarily concerned with the equilibrium shapes formed by paper and paper-like objects (analogous to minimal surface theory in relation to soap-bubble models). Anyone know references for this topic?

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    @JyrkiLahtonen In the example you're thinking of, there will be a large portion of the strip contacting the table, and a section that hangs down in the middle. In this case, the hanging section is affected mostly because of it's weight, as you say, but notably, it is being supported on the side loops, with a contact point under them. In this case, there are only two contact points, and the rest of the loop is being supported from that. Thus, the near and far parts of the loop will hang down more if the force of gravity were to increase, not the other way around.2012-12-17

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The Möbius strip you show is a developable surface. No one, as far as I know, has been able to create a parametrization of it.

Since 1858, when the Möbius strip was discovered, mathematicians have been looking for a way to model it. The problem was finally solved in 2007 by E.L. Starostin and G.H.M. van der Heijden.

You might want to read their paper "The equilibrium shape of an elastic developable Möbius strip" by going to this site - http://www.ucl.ac.uk/~ucesgvd/pamm.pdf

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    Pinging @MJD because Wayne's second answer appears to be targeted at you. As for why the "usual" parameterization is not developable, I am not very good at calculating Gaussian curvature for a parameterization, so I can't say directly, but an easy way to see that it cannot lay flat is to consider a cut at $u=0$. The center line has length $2\pi$, but the edge lines each have length $2\pi(1+v_0^2/32+O(v_0^4))$, and there is no way for a flat surface to have both sides longer than the center. If anything, it is probably developable to a helicoid, but not a plane.2014-08-30
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MJD, since you refer back to the original question, and given your previous comments, I assume you are trying to be provocative.

However, your question does address a very common misconception. In a sense, the same one addressed by the original question.

It is common to think that the Mobius strip that can be modeled by giving a strip of paper a half-twist and joining the ends is described by the parametrization you give.

There are some very real differences between the two that help explain why this isn't so.

FIRST

The parametrization describes a Mobius strip whose center line is a circle.The paper model is like the recycling symbol and has a triangular center line.

SECOND

The parametrization describes the path of a straight line centered on a circle; the straight line travels around the circle and completes a single 180 degree rotation (half twist) by the time it returns to its starting point. At no time is the straight line ever bent in 3D space.

If you draw straight lines crosswise on a strip of paper, then make a model of a Mobius strip, you will discover that in the three corners those lines are bent in 3D space. If you take the time to look seriously at those corners you will discover that each one incorporates a half twist. So a paper Mobius strip actually has three half twists.

THIRD

If you cut the paper model in half crosswise, it will revert to being a flat strip of paper. The Mobius strip being modeled is therefore developable.

If you cut a model of the parametrization in half, it will not lie flat. It is not developable.

To answer your question, the reason I say no one has created a parametrization of a developable Mobius strip, is because as far as I know no one has. As I pointed out, E.L.Starostin and G.H.M. van der Heijden have been able to mathematically model a developable Mobius strip; but their model is not a simple parametrization.

I suggest you go back to your university and point out that they missed the boat on this one. It's as if they told you that topologically a cube, a sphere, and a tetrahedron were the same, then said the formula for a cube describes them all.

By the way, these are not the only two geometrical forms a Mobius strip can take. There are more out there still waiting to be modeled mathematically.

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    Wayne, I encourage you to click the `contact us` link at the bottom to get your two accounts merged. This can help the organization of these answers, and why not?2014-08-31