Typical normal distribution tables give values of $\Phi(x) = P\{X \leq x\}$ for nonnegative values of $x$ where $X$ is a standard normal random variable, usually for $x$ in the range from $0$ to $3.5$. Now, for any normal random variable $Y$ with mean $\mu$ and standard deviation $\sigma$,
$ P\{Y \leq y\} = \Phi\left(\frac{y-\mu}{\sigma}\right)$
Remember the argument on the right as distance of $y$ from the mean $\mu$ measured in units of the standard deviation $\sigma$.
More generally, $P\{y_1 \leq Y \leq y_2\} = P\{Y \leq y_2\} - P\{Y \leq y_1\} = \Phi\left(\frac{y_2-\mu}{\sigma}\right) - \Phi\left(\frac{y_1-\mu}{\sigma}\right)$
The table for $\Phi(x)$ does not list values for $x < 0$ because these values can always be deduced via the relationship
$\Phi(-x) = 1 - \Phi(x).$
Thus, $\Phi(-1) = 1 - \Phi(1)$. So, for any normal random variable, express the probability you want to find in terms of $\Phi(x)$, and then look up values for $\Phi(x)$ in the table if $x \geq 0$, and use $\Phi(x) = 1 - \Phi(|x|)$ if $x < 0$.
Finally, if all else fails, use a calculator such as the one here to check your answer.