How would I do these problems using Implicit Differentiation? I don't understand how to do them. Help?
Find $dy/dx$ if $\cos(4x)-2xe^{4y}=0$.
AND
Find slope of the tangent line to the curve $\sqrt{12x+8y}+\sqrt{2xy}=12$ at the point $(4,2)$.
How would I do these problems using Implicit Differentiation? I don't understand how to do them. Help?
Find $dy/dx$ if $\cos(4x)-2xe^{4y}=0$.
AND
Find slope of the tangent line to the curve $\sqrt{12x+8y}+\sqrt{2xy}=12$ at the point $(4,2)$.
Differentiate both sides of the equation with respect to $x$, remembering that $y$ is supposed to be a function of $x$. So, for example, the derivative of $y^2$ would be $2 y \dfrac{dy}{dx}$. Then solve for $\dfrac{dy}{dx}$. If you are asked for the slope at a point, substitute the $x$ and $y$ values for that point in your expression for $\dfrac{dy}{dx}$.
I'm guessing this is homework, so I won't try to provide a complete solution to either of your questions.
If you differentiate your first equation with respect to $x$, you get $ -4 \sin 4x - 2e^{4y} -8xye^{4y}\frac{dy}{dx} = 0 $ which you should be able to rearrange.
If you differentiate the equation in your second question with respect to $x$, you get $ \frac{12+8\frac{dy}{dx}}{2\sqrt{12x+8y}} + \frac{2y+2x\frac{dy}{dx}}{2\sqrt{2xy}} = 0 $ and you can then substitute in your $x$ and $y$ values.