Given that $S$ is compact and it has no isolated point. Show that given any nonempty open set $P$ of $S$ and any point $x\in S$, there exists a nonempty open set $V\subset P $ such that $x\notin \bar V $ . I am not very sure what i have to do to finish it. My thought is that it for $x\in S$, it is not an isolated point so there exist an $y\in S$ but then not sure how to proceed, and not sure how to know the existence of $V$
Separating points from open sets in a compact space without isolated points
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general-topology
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1@Mathematics It's easy to prove in Hausdorff spaces, and all metric spaces are Hausdorff. Just Pick another point $y \in P$ and an open set $V$ that separates it from $x$. $V \cap P$ satisfies the requirements. – 2012-10-19