today I'm in doubt on calculating the follow expression $\log_4 3 * \log_9 32$
Changing all to base 4: Working on: $\log_4 3 * \dfrac{\log_4 32}{\log_4 9}$
Ending with: $\log_4 3 * \dfrac{2 + \log_4 2}{2*\log_4 3}$
There's a way to simplify it more ? Also, do you know any resource explaining more on rules on every kind of operation with logs ?
Thanks in advance