I have to solve the following,
$\int \frac{8\sin(2x)}{\sin(x)}dx$
but I'm not sure where to begin. I thought of the anti derivative been something like -4cos(2x) but that doesn't take care of the sin in the denominator. Thanks ahead of time.
I have to solve the following,
$\int \frac{8\sin(2x)}{\sin(x)}dx$
but I'm not sure where to begin. I thought of the anti derivative been something like -4cos(2x) but that doesn't take care of the sin in the denominator. Thanks ahead of time.
Hint: You can use the following trigonometric identity: $\sin(2x) = 2\sin(x)\cos(x)$