Which region on complex plane is defined by the geometric images of $z$ that satisfied this condition:
$\frac{z}{i}-\bar{z}=0$
One of my trials was:
$\frac{z}{i}-\bar{z}=0\Leftrightarrow z- \bar{z}i=0$
If $\space z=\rho \space cis(\theta)$, and $ \space \bar{z}=\rho \space cis(-\theta)$, then
$\rho \space cis(\theta)-\rho \space cis(-\theta) \cdot cis(\frac{\pi}{2})=0 \Leftrightarrow$
$ \rho \space cis(\theta)-\rho \space cis(\frac{\pi}{2}-\theta)=0$
But, I get stuck at this stage. Even if I pass to algebric form, I can't figure it out how to solve.
Thanks for the help.