3
$\begingroup$

Take $V = K^{n}$. Let $\omega$ be a non-zero element of $\bigoplus_{k=1}^n \bigwedge^k V$, where we have excluded the summand $\bigwedge^0 V = K$. (1) Prove that there exists an $m > 1$ for which $\omega^m$, where the power is taken in the Grassmann algebra, is zero, and $\omega^{m-1}$ is not yet zero. (2) Find such an $\omega$ for which m of the preceding part is maximal. (Hint: pure non-zero tensors will have $m = 2$, which is certainly not maximal.)

I've figured out that Grassmann algebra is the same as exterior algebra, and that $m-1$ is probably the rank of $\omega$, and therefor in 2) we look for an $\omega$ of maximal rank. But I don't know how to prove it or how to find such a $\omega$.

Any help would be greatly appreciated.

  • 1
    (1) It is enough to show that there exists m>1 such that $\omega^m=0$. (The next step is to choose $m$ minimal with this property.) Or this is clear: the exterior algebra is a graded algebra whose homogeneous components of degree greater than $n$ are $0$.2012-11-25

0 Answers 0