Show that
$(a \times b) \times (c \times d)= [a,b,d]c - [a,b,c]d.$
I understand $[a,b,d] = a \cdot (b \times d)$ and $[a,b,c] = a \cdot (b \times c)$ but not really sure where else to go with this.
Show that
$(a \times b) \times (c \times d)= [a,b,d]c - [a,b,c]d.$
I understand $[a,b,d] = a \cdot (b \times d)$ and $[a,b,c] = a \cdot (b \times c)$ but not really sure where else to go with this.
As Rahul mentioned: $n \times (m \times o) = (n \cdot o)m - (n \cdot m)o$
Then it follows: $(a \times b) \times (c \times d) = (a \times b \cdot d)c -(a \times b \cdot c)d$ Using the expressions you mentioned above this can be further simplified to:$[a,b,d]c - [a,b,c]d$