It does not really matter about the coefficients. Any (invertible) transformation has $ad-bc \neq 0.$ Such a mapping, written as a function, is the composition of a finite string of just three types:
First $f(z) = A z$ for some nonzero (real or complex) $A$ takes circles with center at $0$ to others, lines through $0$ to others.
Second $g(z) = z + B$ takes lines to lines and circles to circles, it is just a translation.
Third, $h(z) = \frac{-1}{z}$ does a little of both. Since $0$ is sent out to $\infty$ and $\infty$ is brought back to $0,$ the following bunch of things happen:
A) a line through $0$ is sent to a line through $0.$
B) a line not through $0$ is sent to a circle that passes through $0,$ with center elsewhere.
C) A circle that passes through $0$ is sent to a line that does not pass through $0.$
D) A circle that does not pass through $0$ is sent to another circle that does not pass through $0.$
You really ought to draw some things yourself for $h(z) = -1/z.$ There is a good reason for the minus sign, but if you prefer draw $H(z) = 1/z.$