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I came across this notation $u \cdot v = \|u\| \|v\| \cos \theta$ while studying for a linear algebra exam.

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    @BrianM.Scott No the dot product is the not the problem, it was the double pipes surrounding the vectors.2012-02-19

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The dot product has the formula

$\mathbf{a}\cdot\mathbf{b}=a_1b_1+a_2b_2+\cdots+a_nb_n.$

The vector norm has the formula

$\|\mathbf{a}\|=\sqrt{a_1^2+a_2^2+\cdots+a_n^2}.$

And the angle $\theta$ (or $\Theta$ in your case, I guess) is the angle between the vectors $\mathbf{a}$ and $\mathbf{b}$ in Euclidean space. The angle can be visualized directly in two or three dimensions, i.e. $n=2$ or $3$.

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    @MikeD: Yes. Geometrically, it is the distance from a vector to the origin in Euclidean space. The absolute value is the distance from a number to $0$ on the real line, which can be interpreted as a one-dimensional Euclidean space, so really this is a generalization of the absolute value! (Of course, it isn't the only generalization available...)2012-02-19
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The equation $u \cdot v = \| u \| \| v\| \cos \theta$ means that the dot product between the vectors $u$ and $v$ is equal to the norm of $u$ times the norm of $v$ times cosine of the angle $\theta$ which is the angle between $u$ and $v$.