I'm having trouble solving an RL circuit using the Laplace Transform.
There's just a 2H inductor in series with a 5M ohm resistor. The inductor is initially charged to 1.25A.
So... Here's what I've done: $ v_L(t) = v_R(t)\\ 2i_L'(t) = 5Mi_L(t) $ Now taking the Laplace Transform, $ 2(I_L(s)s - 1.25) = 5M I_L(s)\\ 2.5 = 2I_L(s)s - 5M I_L(s)\\ 2.5 = I_L(s)(2s - 5M)\\ I_L(s) = \frac{2.5}{2s-5M}\\ I_L(s) = \frac{1.25}{s-2.5M} $ Now taking the inverse Laplace transform, $ i_L(t) = 1.25e^{2.5Mt} $ This answer is wrong though, and there should be negative $ i_L(t) = 1.25e^{-2.5Mt} $
For the life of me, I can't work out where that negative comes from in the maths.
I'd really appreciate some help.
Thanks!
Oh, I should add that the $M$ is Mega (so $10^6$).