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As the title says. Is the matrices $A^*A$ and $AA^*$ hermitian (symmetric if $A$ is real)?

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    Thanks! These hints really helped. Remember this from the lectures now. How could I not see this?2012-01-16

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Check the definition of hermitian. This is not too hard, you just have to use that $(AB)^*=B^*A^*$. You don't need that $A$ is invertible in this proof, the statement is even true for $A$ not a square.