Seeking assistance with the following question please:
A store sells $11$ different flavours of ice cream. In how many ways can a customer choose $6$ ice cream cones, not necessarily of different flavours?
I'm thinking this is a pigeon hole type question where you want to allocate $6$ similar objects (cones) to $11$ pigeon holes (flavours), without restrictions on the number to go in to each pigeon hole. In which case there would be $\binom{6+11-1}6 = \cfrac {15!}{6!\ 9!} = 5005$ ways.
Is this correct?