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This should be really obvious, but I can't quite get my head round it:

I have a complex number $z$. I want to reflect it about an axis specified by an angle $\theta$.

I thought, this should simply be, rotate $z$ by $\theta$, flip it (conj), then rotate by $-\theta$.

But this just gives $z^* (e^{-i\theta})^* e^{i\theta} $...

but this can't be right - as it's just $z^*$ rotated by angle $2\theta$, surely?

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    If I a$m$ not $m$istaken, wouldn't a+ib reflected about $x$ axis be a - ib and about y axis be -a + ib ?2012-02-08

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Indeed, it's just $z^*$ rotated by $2\theta$... And it's almost the right answer! You know that a symmetry composed with a rotation is still a symmetry, and you know that an (orthogonal) symmetry is characterized by its fixed points. So you want to get a symmetry that fixes the axis spanned by $e^{i\theta}$ (as an $\mathbb{R}$ vector space); an easy way to do that is, as you've noticed, to rotate by $-\theta$ (and not $\theta$ actually), flip over the real line (conjugation) and then rotate by $\theta$. So you get $(ze^{-i\theta})^* e^{i\theta} = z^* e^{2i\theta}$. It is easily checked that this fixes $e^{i\theta}$, and it's an orthogonal symmetry, therefore it's the one you're looking for.

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    Oh yes and thanks for correcting my minus signs!2012-02-08