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$A,B,C\in M_n(\mathbb F)$ matrices of the same size such that $rank(A)=r\;\&\;AB=AC.$ Calculate $\max\{\text{rank}(B-C)_{n}\}$

This question is a part of my homework in Linear Algebra, and the title of the homework is "Vector spaces, Linear dependence, Span, and Basis". I have no clue/direction of how to approch this question.

Thank you!

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    Deal with the case $A=\operatorname{Diag}(\underbrace{1,\dots,1}_{r\mbox{ times }},\underbrace{0,\dots, 0}_{n-r\mbox{ times}})$.2012-12-01

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$Im(B-C) \subset null(A)$ then $\dim Im(B-C)+ \dim Im(A) \leq \dim Im(A) + \dim null (A) = n$ $\dim Im(B-C) \leq n -\dim Im(A)$

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    @DorShalom Im =image space $dim Im(B-C) = rank(B-C)$2012-12-01
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Hint: Consider a vector $v$ in the column space of $B-C$. Then $v=(B-C)u$ for some vector $u$. Since $AB=AC$, we have $Av=0$. So, $v$ also lies inside the null space of $A$. Now, what is the relationship between the dimension of the column space of $B-C$ and $\mathrm{rank}(B-C)$? What is the dimension of the null space of $A$?