Let $A$ be a real $N\times N$ matrix. If $A^k$ is symmetric for some $k>0$, does that give away something about $A$.
Power of a matrix and its symmetricity
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linear-algebra
matrices
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0may be in terms of symmetry or may be in terms of its trace or eigenvalues or something. – 2012-12-11
1 Answers
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Since $A^k$ is symmetric, it has real eigenvalues. So, at least you know that if $\lambda=re^{i\theta}$ is an eigenvalue of $A$, you must have $\theta=im\pi/k$ for some integer $m$.