We have to integrate $\int\frac{2x \ln x}{\sqrt{(x^2-9)}} \mathrm dx$
Is it right to use Integration by Parts?
I tried to substitute it with $u = \log x,\: \mathrm du = \frac 1x \mathrm dx;$ $v = x^2 - 9,\: \mathrm dv = 2x \mathrm dx.$
But then I'm stuck with substituting it within the original equation because from $\mathrm du = \dfrac 1x \mathrm dx,$ and $\mathrm dv = 2x \mathrm dx,$ there will be two $\mathrm dx$'s to substitute and from $\mathrm du = \dfrac 1x \mathrm dx,$ the $x$ will go to the denominator and I don't know what to do any more.