Is there some sufficient condition on the kernel $K$ of a (say, finite rank, to simplify) integral operator $ \mathcal K:f(x)\in L^2(\mathbb R)\mapsto \int K(x,y)f(y)dy $ so that it has all its non-zero eigenvalues $\textbf{distinct}$ (i.e. with multiplicity one) ?
Distinct eigenvalues for integral operator?
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real-analysis
functional-analysis
eigenvalues-eigenvectors
operator-theory
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4A finite-rank operator on an infinite-dimensional Banach space has infinite-dimensional kernel. Are you talking about the nonzero eigenvalues? – 2012-08-25