How do I solve the following equation?
$x^2 + 10 = 15$
Here's how I think this should be solved. \begin{align*} x^2 + 10 - 10 & = 15 - 10 \\ x^2 & = 15 - 10 \\ x^2 & = 5 \\ x & = \sqrt{5} \end{align*} I was thinking that the square root of 5 is iregular repeating 2.23606797749979 number. 2.236 multipled by itself equals 5ish.
I've also seen another equation like this: \begin{align*} x^2 & = 4 \\ x^2 + 4 & = 0 \\ (x - 2)(x + 2) & = 0 \\ x & = 2 \text{ or } -2 \end{align*} So I guess I could near the end of my equation do the following:
$x^2 + 5 = 0$
and then go from there?
Is my first attempt at solving correct?