The original question is $f(x) = 7\ln(5xe^{-x})$
I'm not sure if I have to use the chain rule to figure out $\ln(5xe^{-x})$ because $5xe^{-x}$ is one term within ln.
My guess is that it's like this:
$7(-(e^{-x-1})/e^{-x})$
or just simply $-7$.
I'm specifically unsure with how to find the derivative of $5xe^{-x}$.
I know that $e^x$'s derivative is simply $e^x(1)$ because the derivative of $x = 1$
so when I find the derivative of $e^{-x}$ I'd expect it to be $-1e^x$ and in my case $-5xe^{-x}$