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$E_1 = Ch_1^\alpha$

How can I solve for the exponent alpha?

Is it just $\frac{\frac{E_1}{C}}{ln(\alpha)}$?

1 Answers 1

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You get

$h_1^\alpha = \frac{E_1}{C}$

Tking the log, you get

$\alpha \ln(h_1) = \ln \frac{E_1}{C}$

You can easily get $\alpha$ from here. Your answer is almost right, unfortunately, almost right also means wrong ;)

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    Fixed, I knew I should go to sleep instead of answering questions :)2012-10-25