This question arose when playing yahtzee with some friends. Not entirely sure if I'm in the right area, but hope you can help.
How many dice do you need to create a tower whose walls have the same number of eyes?
Through brute force we found that you could do it with 2 dice and 4 dice, so then any multiple or sum of these would be a solution.
But how can you solve such a problem generally?
Or to rephrase it into a hypothesis:
There are no dice towers where every wall has an equal number of eyes and an odd number of dice.