If the triangle must have the following sides:
DE = 3cm DF = 8cm EF = 4cm
And not taking into consideration anything about the angles. Is it possible to draw such a triangle?
If the triangle must have the following sides:
DE = 3cm DF = 8cm EF = 4cm
And not taking into consideration anything about the angles. Is it possible to draw such a triangle?
We can not draw this triangle since $ DE+EF=7<8=DF $ In any triangle, the sum of the lengths of any two sides must be greater than the length of the remaining side.
No. The triangle inequality $DE + EF>DF$ does not hold.
Take the 3 cm and 4 cm sides and hinge them together. Can you then orient them in such a way to fit an 8 cm side between them? No, you'll run out of room. The farthest that you can get the relevant vertices apart is 7cm. This is the content of the triangle inequality mentioned in the other answers.