How can I solve the following equation:
$2^{log_3 x}+x^{log_3 2}=4$
I don't want the final answer, I want to know how I can solve these kind of equations.
How can I solve the following equation:
$2^{log_3 x}+x^{log_3 2}=4$
I don't want the final answer, I want to know how I can solve these kind of equations.
Put $x=3^y$
Simplify $2^{log_3 x}$ and $x^{log_3 2}$ as follows:
$log_3 x=log_3 3^y=ylog_3 3=y$
$x^{log_3 2}=(3^y)^{log_3 2}=(3^{log_32})^y=2^y$