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$y(n) = x(-n)$ , causal or not , memory or memory-less ?

it's a question in digital signal processing course .

My guess it's memory less , causal because $x(-n)$ is only the inverse of the function ?

Memoryless System A system is memoryless if the output y[n] at every value of n depends only on the input x[n] at the same value of n

Causality A system is causal it’s output is a function of only the current and previous samples

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    well, a system is memoriles if output$y[n]$for every value of n (say, for n=5, y[5]) depends only of the input at the same instant (x[5]) But y[5] does depend rather on x[-5], so...2012-06-02

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  • It is not causal. Consider $n=-1$. The output $y(-1)$ depends on the input at $n=1$, which is only available in future.
  • It is not memoryless. Consider any $n > 0$. The output $y$ depends on the input at $-n$ which was applied in the past. Thus the system has memory.