The title is quite vague, but I don't see how to phrase it.
I'm new to MatLab and have very little experience with matrix calculation.
Suppose a matrix "a" :
a = 2 5 6 12 13 17
It represent some intervals of values.
Then a matrix "b" that represent wider intervals :
b = 1 8 9 20
I need to compare these two matrix so the result will have the same number of rows than a
and as many columns as there are rows in b
. In that particular case the result should be :
result = 4 0 3 4 0 5
explanation : the first row of result is [4, 0]
because the first row of a
have 2 4 values included in the interval of the first rows of b
and 0 in the second. 2, 3, 4 and 5 (from a
) all falls between 1 and 8 (from b
).
The second row is [3, 4]
because 6, 7 and 8 fall between 1 and 8 (3 numbers in the first intervals of b
) while 9, 10, 11 and 12 fall between 9 and 20 (4 numbers in the second interval of b
).