I have the following expression to get its laplace transfer: $e^{2t}(3t-3t^2)$
Is it ok to just calculate the transfer of each term then multiply the result? I calculated the expression above like this but it is different than the answer in my book:
${\frac{1}{s-2}}*\frac{3}{s^2}-\frac{6}{s^3}$ $\frac{1}{s-2}*\frac{3s^3-6s^2}{s^5}$ $\frac{3s^3-6s^2}{(s-2)s^5}$