The question is to find
$\displaystyle \int \frac {4\sin (x)}{5+4\cos^2x -8x}dx$
Can anyone help me? I need all the steps, because I need to understand what to do. Many thanks in advance.
What I tried so far: substitute $t=\cos(x) \ldots$ no way to solve $\int \frac{-4}{4t^2-8\arccos t+ 5}dt$