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I have a little confusion with signs. Thanks in advance.

$\lim_{x \to 0^-}{\frac{-\sin|x|}{x}}$ (This is a left limit, i.e. $x<0$)

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    that's that I mean Asaf.2012-12-02

1 Answers 1

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$x<0\Longrightarrow |x|=-x\Longrightarrow\frac{-\sin|x|}{x}=\frac{\sin x}{x}\xrightarrow [x\to 0^-]{}1$

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    I see, tha$n$ks for the courtesy.2012-12-02