I am trying to evaluate the following integral, but don't know how to take the coefficient of $z$ out of the parenthesis to get it into the Cauchy integral form. Any help is appreciated.
$ \oint_C \frac{\sin 2z}{(6z-\pi)^3}dz$
I am trying to evaluate the following integral, but don't know how to take the coefficient of $z$ out of the parenthesis to get it into the Cauchy integral form. Any help is appreciated.
$ \oint_C \frac{\sin 2z}{(6z-\pi)^3}dz$
Do you mean as in $6^3\left(z-\frac{\pi}{6}\right)^3?$