When you answer this question $(10^4 - 10^2) \cdot 0.0012121212\dots$ you get $12$. However, that seems to defy PEMDAS. Please explain. Doing PEMDAS wouldn't you get $(10^4 - 10^2)$ = $10^2$ and then multiply that by $0.0012121212\dots$?
Why does $(10^4 - 10^2) \cdot 0.0012121212\dots = 12$?
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$\begingroup$
arithmetic
exponentiation
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0@Isaac: Oh well, I rather be well-educated. :-) – 2012-07-05
2 Answers
5
I figure it might be easier to see like this.
$10^4\times0.001212...=12.1212..$
$10^2\times0.001212...=0.1212...$
Now subtract.
$(10^4\times0.001212...)-(10^2\times0.001212...)=12$
Using the distributive property, we can rewrite this as
$(10^4-10^2)\times0.001212...=12$
3
First, let $n=0.0012121212\dots$ so that $100n=0.12121212\dots$. Subtracting, $100n-n=99n=0.12=\frac{12}{100}$, so $n=\frac{12}{9900}$ (I'm intentionally not simplifying those fractions).
Now, as pointed out in the comments, $10^4-10^2=10000-100=9900$, so $(10^4-10^2)(0.0012121212\dots)=9900\cdot\frac{12}{9900}=12.$
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0oh woops I see the problem I was dividing therby subtracting the exponents. thanks! – 2012-07-05