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In the figure AB=4 , BC=6 , AC=5 and AD=6 what is length of DE ? Ans=9 enter image description here

I know there must be some property here that would solve this problem instantly but I cant figure it out any suggestions ? Edit: Since the two triangles are similar there corresponding sides will be equal in ratio , however I am still getting the wrong answer

BA   CA   BC 4    5    6 AE   6    DE 

$AE = \frac{24}{5}$ and $DE = \frac{36}{5}$

Where am I going wrong ?

  • 1
    One way to see why the symmetry should be reflection and not rotation is to consider moving A 'north' towards the top of the circle; then AC obviously shrinks, but on the other triangle the edge that shrinks is AE, not AD - so the similarity must be between ABC and ADE (note orientation), not ABC and AED.2012-07-17

1 Answers 1

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Hint: Use the inscribed angle theorem.

Edit: I guess it's time to expand this answer a bit. The inscribed angle theorem guarantees that the angles $\angle CBE$ and $\angle CDE$ are equal, as well as the angles $\angle BCD$ and $\angle BED$. Also, the angle $\angle CAB$ is obviously equal to the angle $\angle EAD$. Therefore the triangles $\triangle AED$ and $\triangle ACB$ are similar. This means that the ratios of the lengths of respective edges should be equal or:

$\frac{|AE|}{|AC|}=\frac{|AD|}{|AB|}=\frac{|ED|}{|CB|} \; .$

This means that the length of edge $ED$ must be $9$.

  • 0
    Rajeshwar, if two triangles are similar then their angles will be *equal*.2012-07-18