How to evaluate $\int {\frac{{\cos {x^3}}}{x}dx}?$ Maple evaluates this as $\frac{{{\text{Ci}}({x^3})}}{3}.$ Edit: If this cannot be evaluated in terms of elementary functions, is there a general strategy which allows us to deduce that this is the case?
How to evaluate $\int {\frac{{\cos {x^3}}}{x}dx}$
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integration
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0Concerning the edit : just some days earlier we had the same kind of [question](http://math.stackexchange.com/questions/239105/special-integrals/239854#239854). Set $z=x^3$ to get $\ \frac 13\int \frac{\cos(z)}z dz$ and use the demonstration there for $\int \frac{\sin(z)}z dz$. – 2012-11-20
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$I = \int \dfrac{\cos(x^3)}{x} dx = \dfrac13 \int \dfrac{\cos(x^3)}{x^3} (3x^2)dx = \dfrac13 \int \dfrac{\cos(x^3)}{x^3} d(x^3) = \dfrac{\text{Ci}(x^3)}{3} + \text{constant}$ There is no expression for the above integral in terms of "elementary functions". If the limits of the integral are from $-a$ to $a$, the Cauchy principal value of the integral is $0$ since the integrand is an odd function.
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0@glebovg thanks a lot. – 2013-04-06
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http://reference.wolfram.com/mathematica/ref/CosIntegral.html
http://www.wolframalpha.com/input/?i=cosineintegral%28x%29
That means there is a real part and a imaginary part.
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