The ODE looks very identical ( kinda of)
The ODE I have is
$y'' - y' + y = 0$ $y(0) = 5$ $y(1) = y(-1)$
The solution (nontrivial) I got is
$y = 5e^{t/2}[\cos(\sqrt{3}x/2) + \left ( \frac{1-e}{1+e} \right )\cot(\sqrt{3}/2)\sin(\sqrt{3}x/2)]$
Wolframalpha
Could someone explain to me how do I get from my solution to do that weird shifting with the x - 1 part inside the sine functions? Wolframalpha doesn't show the "simplification"
Thanks