How can I Find all solutions of the diophantine equation? :
$xy=\frac{3x+y}{2}.$
How can I Find all solutions of the diophantine equation? :
$xy=\frac{3x+y}{2}.$
$(x,y)=\left(x,\frac{3x}{2x-1}\right)$
Hence :
$3x=k(2x-1)$
$3x=2kx-k$
$x=\frac{k}{2k-3}$ for some integer $k$
Given this answer that Bill gave you just one hour ago, this would be unfair to give you another similar one for this question as well.
Hint: (Inspired by a similar hint from Bill Dubuque)
Rewrite the equation as $(2 x - 1) (2 y - 3) = 3$ and equate $2x - 1$ with the factors of $3$.