$\lim_{x\to 0}\frac{\sin{6x}}{\sin{2x}}$
I have no idea at all on how to proceed. I am guessing there is some trig rule about manipulating these terms in some way but I can not find it in my notes.
I tried to make $\tan$ into $\dfrac\sin\cos$
$\frac{\sin6x}{\cos6x} \times \frac{1}{\sin2x}$
But this doesn't get me anywhere as far as I can tell.