4
$\begingroup$

I am trying to evaluate the following integral, but don't know how to take the coefficient of $z$ out of the parenthesis to get it into the Cauchy integral form. Any help is appreciated.

$ \oint_C \frac{\sin 2z}{(6z-\pi)^3}dz$

1 Answers 1

4

Do you mean as in $6^3\left(z-\frac{\pi}{6}\right)^3?$

  • 0
    Hmm. I tried expanding it out and got into a mess, and didn't realize it was that simple. Thanks.2012-07-17