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Can someone please explain how to do this problem?

Prove or disprove the statement “If $a \mid b$ and $c \mid d$, then $(a + c)\mid(b + d)$”.

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    Experimentation with such things can be very important, both in a search for a counterexample and a search for a proof. In your case, in seconds you will find a counerexample.2012-10-03

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Take $a=2,b=4,c=3,d=3$, then what can you say ?

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    Assume $a \mid c$ and $b \mid d$. Then there exist integers $l,m$ with $am = c$ and $bl = d$. Find integer $q$ with $(ab)*q=cd$2012-10-03
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Hint $\ $ By the mediant inequality $\rm\:\frac{b}a < \frac{d}c\:\Rightarrow\:\frac{b}{a} < \frac{b+d}{a+c} < \frac{d}{c}.\:$ Therefore, when the extreme terms are consecutive integers, the middle term is not an integer.