0
$\begingroup$

On a Cartesian graph I have a point at $x = 0$ and $y = 0$. This point needs to move forward at a $30^\circ$ angle. It should travel forward at this angle for $1.75$ on the graph. What equation can I use to do this?

Summary:

  • Cartesian graph point $(0, 0)$
  • Moves forward at a $30^\circ$ angle
  • Needs to travel forward at the angle $1.75$ on the graph
  • Is there an equation for this?
  • 0
    Looks like (sin( angle * pie / 180) * 1.75) worked.2012-05-07

1 Answers 1

3

There is an way to determine the coordinates of the point. I assume that you mean "moves $1.75$ units along a line in the first quadrant that makes a $30$ degree angle with the positive x-axis", or something like that.

Draw a reference right triangle enter image description here

This one is pretty sloppy... learn "SOHCAHTOA", a mnemonic device for trig ratios. Then we can say $\cos(30) = x/1.75 $

$\sin(30) = y/1.75$ And solve for x, y.

  • 0
    your missing (angle * pie / 180) * 1752012-05-15