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The question is:

If the area of a parallelogram $JKLM$ is $n$ and if length of $KN$ is $n+(1/n)$, then find the length of $JM$. (The answer is $n^2 /( n^2+1 )$.)

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How would i go about solving this problem ?

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    Thats a standardized test question .. A lot of their questions don't make any sense.2012-06-08

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The area of a parallelogram (or see on Wikipedia) is the base times the height. The base here is $JM$ and the height is $KN$, so the area is $KN * JM = n$

So you have

$ \left(n + \frac{1}{n}\right)*JM = n $ Then you solve for $JM$

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    @Rajeshwar: So in general the area of a parallelogram is the base times height. Your base is $JM$, the height is $KM$, so the area is the product $JM*KN$.2012-06-08