If $2\sin(x-y) = \sin(x+y)$, find $\displaystyle \frac{\tan(x)}{\tan(y)}$
= 2(sinxcosy-sinycosx) - sinxcosy - sinycosx = sinxcosy - sinycosx
//I'm not sure if bringing the sin(x + y) to the left side was right or wrong, just an idea I had.
Thanks in advance for your help, very appreciated.