For simplicity, imagine that a strategy is just to pick up a number. Now think about the value of increasing the strategy of player 1 assuming player 2 strategy is being held constant. If the value of increasing the strategy is higher the higher is the strategy of player 2, we say the payoff of player 1 is super-modular in the strategies. If this happens for both players, their strategies are said to be complementary. If payoffs are differentiable this is the same as the cross-partial derivatives of payoffs being positive: $\frac{\partial u_i}{\partial s_1 s_2}(s_1,s_2)\ge 0$ for $i=1,2$.
In the case of ta finite game like the Prisoners Dilemma, we must somehow order the strategies. Let's say that cooperation is low strategy and defect is the high strategy, $C. Super-modularity would imply that $u_1(D,C)-u_1(C,C) \le u_1(D,D)-u_1(C,D)$. That is, the gain of changing from cooperating to defecting given the opponent cooperates must be less than the gain of changing from cooperating to defect given the opponent defects. Some remarks: If you choose a different order (ay $C>D$) then you still have the same inequality as before. Not all Prisoners Dilemma games are super-modular.
$D>C,\;\text{super-modular}\Longrightarrow \begin{matrix} & D & C \\ D & 0,0 & 3,-7 \\ C & -7,3 & 2,2 \end{matrix} $
$D>C,\;\text{not super-modular}\Longrightarrow \begin{matrix} & D & C \\ D & 0,0 & 7,-1 \\ C & -1,7 & 2,2 \end{matrix} $
Super-modularity is more interesting/useful in the context of coordination or matching games than in the prisoners dilemma because it implies the set of Nash equilibrium is a lattice (nice math object). In the case of the prisoner dilemma, there is only one Nash equilibrium so we are not interesting in talking about the set of equilibria...