Would it be possible to show the breakdown of how $\log_4$ $32$ = $\frac{5}{2}?$
I have to come up w/ 11 more just like it & I'm not sure how you came up w/ the answer.
Thank you!
Would it be possible to show the breakdown of how $\log_4$ $32$ = $\frac{5}{2}?$
I have to come up w/ 11 more just like it & I'm not sure how you came up w/ the answer.
Thank you!
You could use the change of base formula, noting that $4$ and $32$ are each powers of 2...
$\log_4(32) = \dfrac{\log_2(32)}{\log_2(4)} = 5/2$
Alternatively you could say: $log_432=log_42^5=log_4(4^{\frac{1}{2})^5}=log_44^{\frac{5}{2}}=\frac{5}{2}log_44=\frac{5}{2}$
please look at $log_4(32)$ ,here $4=2^2$ and because it is log function,we can factor out 2 as 1/2,and $32=2^5$ ,for this ,we simple take out 5 from power and place in front of logarithm,so we would have 5/2*$log_2(2)$,this one
$log_2(2)=1$ so we have left $5/2$,i hope it would help