Given $(\log_3 x)^3 = 9 \log x$, solve for $x$.
Here is what I have so far: $(\log_3 x)^3 = \frac{9\log_3 x}{\log_3 10}$ $let a = \log_3 x$ $a^3=\frac{9a}{\log_3 10}$ $a^3-\frac{9a}{\log_3 10} = 0$ $a(a^2-\frac{9}{log_3 10}$ $\log_3 x = 0, \log_3 x = \pm\sqrt{\frac{9}{\log_3 10}}$
I solved the first part of that to give $x=1$, which I plugged back in and worked. But for the second part of the solution, $x$ could equal roughly $9.743156891$ or $0.1026361385$. Plugging them both into the original equation, I get the same on both sides. Yet, when I graphed it, the only solution, as far as I could see, is $1$.
I guess my real question is, are $9.74$ and $0.10$ actual solutions to the equation? Or are the extraneous for some reason?