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Given a modified regression equation:

$\hat Y = \exp(\beta_0 + \sum\beta_ix_i + \varepsilon)*F$

where:

$\hat Y = 11353$

$\beta_0 = 8.693021$

$\sum\beta_ix_i = 5.95487177696$

$F = 0.21829$

what is:

$\varepsilon =$

1 Answers 1

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$ \hat Y = \exp(\beta_0 + \sum\beta_ix_i + \varepsilon)*F \\ \hat Y / F = \exp(\beta_0 + \sum\beta_ix_i + \varepsilon) \\ \ln (\hat Y / F) = \beta_0 + \sum\beta_ix_i + \varepsilon \\ \ln (\hat Y / F) - \beta_0 - \sum\beta_ix_i = \varepsilon $