Three vertices: X, Y, Z Three edges: edge a (Vertex X to Y), edge b (Vertex Y to Z), edge c (Vertex Y to Z [yes another edge connecting it]).
I want to know the probability of X to Z (as in flow from X to Z) if edge a has probability of .9 edge b has probability of .8 P(edge a intersects edge b) = .75 edge c has probability of .5 a and b is independent of edge c
*note you can reach vertex z from X with edge a and b OR edge a and c.
So, I was thinking P(a U b) = P(a) + P(b) - P( a intersects b); P(a Union b) or P(a)*P(c) which is adding those two 1.3 or 130% which doesnt make sense.
Anyone know how to approach this problem?
or maybe multiplying them instead of adding them?
them = P(a U b) and P(a U c) = .95*.45 = .4275 which seems a bit low to gettin to Z from X