Let $G$ be a non-Abelian group and let $n$ be a (large) positive integer (eventually going to infinity). For simplicity, let's take $G=\mathbb{D}_6$ (Dihedral group of order $6$). Is there a way to find (all or a lot of) subgroups of $G^n$? One way is to take images of homomorphisms into $G^n$ or kernels of homomorphisms from $G^n$ but neither of these gives you all of the subgroups. Another way is to use Goursat's lemma sequentially for $i=2,3,\cdots,n$ but since $n$ is large this is not feasible. Any other ideas?
Subgroups of $G^n$
3
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abstract-algebra
finite-groups
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0The number is going to blow up very quickly. For every prime divisor $p$ of $|G|$ you have a subgroup of order $p$ in $G$, so $G^n$ contains *at least* one copy of the elementary abelian group $(C_p)^n$, which by @Gerry already gives rise to a ton of subgroups. – 2012-12-05