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I'm having trouble understanding what the $A$ stand for. That's the only place $A$ is mentioned, without knowing what it is, I can't solve the rest of the exercise.

$V = \{ X \in P(A) \mid |X| \text{ is odd}\},$

Thanks for your help

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    I have no idea, since we have even less context than you do. Could you tell us what exactly the exercise is, and what you've done so far?2012-03-25

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Suppose that $A$ is a set, then $P(A)$ is the collection of all subsets of $A$. This means that $V$ in your question is the collection of all subsets of $A$ that has an odd number of elements.

For example, if $A$ is the set $\{0,1,2\}$ then $V=\{\{0\},\{1\},\{2\},\{0,1,2\}\}$.

Without further context it is hard to tell what $A$ means exactly, though. I suppose it is a general set on which you are supposed to prove some statement.

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    Thanks for your help, turns out it doesn't matter what$A$actually is, as long it doesn't contain the empty set I can prove it's not a vector space. (Multipling X ∈$V$by scalar 0̅ ∈ Z₂ yields an empty set, which is not part of V)2012-03-25