I must solve for x for this function.
$e^x-20x=0$
I'm not sure what to do here. I've tried this so far but it makes no sense: $\begin{align*} e^x&=20x\\ x\ln e&=\ln20+\ln x\\ \frac{x}{\ln20}&=\ln x \end{align*}$
I tried this as well but I'm not sure if this is right either: $\begin{align*} e^x&=20x\\ \ln e^x&=\ln20x\\ x&=\ln20+\ln x \end{align*}$
I've got more confidence in the second try, although I don't know how to solve for an actual number.
The answer is a decimal.