In the American version of Scrabble version there are how many possible starting racks.
A rack contains exactly 7 letters (blanks count as a letter for this problem). Most of the letters in scrabble are constrained meaning that a rack can contain:
At most 2 of B, C, M, P, F, H, V, W, Y, or blanks
At most 1 of K, J, X, Q, Z,
AT most 3 G, 4 D, 4 U, 4 S, 4 L 6 T, 6 R, 6 N, 7 A, 7 I, 7 E, 7 O, 7 U
I guess this would be the number of positive integer solutions for the equation .................................. a +b +c +d + ... +x +y +z +blanks = 7.
Where a is greater than or equal to 0 and less than or equal to 7, b is greater than or equal to zero and less than or equal to 3 ....