$(x^2+xy)\displaystyle\frac{dy}{dx}-(3xy+y^2)=0$
Here is my idea , $\displaystyle\frac{dy}{dx}=\displaystyle\frac{y}{x}-\displaystyle\frac{2x}{x+y}+2$
Let $t=\displaystyle\frac{y}{x} $ , then
$RHS=t-\displaystyle\frac{2}{1+t}+2$
But I don't know how to do the LHS
Is that a right way to solve this question??
If the idea is wrong , please teach me.
Thanks a lot