I have 3 derivatives that I need to find:
1: $ y = 3sin(x) - ln(x) + 2x^\frac{1}{2} $
My answer:
$ 3cos(x) - \frac{1}{x} + (\frac{1}{2}) (2x^\frac{-1}{2}) $
2: $ y = 3e^{2x} * ln(2x + 1) $
My Answer:
$ 3e^{2x} (\frac{2}{2x+1}) + 6e^{2x} (ln(2x+1)) $
3: $y = \frac{sin(2x)}{3x^2 + 5} $
My Answer:
$ \frac{(3x^2 + 5)(2sin(2x)) - sin(2x)(6x)}{(3x^2 + 5)^2} $
I'm relatively positive I did these correctly, but please let me know if I haven't.
EDIT
3: $ \frac{(3x^2 + 5)(2cos(2x)) - sin(2x)(6x)}{(3x^2 + 5)^2} $