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I was wondering if you could help...

I have Math homework, I was hoping if you could check my answer.

Find the equation of the line perpendicular to $3x+2y-4=0$ going through point $(2,-3)$.

$y=\large\frac{-3x+4}{2}$

$y = 2$

$x=-\large\frac{2(y-2)}{3}$

$x=-3$

Therefore my equation is correct?

thanks for you help in advance guys.

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    OK... It all sort of makes sense. I lied when I said it my homework. My little Sister's. It's all gibberish to me. @Isaac - you're very correct in determining what sort of response is required. I assumed it was the search for Ordered Pairs [x, (-2-(3/2)x)]2010-08-31

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If two lines are perpendicular, the product of their slopes is -1. This is often restated as the slope of the line perpendicular to a given line is the opposite reciprocal of the slope of the given line. For example, the line $6x-15y+3=0$ has slope $\frac{2}{5}$, so a line perpendicular to it will have slope $-\frac{5}{2}$.

With that fact, you should be able to determine the slope of the line for which you are finding an equation, and you know a point on the line. Those two pieces of information should be enough for you to write an equation of the line perpendicular to $3x+2y-4=0$ going through point $(2,-3)$.