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I need to re-arrange the following equation to make $d$ the subject [i.e., solve for $d$]:

$a = \sqrt{\frac{d}{be}}.$

The square root part is really confusing me, any help would be much appreciated.

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    So as the equation is re-arranged to be$d$=2010-11-18

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Ok. Squaring both sides you obtain $a^{2} = \frac{d}{be} \Longrightarrow d = (be) \times a^{2}$

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    If you want extra points for precision, note down “if \Re a>0” after your answer. For additional credit, extend that condition to the full set of $a$ for which $a=\sqrt{c}$ has an answer, it's very similar to the condition above …2010-11-19