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(1/8)(3m - 5) = (6/5)(6m - 2) + 5...Type your answer as a fraction. Do not use decimals!

**i got -129/273 is this correct ?

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    http://www.wolframalpha.com/input/?i=Solve[%281%2F8%29+%283x+-+5%29+%3D%3D+%286%2F5%29+%286x+-+2%29+%2B+5%2C+x]2010-12-22

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Assuming you mean: $\frac{1}{8}(3m - 5) = \frac{6}{5}(6m - 2) + 5$
You would solve as:
$40 * \frac{1}{8}(3m - 5) = 40 * (\frac{6}{5}(6m - 2) + 5)$ $5 * (3m - 5) = (48 * (6m - 2)) + 200$ $15m - 25 = 288m - 96 + 200$ $15m - 25 = 288m + 104$ $-129 = 273m$ $m = -\frac{129}{273} = -\frac{43}{91}$


Assuming you mean $\frac{1}{8(3m - 5)} = \frac{6}{5(6m - 2)} + 5$
You would solve as:
$\frac{1}{24m - 40} = \frac{6}{30m - 10} + 5$ $(30m - 10)(24m - 40) * \frac{1}{24m - 40} = (30m - 10)(24m - 40) * (\frac{6}{30m - 10} + 5)$ $30m - 10 = 24m - 40 + (5*(30m - 10)(24m - 40))$ $30m - 10 = 24m - 40 + (5 * (720m^2 - 1140m + 400))$ $30m - 10 = 24m - 40 + 3600m^2 - 7200m + 2000$ $0 = 3600m^2 - 7206m + 1970$ $m = \frac{1201 \pm \sqrt{654401}}{1200}$

(I would double check the work on both of these though, I'm tired =/)

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    @ Reese Moore i agree, it never told me to reduce but to only write it in fraction form.2010-12-22