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Say I have $\sqrt{\frac{2}{9}}$. How would I convert this to a mixed radical where the radicand is a whole number?

I can convert the $\sqrt{8}$ to a mixed radical easily, $2\sqrt{2}$, but this fraction is tripping me up.

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    _"I'm assuming it has something to do with the square root of 9."_ Yes. Hint: What's $3 \times 3$?2011-07-24

2 Answers 2

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$\sqrt{\frac{2}{9}} = \frac{\sqrt{2}}{\sqrt{9}} = \frac{\sqrt{2}}{3}$

Is this what you wanted?

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    @Hans- Oops, you are right, thanks.2010-10-04
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What do you mean by the radicand is a "whole number"? In your example $\sqrt{8}=2\sqrt{2}$ in both sides of the equation the radicand is a whole number.

In any case, it doesn't really matter because the problem as you stated it doesn't have a radical at all when you simplify: $\sqrt{\frac{2}{8}}=\sqrt{\frac{1}{4}}=\frac{\sqrt{1}}{\sqrt{4}}=\frac{1}{2}$.

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    Maybe I'm wrong, but I assumed the first 2 is called the index, and the second was the radicand. Also, sorry for the mistake, I wanted 2/9 as opposed to 2/8.2010-10-03