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I had the question $9x^2 - y^2 = 1$ and my answer was $\frac{\mathrm{d}x}{\mathrm{d}y} = -18x-2y .$

I was wondering if I tackled this correctly? I am new to this.

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    Some of us would then simplify to $(9x)/y$.2011-10-25

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$ \frac{d}{dx}\left(9x^2 - y^2\right) = 18x - 2y\cdot\frac{dy}{dx} = \frac{d}{dx} 1 = 0. $ Then from $ 18x - 2y\cdot\frac{dy}{dx} = 0, $ you can find $dy/dx$.

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    (+1), also to get the ball rolling ;)2011-10-25