The problem statement, all variables and given/known data
Find the center of mass of the solid of uniform density bounded by the graphs of the equations: Wedge: $x^2+y^2=a^2$ $z=cy\qquad(c>0),\;y \geq 0, z \geq 0$.
Relevant equations
$M_x= \int y \cdot \rho(x,y) dA$ $M_y= \int x \cdot \rho(x,y) dA$ $\overline{x} = \frac{M_y}{m}$ $\overline{y} = \frac{M_x}{m}$
The attempt at a solution
I set up all the equations for $M_x, M_y, \overline{x}, \overline{y}$ but I cant seem to realize what the limits of integration are. I can't see how the $z=cy$ comes into play at all. Does it imply a 3 dimensional figure? Do I just integrate with respect to the limits of $x^2+y^2=a^2$?