Sorry for the easy question in advance, I'm trying to remember my algebra and I've come across a problem I don't quite remember the answer to:
I've gotten the original problem (trying to get the $y$ to one side): $7\left(\frac{-9-2y}{y}\right) + 3y = -13$ to this: $-\frac{14y}{5} + 3y = -13 + \frac{63}{5}$ by simply distributing the 7.
But now I'm stuck because I don't remember how to "split apart" the $y$ from $-14y/5$. Mainly it's the /5 that confuses me, I don't remember how to deal with (i.e. what the rules are) the dividing when "splitting apart" the numbers from the variable.
Thanks bunches!