For $ 0 <\theta<\frac{\pi}{2}$ find the solution of
$\sum\limits_{m=1}^{6}\csc\left(\theta+\frac{(m-1)\pi}{4}\right)\cdot\csc\left(\theta+\frac{m\pi}{4}\right)=4\sqrt{2}$
I thought of solving this as the angles form an A.P , But the given sum does not come under any standard type such as the sum of the sines or cosines of the angles in an A.P.So I am unable to proceed further.