How do you solve for $x$ when $x$ is in the denominator?
E.g.
$10 = \frac{g-1}{x}$
How do you solve for $x$ when $x$ is in the denominator?
E.g.
$10 = \frac{g-1}{x}$
Zillions of undergraduates with no interest in mathematics but a fair amount of interest in "surviving" required math courses will reflexively say "cross-multiply!". And in this case, they'd be right. But maybe they'd miss it because they don't quite see two fractions: $ \begin{align} \frac{10}{1} & = \frac{g-1}{x} \\ \\ \\ 10x & = 1(g-1) \end{align} $ then divide both sides by $10$.
(Then you have to talk them out of "cross-multiplying" when they see $\dfrac ab - \dfrac cd$ and claim that it's of course equal to $ad - bc$, etc.)
You can use the technique of "clearing denominators". To do so, just multiply both sides of the equation by whatever denominator you wish to get rid of. $ \begin{align*} 10 &= \frac{g-1}{x}\\ 10 \cdot x &= \frac{g-1}{x} \cdot x\\ 10x &= g-1. \end{align*} $ No matter how many denominators there are, you can use this trick to clear them all. Now you have a much simpler equation to work with.