How to find a three digit number which,when reversed, becomes equal to $17$ times the square of it's cube root?
If we assume that the three digit number is of the form $100x+10y+z$,where $x \in [1,9]$ and $y,z \in [0,9]$.It seems to me that we have to solve $(x,y,z)$ from the equation $100z+10y+x = 17 \times (100x+10y+z)^\frac{2}{3}$
but I just can't see what to do next,any ideas?