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Four of the six numbers $1867,\quad 1993,\quad 2019,\quad 2025,\quad 2109,\quad \text{and}\quad 2121 $ have a mean of 2008. What is the mean of the other two numbers?

I would like to get help for this problem because i want to find a way to answer this problem without using guess and check. thank you :)

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    This is a great example of how math works (i$n$ an elementary example). A beginner will think (I'm guessing): compute -all- means of subsets of size four out of six, find one that is 2008, and then compute the means of what is left over. And of course this is too hard, too much computation. And the beginner would then just give up, but the more experienced would try -not- to do all that work.2011-05-11

2 Answers 2

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Suppose $a,b,c,d$ are the four numbers whose mean is 2008. That means that $\frac{a+b+c+d}{4} = 2008.$

If $e$ and $f$ are the other two numbers, you want to find $\frac{e+f}{2}.$

Well, if you know $e+f$, you can figure out their mean (just divide by $2$). And you happen to know how much the sum of all six numbers is (you can just compute it). Can you use the information you have to figure out what $e+f$ must be?


Added. Given the comment by the OP below, it seems the hint above is insufficient.

You don't need to know the four numbers. Nobody is asking you what the four numbers are, or what the other two numbers are. All you need to know is what $e+f$ is. Because once you know what the sum of "the other two numbers" is, then you can just divide that sum by $2$ and get the mean.

Now, you know what $a+b+c+d+e+f$ (the sum of all six numbers) is: it's $1867 + 1993 + 2019 + 2025 + 2109 + 2121 =12134.$ (I'm not saying that $a$ is 1867; I'm just saying that adding all six numbers is 12134).

You also know what the sum of the four numbers whose mean is 2008 is: because you know that $(a+b+c+d)/4 = 2008$, so that means that the sum of the four numbers is $4\times 2008 = 8032$.

So: the sum of all six numbers is $12134$. The sum of the four numbers with mean 2008 is $8032$.

How much is the sum of "the other two numbers"?

And if the sum of the other two numbers it that much, how much is their mean?

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    nevermind i got the answer you just subtract the sum of the six numbers and the sum of the four numbers2011-05-17
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Hint: If $X$ is the mean of $N$ numbers then their sum is...?

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    @Bri$a$na791: Read the question: **you don't need to get the four num$b$ers.** Nobody is $a$sking you to find the four numbers. You don't care what the four numbers are. What you want to know is what the mean of "the other two numbers" is.2011-05-17