Solution to problem
Hi, I'm correcting my work for study, and I cant get my head around this sum.
I understand where the $x^2 + x − cx$ comes from but then when the 6 appears it loses me.
Solution to problem
Hi, I'm correcting my work for study, and I cant get my head around this sum.
I understand where the $x^2 + x − cx$ comes from but then when the 6 appears it loses me.
$(x^2-5x+5cx-6b^2)-(x^2+x-cx)=x(-6+6c)-6b^2$
because:
$(x^2-5x+5cx-6b^2)-(x^2+x-cx) =$
(by distributing the - sign onto each operand in the bracket this is the equivelant of multilying each term by -1 so -(a+b-c)=-a-b+c)
$(x^2-5x+5cx-6b^2)-x^2 -x + cx =$
re-arranging the terms:
$x^2 - x^2 -x -5x+ cx + 5cx-6b^2 =$
$-6x+ 6cx - 6b^2 =$
$x(-6+6c)-6b^2$