I am attempting to find the derivative of $\frac{(v^3 -2v\sqrt v) } v$ using the quotient rule I set the problem up like this: $v(3v^2 - 3v^{1/2}) - (v^3 - 2v^{3/2})1$ and the denominator is $v^2$ which I do not think it important until the end. Anyways from that I get $ \frac {2v^3 - 2v^{3/2}}{ v^2} $.
This is not the answer my book is getting, I am sure I messed up something simple.