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$\begingroup$

$ (k+1)[k/2 + 1] = [(k+1)(k+2)] / 2 $

can anyone explain why the factorization becomes $ [(k+1)(k+2)] / 2 $

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    I don't understand the question: why there is suddenly an equality sign in the middle of an expression?2011-05-06

2 Answers 2

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Answer to the revised question. Observe that the factor $\frac{k}{2}+1=\frac{k+2}{2}$ and the other one is the same on both sides.

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I assume $k=2$ is a typo for $k+2$, and trust you to work out why $(k/2)+1=(k+2)/2$.

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    @liangteh: $k/2+1=\frac{k+2}{2}$.2011-05-06