If I want to change the following integral from Cartesians to Polars:
$\int_{-\infty}^\infty\int_{-\infty}^\infty (x-a)^2+(y-b)^2\,\,dx\,dy$
in a way such that we are centered at $(a,b)$, so $(x-a)^2+(y-b)^2=r^2$,
Is the polar form simply $\int_0^{2\pi}\int_0^\infty r^3 \,\,dr\,d\theta$?