Roll 8 fair dice. $X$ is the number of dice that land on $6$. How would you calculate the variance of $X$?
Can we treat this problem as a binomial such that $p$ = probability of landing on a $6$, $p = \frac{1}{6}$ and $q$ = probability of not landing on a $6$, $q=\frac{5}{6}$. Then the variance $\operatorname{Var}(X) = n p q = 8 \times \frac{1}{6} \times \frac{5}{6}$.
Would this be correct?