I'm having a hard time with this exponential equation, I'm sure I'm doing some kind of a "minor" mistake again somewhere along the way. Your help is very much appreciated.
$4\cdot4^{2x}-9\cdot 4^x+2=0$
*Answers given are: $0,5; -1$.
I'm having a hard time with this exponential equation, I'm sure I'm doing some kind of a "minor" mistake again somewhere along the way. Your help is very much appreciated.
$4\cdot4^{2x}-9\cdot 4^x+2=0$
*Answers given are: $0,5; -1$.
Let $y=4^x$. The equation $4\cdot4^{2x}-9\cdot 4^x+2=0$ $4\cdot(4^x)^2-9\cdot 4^x+2=0$ becomes a quadratic $4y^2-9y+2=0,$ which we can solve with the quadratic formula. Then, once you've found the two values for $y$, solve for $x$ using $y=4^x$.