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i have a periodic signal $x[n] = \cos (\frac{2 \pi}{10}n)$.
I found this DTFT pair:

enter image description here

That's the only pair for a cosine function i found. But what is $\delta _{2\pi}$ ? Is it just a Dirac $\delta$ function for every period ?
And the $\pi$ before the brackets is just for a higher amplitude of the impulse ?

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    Well, it just says calculate the periodic signal $x[n]$.2011-05-25

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The DTFT is always $2\pi$-periodic, since changing the frequency by $2\pi$ doesn't change the phase at the integers. The cosine is a sum of two exponentials and has frequency components at $\theta_0$ and $-\theta_0$. The $\delta_{2\pi}$ function replicates these with period $2\pi$. As was already stated in the comments, the factor $\pi$ is a matter of convention; it gives the right normalization for the definition used e.g. in the Wikipedia article.