I found this limit within the Calculus Single Variable book from Thomas. $ \lim _{x \to -2^-} (x+3) \frac{|x+2|}{(x+2)}$
This is how I'm trying: First of all, we need to found where the absolute value will apply. $|x+2|$ $x+2=0$ $x=-2$ $ -3+2<0 $ $ -1+2>0 $
So the function will change of sign in this interval: $(-\infty, -2)$ Then I´m trying to solve by substitution but im stuck with the |x+2|, I don't know what to do within the absolute value :(. Thanks.