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How would I go about solving a problem that goes roughly as such?

Solution A: .1% Solution B: .15% 

How many milliliters of each A & B are required to create 260 milliliters of a solution, C, that is .14%?

1 Answers 1

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Solve the following system:

  1. $x+y = 260$
  2. $0.1x+0.15y = (0.14)(260)$
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    @Josh: The RHS of equation 2 should be 0.14*260. Then you should be OK. Can you explain why?2011-01-13