Algebraically find where the cubic polynomial function that has zeroes at $2, 3 -5$ and passes through $(4, 36)$, has a value of $120$.
Yeah, so this is a question in my textbook which I don't really understand what its asking. It's an inequality question. The textbook answer is $x =-2, x =-3, x =5$.
I try writing up the equation as $f(x) = (x-2)(x-3)(x+5)$. Then I am not too sure where to go from there since I have $2$ $y$-values. So can anyone tell me how to solve this functions inequality?