A projectile is launched over level ground at $35 \frac{m}{s}$ at an angle of $24^{\circ}$ above the horizontal. Friction is negligible. What is the velocity (magnitude and direction) of this projectile $2.5$ s after launch?
For the magnitude do they mean the overall velocity at $2.5$ seconds $(\cos(24)35)$ in or do they mean the magnitude of the displacement: $\cos(24)35 \cdot 2.5$ ?
For the direction part do you assemble a triangle of the the combined velocity and the x and y components. Then use the cos law to solve for cos of the angle? Is this completely wrong? The answer on my homework differs from mine, but maybe thats just cause my math skills are questionable. Can anyone help me out with this and solve it step for step with an answer at the end? Thanks soooooo much :)!!!!!!