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I am confused about this problem: Find the domain of the function, $f(x)=\frac{x^3-1}{2x^2+5}.$ I'm guessing it's all real numbers but the book gives a different answer.


The book gave $(-\infty,-1)\cup (-1,0)\cup (0,\infty)$ as the answer.

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    Thanks very much. The online version of the book gave the above answer. So I got a copy of the book itself, and it gave the answer to be $(-\infty, \infty)$. I guess it's just a typo in the online version.2011-07-14

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The book has goofed. You have $2x^2 + 5 \ge 5 > 0$ for all real $x$. Since the denominator has no real zeroes, the function is defined everywhere. Its natural domain in the entire real line.