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I need help solving (b) in this math problem.

Determine the matrix of f in the standard basis (Linear Algebra)

What is the relationship between the matrix f and the transformation matrix in the standard basis?

Thanks for any suggestions!

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    Yeah I got that, only I am not very good at expressing myself in English (about math). I know I am supposed to find the matrix for the linear transformation in the standard basis, given another basis {g1 g2}. Though, I am not sure how to do this. How to switch basis, that is. I think I should be able to use the result from (a) to determine the matrix, but I'm not sure how so any pointers would be appreciated!2011-03-07

1 Answers 1

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Say $\gamma=[g_1,g_2]$, $\beta$ is the standard ordered basis, and $[T]_{\gamma}$ is the matrix from part $(a)$.

We can find the change-of-basis matrix from $\gamma$ to $\beta$ by writing $g_1$ and $g_2$ as linear combinations of ${1 \choose 0}, {0 \choose 1}$:

${5 \choose 4}=5{1 \choose 0}+ 4{0 \choose 1}$

${-4 \choose 5}=-4{1 \choose 0}+ 5{0 \choose 1}$

These coefficients form the columns of the change-of-basis-matrix from $\gamma$ to $\beta$.

$[Q]_{\gamma}^\beta= \begin{pmatrix} 5 & -4 \\ 4 & 5 \end{pmatrix} $

We can also find the change-of-basis-matrix from $\beta$ to $\gamma$ by reversing the process above (writing ${1 \choose 0}$ and ${0 \choose 1}$ as linear combinations of $g_1$ and $g_2$) or by taking the inverse of $[Q]_{\gamma}^\beta$.

In either case, $[Q]_{\beta}^\gamma=\begin{pmatrix} \frac{5}{41} & \frac{4}{41} \\ \frac{-4}{41} & \frac{5}{41} \end{pmatrix} $

Then we multiply the matrices in the proper order. (The matrix $[T]_{\beta}$ is the matrix representation of $f$ with respect to the standard ordered basis.)

$[T]_{\beta}=[Q]_{\gamma}^\beta[T]_{\gamma}[Q]_{\beta}^\gamma= \begin{pmatrix} 5 & -4 \\ 4 & 5 \end{pmatrix} \begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix} \begin{pmatrix} \frac{5}{41} & \frac{4}{41} \\ \frac{-4}{41} & \frac{5}{41} \end{pmatrix}= \begin{pmatrix} \frac{9}{41} & \frac{40}{41} \\ \frac{40}{41} & \frac{-9}{41} \end{pmatrix}$

I hope that helps!

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    Very helpful, thanks!2011-03-07