I have a MATLAB question. How can I calculate and subsequently plot the argument of
$x(n) = e^{(0.1 + 0.3j)n}$
I have a MATLAB question. How can I calculate and subsequently plot the argument of
$x(n) = e^{(0.1 + 0.3j)n}$
n=1:3; x=exp((0.1+i*0.3)*n); p=angle(x) plot(p)