I'm having trouble finding the solution to the following problem.
(1) $2\log(y) = \log(2) + \log(x)$
(2) $2^y = 4^x$
So far all I've managed is:
from (1) simplify using properties of logarithms:
$\log(y^2) = \log(2x)$
$y^2 = 2x$
or from (2)
$2^y = 4^x$
$10^y = \log(y) = 20^x$
neither of which seem to lead to a suitable substitution into the other equation.
tagged as homework as it is obviously homework level, only trouble I don't have a teacher or tutor to ask.