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Problem statement:

Let A be an uncountable set, B a countable subset of A, and C the complement of B in A. Prove that there exists a one-to-one correspondence between A and C.

My thoughts:

There's a bijection between A and A (the identity function). There's a bijection between C and C (the identity function). There's a bijection between B and $\mathbb{N}$. That's all I know.

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    Cardinal numbers are in the next chapter, so I guess not. This chapter proves that a countable union of countable sets is countable, $\mathbb{N}$ is countable, $\mathbb{Q}$ is countable, the algebraic numbers are countable, and $\mathbb{R}$ is not countable.2011-03-06

1 Answers 1

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Since $A\setminus B$ is uncountable, assuming countable choice it has a countably infinite subset B'. Then B'\cup B is countable, so there is a bijection g:B'\cup B\to B'. Define $f:A\to A\setminus B$ by f\vert_{B'\cup B}=g and $f(a)=a$ for a\in A\setminus(B'\cup B).

Basically, you just take chunks off of $A$ and $A\setminus B$ that have equal size, respectively B'\cup B and B', leaving the remaining sets equal to A\setminus(B'\cup B), then piece together the two bijections.