I am having trouble figuring out how I can solve this log:
$6 \log(x^2+1)-x=0$
The steps i've thought to take so far are as follows:
step 1: subtract the right most x to the other side of the equation:
$6 \log(x^2+1) = x$
step 2: divide by 6:
$\log(x^2+1)=\frac{x}{6}$
step 3: make both sides an exponent of 10 to get rid of the log:
$x^2+1 = 10^{\frac{x}{6}}$
step 4. ??????????????