2
$\begingroup$

I've been looking through Milne's notes, and I've gotten a bit tripped up by the section on finite maps. This is just a basic question about the definition, so I hope it's not too stupid.

A regular map of algebraic varieties $\varphi: W \rightarrow V$ is finite if for all open affines $U \subset V$, $\varphi^{-1}(U)$ is an affine variety and $k[\varphi^{-1}(U)]$ is a finite $k[U]$-algebra.

I'm trying to understand the basic case when $W,V$ are affine algebraic varieties and $k[W]$ is a finite $k[V]$-algebra. This is a finite map, but I'm having a bit of trouble digesting how this fits into the definition.

The explanation is that $k[\varphi^{-1}(U)] \simeq k[W] \otimes_{k[V]} k[U]$; I know this holds if $k[W] \otimes_{k[V]} k[U]$ is reduced, but how do we know that?

Milne says this implies that $\varphi^{-1}(U) \rightarrow \text{Spm}(\Gamma(\varphi^{-1}(U), \mathcal{O}_W)$ is an isomorphism (showing that $\varphi^{-1}(U)$ is affine). As I understand it, this follows from the general fact that

$ \text{Spm}(A) \times_{\text{Spm}(R)} \text{Spm}(B) \simeq \text{Spm}(A \otimes_R B / \mathfrak{N}) $

applied to the situation above, where we have $W \simeq \text{Spm}(k[W])$, etc. due to affineness.

So to summarize, I'm wondering why the isomorphism $k[\varphi^{-1}(U)] \simeq k[W] \otimes_{k[V]} k[U]$ holds (why is the RHS reduced?) and if my reasoning for how this implies that $\varphi$ is a finite map (in particular, that $\varphi^{-1}(U)$ is affine) is correct.

  • 0
    Incidentally, the general claim about finite maps you write is true for schemes; it is a special case of the so-called "affine communication lemma" (see the notes by Ravi Vakil) where you want to show that if an affine cover has a certain property, then *every* open affine has this property.2011-08-25

1 Answers 1

1

First let me take care of your question about reducedness of your tensor product.
The trick here is to realize that, given a morphism of varieties $\phi:W\to V$ and an open subset $U\subset V$, affine or not,the fiber product $U\times_V W$ is $\phi^{-1}(U)$, with its obvious morphisms to $U$ and $W$.
This follows directly from the categorical definition of fibered product , without any mention of tensor products.A confirmation is that Milne mentions that in Example 4.29, whereas he only starts mentioning tensor products in Example 4.30.

As for finite morphisms, it is very easy to check finiteness of a morphism $\phi:W\to V \:$ if $V$ and $W$ are affine varieties . Namely $\phi$ is finite iff the corresponding ring morphism $\phi:k[V] \to k[W]$ is finite.
In other words when the varieties are affine, you don't have to check that for all open affines $U \subset V$, $\varphi^{-1}(U)$ is an affine variety and $k[\varphi^{-1}(U)]$ is a finite $k[U]$-algebra: this is automatic (but not at all trivial), as mentioned in Proposition 8.2.

Finally, since you are learning the subject, you might enjoy the little exercise of proving that the projection $\phi:(x,y)\mapsto x$ of the hyperbola $W=\{(x,y)\in \mathbb A^2_k|xy=1\}$ into the affine line $V=\mathbb A^1_k$ is not finite even though the fibers of this morphism are certainly finite sets (singletons or $\emptyset$)