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How can I compute this limit: $\lim_{z\rightarrow i} (z\cdot \overline{z})$ (where $\overline{z}$ is the conjugate of $z$)?

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    Sory, I'll try that next time.2011-02-16

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As $\mathbb{C}$ comes nicely equipped with a metric, limits behave as nice as ever. Therefore, the limit of the product is the product of the limits. And the limit of the conjugate is the conjugate of the limit (this can be proved using a standard epsilon-delta argument). Hence, in your example: $\lim_{z \to i} (z \cdot \overline{z})=\lim_{z \to i}(z) \lim_{z \to i}(\overline{z})= i \cdot(-i) = 1.$

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    Thanks, I should revise the properties of the limit in the complex plane2011-02-16
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Hint: Is z' the conjugate of $z$ and the lower dot a multiplication? If so, what is the problem? You might try expressing $z=a+bi$, with $a,b$ real and trying a real limit.

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    `\overline`, just got it!2011-02-16