I have a formula to do the calculation from 7 set of numbers to 4 digits, for example:
04, 05, 19, 21, 22, 31, 13 ====> 4382
These 7 sets of numbers are ranging from 01 to 45, each set will only exists once.
Calculation are as follow:
Sum up 1st to 6th number, and times with 2
(4 + 5 + 19 + 21 + 22 + 31) * 2 = 204
Take the result of step 1, minus 1st number and 6th number
204 - 4 - 31 = 169
Take the result of step 2, plus with the 7th number
169 + 13 = 182
- From here, take the last 2 digits of the result from step 3
82
- From here, take the last 2 digits of the result from step 3
Sum up the 4th and 5th number
21 + 22 = 43
- From here, take the last digit of the result from step 4
3
- From here, take the last digit of the result from step 4
Sum up the 2nd and 3rd number
5 + 19 =24
- From here, take the last digit of the result from step 5
4
- From here, take the last digit of the result from step 5
There you get the final result of 4382
If any result from any step above contains 0 (zero), take that as a value in one of the digit into the final result.
So anyone has any idea if I have "4382" with me, can you get back the 7 sets of numbers? Not necessary must be exactly the same as I've written on top, as long as the 7 sets of numbers can produce the final result into "4382".
Really need a master to gimme some clues. Thanks.
1st to 6th number must be in a sequence from smallest to largest number in the range of 01 to 45. It's a game that comes out with this calculation, and I need to find out the way to reverse it.