I have the problem $2x^3 + x^2y-xy^3 = 2$ and i am supposed to implicity differentiate the problem but i am getting lost at $-xy^3$ in theproblem and it got me stuck. How do i work this problem out i got the idea down but its just murdering me in that little part, do i use the quotient rule? Or do i combine quotient with chain? And how does that work? maybe im just missing it.
So far i got this
$\frac{\mathrm{d}}{\mathrm{d}x} [2x^3+x^2y -xy^3 ] = \frac{\mathrm{d}}{\mathrm{d}x}(2)$
$6x^2 + \left(2xy + x^2\frac{\mathrm{d}y}{\mathrm{d}x}\right) - \text{Here i am lost}) = 0$