How to calculate the integral below:
$ \int_{0}^{1}(ax^2+bx+c)^{-3/{2}}dx $
How to calculate the integral below:
$ \int_{0}^{1}(ax^2+bx+c)^{-3/{2}}dx $
Hint: Complete the square on $ax^2+bx+c$ and then try a trigonometric substitution. Also, depending on the values of $a$, $b$, and $c$, the integral may be improper (and divergent).