$\frac{52}{x}=13$
It says to next step
$\frac{52}{13}=x$
Ok, I can do future problems like this, but is there a rule that explains this? What just happened to both sides of the equal sign?
$\frac{52}{x}=13$
It says to next step
$\frac{52}{13}=x$
Ok, I can do future problems like this, but is there a rule that explains this? What just happened to both sides of the equal sign?
There are two steps here: starting with $\frac{52}{x}=13$ we multiply both sides by $x$ to get $\frac{52}{x}\cdot x=13\cdot x$ $52=13\cdot x$ and then dividing both sides of that by $13$ to get $\frac{52}{13}=\frac{13\cdot x}{13}$ $\frac{52}{13}=x$
For $a, b, c, d$ non-zero,
$\frac{a}{b} = \frac{c}{d}$ is equivalent to
$ad = bc$.
Then if you divide both sides by $c$, you'll get $\frac{ad}{c} = b$
Believe it or not, this is your situation! (with $d = 1$)
I'd count several steps here. Anyways...
We start with $\left(\frac{52}{x}\right)=13$. Multiplying both sides by x we have $\left(\left(\frac{52}{x}\right)*{x}\right)=(13*{x}).$ Since $\left(\frac{x}{1}\right)=x$ we have $\left(\left(\frac{52}{x}\right)*\left(\frac{x}{1}\right)\right)=(13*{x}).$ Applying the product rule for quotients, we have $\left(\frac{(52*x)}{(x*1)}\right)=(13*{x}).$ Since multiplication commutes, we have $\left(\frac{(x*52)}{(x*1)}\right)=(13*{x}).$ Applying the product rule for quotients again, we have $\left(\left(\frac{x}{x}\right)*\left(\frac{52}{1}\right)\right)=(13*{x}).$ Since $\left(\frac{x}{x}\right) =\left(\frac{1}{1}\right)$ we obtain $\left(\left(\frac{1}{1}\right)*\left(\frac{52}{1}\right)\right)=(13*{x}).$ Applying the product rule for quotients once again we have $\left(\frac{(1*52)}{(1*1)}\right)=(13*{x}).$ Since $(1*1)=1$, and $(1*52)=52$ we obtain $\left(\frac{52}{1}\right)=(13*{x}).$ Now we multiply both sides by $\left(\frac{1}{13}\right)$ and obtain $\left(\left(\frac{1}{13}\right)*\left(\frac{52}{1}\right)\right)=\left(\left(\frac{1}{13}\right)*\left(13*{x}\right)\right).$ Since 13 equals $\left(\frac{13}{1}\right)$ we obtain $\left(\left(\frac{1}{13}\right)*\left(\frac{52}{1}\right)\right)=\left(\frac{1}{13}\right)*\left(\left(\frac{13}{1})*{x}\right)\right).$ Since * associates we have $\left(\left(\frac{1}{13}\right)*\left(\frac{52}{1}\right)\right)=\left(\left(\left(\frac{1}{13}\right)*\left(\frac{13}{1}\right)\right)*{x}\right).$ Applying the product rule for quotients on both sides we obtain $\left(\frac{(1*52)}{(13*1)}\right)=\left(\left(\frac{(1*13)}{(13*1)}\right)*{x}\right).$ Since $(1*52)=52$, $(13*1)=13$, and $(1*13)=13$, we obtain $\left(\frac{52}{13}\right)=\left(\left(\frac{13}{13}\right)*{x}\right).$ Since $\left(\frac{13}{13}\right)=1$ we obtain $\left(\frac{52}{13}\right)=(1*x).$ Since $(1*x)=x$, we obtain $\left(\frac{52}{13}\right)=x$
Even reasoning in this way steps have gotten left out, such as how we can "multiply both sides by x."