I am supposed to show that $R/J=(R/I)/(J/I)$ for two ideals $I\subseteq J\subset R$. How can I do this? I tried to construct an explicit isomorphism, but that did not work out (for me). Is there a more elegant solution?
Thank you in advance,
I am supposed to show that $R/J=(R/I)/(J/I)$ for two ideals $I\subseteq J\subset R$. How can I do this? I tried to construct an explicit isomorphism, but that did not work out (for me). Is there a more elegant solution?
Thank you in advance,
If you know it for groups, you can show that this works at the group level and then just verify that the resulting map is a homomorphism of rings.
As for an elegant method, there is an obvious map $\frac{R}{I}\to\frac{R}{J}$ given by $a+I \longmapsto a+J$ (which is well defined since $I\subseteq J$). Verify that the kernel is precisely $\frac{J}{I}$, and apply the First Isomorphism Theorem.