If G is an abelian group and N is a subgroup of G, show that G/N is an abelian group.
What I have so far: N is abelian since N is a subgroup of the abelian group G. N is also normal to G because of this reason. Since G and N are abelian, GmodN (or G/N) is abelian.
Is this sufficient or am I missing some details?