I know that $\cot\theta = 4/3$ how do I find $\csc\theta$?
I tried to do $\csc^2\theta - \cot^2\theta = 1$
This gives me $\csc^2\theta = 1 + \cot^2\theta$
this gives $csc^2\theta = 9/9 + 16/9 = 27/9 = \sqrt{3}$
is this wrong? My book gives the answer as $5/3$
I can never go more than $2$ homework problems without getting stuck.