I have the ODE y' = y^2-4
I want to draw the direction field and draw the solutions that satisfy $y(0)=-4$ and $y(0)=0$ without solving the equation.
So i am writing $y^2-4 = c$ and then i start giving values to c in order to calculate y.
$c = 0, y=_{-}^{+}2$ $c = 1, y=_{-}^{+}\sqrt{5}$ $\vdots$
Then how am i drawing the direction field and the integral curves?