let be the function $y=ax\log(bx)$, here $a$ and $b$ are constants and $\log$ is the natural logarithm
how can i evaluate the inverse function of this in terms of the Lambert $W$-function ??
let be the function $y=ax\log(bx)$, here $a$ and $b$ are constants and $\log$ is the natural logarithm
how can i evaluate the inverse function of this in terms of the Lambert $W$-function ??
opt has given the Wolfram Alpha output. Here I give an explicit derivation for reference.
We rearrange like so:
$\frac{y}{a}=x\log\,bx$
multiply both sides by $b$:
$\frac{by}{a}=bx\log\,bx$
and make things a little complicated:
$\frac{by}{a}=\exp(\log\,bx)\log\,bx$
We are now in a position to leverage the Lambert function:
$\log\,bx=W\left(\frac{by}{a}\right)$
and now solving for $x$ is a snap:
$x=\frac1{b}\exp\left(W\left(\frac{by}{a}\right)\right)$
Some people are tempted to "simplify" $\exp(W(z))$ to $z/W(z)$ (as was done in the Wolfram Alpha output), but I don't recommend this, as it introduces an unneeded removable discontinuity when $z=0$ for the principal branch...