Quesiton:
Represent the root(s) of $\sin x=\cos x+\tan x$ as length on rectangular coordinate.
For example, if $x=2$, you represent it as "the length between $(0,0)$ and $(2,0)$".
How can I solve this?
Quesiton:
Represent the root(s) of $\sin x=\cos x+\tan x$ as length on rectangular coordinate.
For example, if $x=2$, you represent it as "the length between $(0,0)$ and $(2,0)$".
How can I solve this?
The equation $\sin x=\cos x+\tan x$ is equivalent to
$\frac{2\tan \frac{x}{2}}{1+\tan ^{2}\frac{x}{2}}=\frac{1-\tan ^{2}\frac{x}{2% }}{1+\tan ^{2}\frac{x}{2}}+\frac{2\tan \frac{x}{2}}{1-\tan ^{2}\frac{x}{2}}.$
Set $\tan \frac{x}{2}=y$. Then
$2y=1-y^{2}+\left( 2y\right) \frac{1+y^{2}}{1-y^{2}},$
or, equivalently
$y^{4}+4y^{3}-2y^{2}+1=0.$
Then $x=2\arctan y$, where $y$ are the solutions of this quartic (see this computation in Wolfram Alpha).
The direct computation in Wolfram Alpha gives solution(s) in terms of $\arccos(R(x))$ where $R(x)$ is a function with too many radicals.