A three-digit number 'n' (less than 500) is taken. A six-digit number is formed by writing the number 'n' as first three digits and the number '2n' as the last three. Which of the following is necessarily a divisor of the number so obtained?
After this there is actually 4 options to choose $6,37,167,501$. The solution specified in my module is goes like this: "If the original number is $ab$c, the new $6-$digit number will be $abc \times 1002$", after this it is pretty straight forward, but I don't understand how they are forming "$abc \times 1002$" as the concatenated number.