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I'm taking a course on differential geometry, and up until now I'd always thought that the definition of a geodesic is (loosely speaking) a curve on a surface with the minimal length between its endpoints. My professor, taking his lead from do Carmo, however, defines it as any curve whose geodesic curvature $\kappa_g=0$. We showed that this is equivalent to satisfying the following pair of nonlinear ordinary differential equations:

$(\boldsymbol{E}u' + \boldsymbol{F}v')' = \frac12(\boldsymbol{E}_u(u')^2 + 2\boldsymbol{F}_uu'v' + \boldsymbol{G}_u(v')^2)$

$(\boldsymbol{F}u' + \boldsymbol{G}v')' = \frac12(\boldsymbol{E}_v(u')^2 + 2\boldsymbol{F}_vu'v' + \boldsymbol{G}_v(v')^2)$

We then went through an incredibly painful calculation on the length of the family of curves $\gamma_\lambda$ to show that geodesics (i.e, those curves satisfying the geodesic equations above) are critical points of the functional

$\displaystyle\mathcal{L}(\lambda) = \int_a^b{\left\|\frac{d\gamma_\lambda}{dt}\right\| dt},$

which is the length of the curve. Therefore, according to my professor's (and the textbook's) definition, geodesics are not necessarily length-minimizing, just critical points of $\mathcal{L}$. Therefore, on a sphere, two non-antipodal points have two geodesics: the obvious length-minimizing one, and the other one going the long way around the sphere (which is, in this case, a saddle point of $\mathcal{L}$). This is not just an oversight on my professor's part, he explicitly brought attention to this fact.

My question is, what are the advantages and disadvantages of these two conflicting definitions? I still see the length-minimizing one almost everywhere.

On a related note, the fact that a geodesic is only a critical point, not necessarily a minimum, leaves open the possibility of a geodesic actually being the longest path between two points. Are there any situations where this is actually possible? It seems you could always perturb a curve slightly to stay within the image of a chart while still increasing its length infinitesimally. Are there some weird spaces where this is not the case?

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    By the way, the calculations are significantly cleaner in the general case. Check out the other do Carmo ("Riemannian Geometry"), it's pretty accessible.2011-03-23

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I don't really see any advantage to restricting the definition of geodesic to be minimal -- after all, those are just what we call "minimal geodesics"! As you do more geometry (Riemannian and otherwise), you'll encounter many other definitions that are given via differential equations. These all have their local theories -- in this case, we find that every point on a Riemannian manifold has a neighborhood where minimizing geodesics are unique -- and this does not detect the global behavior. But this can be a good thing, because once you've nailed down the local picture then you have firmer footing to ask global questions. Here, we might ask: When exactly does a geodesic stop being a minimizing geodesic?

These words may not mean anything, and they don't really need to, but a similar differential-geometric example that might shed light by analogy is Darboux's theorem, which says that all symplectic manifolds of the same dimension are locally symplectomorphic. That is, as far as the stuff we care about is concerned (namely the "symplectic structure"), neighborhoods of any two points on any two equidimensional symplectic manifolds are indistinguishable. This is true too of smooth manifolds, but not of Riemannian manifolds, since curvature gives us a local invariant with which to distinguish them. (In fact curvature is the only local invariant! But that's another story.) But nevertheless people call themselves symplectic geometers, and indeed there are some very deep global questions in symplectic geometry.

The moral of the story is that in geometry one often starts with an idea (e.g. "the shortest path between two points"), examines the local behavior, and then works to understand how the local story pieces together to form a global picture. This makes it very natural to begin with local definitions such as the one you mention.

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    Sure! I guess the way it was phrased suggested to me that it was meant to give information rather than just mention the name. But you're right, it's nice to have heard the words.2011-03-24
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A short answer is that the definition via geodesic curvature is much easier to verify, hence much easier to prove things about.

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One example of a geodesic being the longest path in some sense is in Einstein's relativity. It is related to the Twin Paradox, where two twins set off from some point in spacetime and then meet again at another point in spacetime, to discover one has aged more than the other.

The geodesic is the path which takes the longest as measured by a clock passing along it. For Special Relativity, this is a straight line and a constant speed, i.e. inertial motion, and any clock going by any other path will measure less time.

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    Inte$r$esting. It seems like this is a $d$ifferent use of the word "longest", as a measurement in a particular coordinate with no reference to the metric on the 4-manifold. What is the metric, anyways?2011-03-24
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It seems to me that the only possible situation where a geodesic is the longest path (among the class of injective paths) between two points is where it is the only path; in particular, on some one-dimensional (sub)manifolds (lines but not circles). Here it is also the shortest path.

Keep in mind that all minimisers of the length functional are also critical points, thus every "shortest path" is also a geodesic, but not vice-versa.

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    Sure, of course you are right, on one can always continue to loop over the path or go back and forth to generate paths longer than the geodesic. It also isn't true for S^1. Sigh. I'll edit.2011-03-24