Having trouble with one of my math homework problems. I need to find the least common denominator (LCD) to solve the problem. I'm not sure how to figure this out one. Thanks in advance.
$ \frac{3}{j^2+6j} + \frac{2j}{j+6} - \frac{2}{3j} .$
Having trouble with one of my math homework problems. I need to find the least common denominator (LCD) to solve the problem. I'm not sure how to figure this out one. Thanks in advance.
$ \frac{3}{j^2+6j} + \frac{2j}{j+6} - \frac{2}{3j} .$
Hint: First try finding the LCD of some integers. For example, evaluate $\frac{3}{4} + \frac{7}{10} + \frac{13}{25}$ and be very conscious of how you're doing it when you get a common denominator. Next try adding these: $\frac{1}{x^2} + \frac{1}{x}$ and $\frac{1}{x+3} + \frac{1}{x^2-9}$ It's the same thing each time, but you need to use a bit of algebra. Now try your homework problem. Good luck!
Hint: The denominator $j^2 + 6j$ factors as $j(j + 6)$. Now, look at all the factors that appear in the various denominators: $ j, j + 6, 3. $ So, a good common denominator might be $3j(j+6)$. How can you make all the fractions have this denominator?