What is the behaviour of the steady state $(0,0)$ of the system \left\{ \begin{array}{c} x' = x + x \cdot \sin{y} \\\ y' = 2y - y \cdot \cos{x} \end{array}\right.
Can anybody help me with the solution of this question.
What is the behaviour of the steady state $(0,0)$ of the system \left\{ \begin{array}{c} x' = x + x \cdot \sin{y} \\\ y' = 2y - y \cdot \cos{x} \end{array}\right.
Can anybody help me with the solution of this question.
Well, seems to be a homework. First even though you don't ask about it, I would mention that there is indeed only one equilibrium because y' = y(2-\cos x).
The first step would be to linearize the system, i.e. for $\begin{cases} f(x,y) = x(1+\sin y)\\g(x,y) = y(2-\cos x) \end{cases} $ to find the matrix of partial derivatives $ A = \left(\begin{align}&f_x(0,0)& f_y(0,0)\\&g_x(0,0) &g_y(0,0)\end{align}\right) $ and find eigenvalues of $A$.