The fraction:
$\frac{y^2-x^2}{x-y}$
should simplify to the answer:
$-(x+y)$
but the best I could do was expand it to:
$\frac{(y+x)(y-x)}{x-y}$
What's next step?
The fraction:
$\frac{y^2-x^2}{x-y}$
should simplify to the answer:
$-(x+y)$
but the best I could do was expand it to:
$\frac{(y+x)(y-x)}{x-y}$
What's next step?
For $x \neq y$, $\frac{(y+x)(y-x)}{x-y} = \frac{(y+x)(y-x)}{-(y-x)}$
$ = -(y+x)$ $ = -(x+y)$