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I have an equation. For example the law of cosines, $c^2 = a^2 + b^2 - 2ab \cos C$

So I calculate it all and I get something like this: 2500 cos 130. I calculate the cos 130, and get -0.643 Now what? I have 2500 and -0.643. Do I multiply them? Or what?

Thanks.

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    So, $2ab\cos C = 2\cdot a \cdot b \cos(C)$. – 2011-06-15

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Usually in math the convention is that when an operator is missing and arguments are just juxtaposed, the implicit operator is multiplication - Yuval Filmus

So, $2ab\cos C=2â‹…aâ‹…bâ‹…\cos(C)$ - Ihf

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Well as everyone points out there is a $\text{multiplication}$ operator. In other words $2ab\cos{C} = 2 \times a \times b \times \cos{C}$