In the textbook "A classical introduction to modern number theory" 1990 edition, at page 22 they write that
if $n>3$ then $e^{n-1}>2^n$.
I am not sure I see why, I mean if $n>3$ then $e^n /2^n > (e/2)^3$ but the RHS isn't greater than e, right?
Any hints?
Thanks in advance.