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For this question:

Given a poisson process with on the avg "a" arrivals per unit time, find the probability that there will be no arrivals during a time interval of length t, namely, the probability that the waiting times between successive arrivals will be at least of length t.

What probability density would I use for this of which I could use to solve the question? Thanks!

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    (I also think that whoever worded that question like that should really give it another shot; the part from *namely...* on could definitely be stated more clearly.)2011-11-12

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You want to use the distribution for the waiting time between events of a poisson process. $W$ has exponential distribution with parameter $ \lambda$, where $\lambda$ is the average number of events per unit time for the Poisson process.


This isn't hard to see. If $X$ is the number of events occurring in the interval $[0,t]$, then $P[W>t]=P[X=0]= e^{-\lambda t}$. So the cdf of $W$ is $F_W(t)=1-e^{-\lambda t}, t\ge0$; whence the density of $W$ is $f_W(t)= \lambda e^{-\lambda t}, t\ge 0$.

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    $X$ has Poisson distribution with parameter $\lambda t$. So $X=0$ is the event that no events occur in the interval $[0,t]$. This is the same as P[W>t], where $W$ is the waiting time. Note, I first found the cumulative density, $F_W$, of $W$ first, then differentiated to get the density (though I didn't explicitly say so).2011-11-12
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The exponential distribution.

Exponential Distribution