I had the question $9x^2 - y^2 = 1$ and my answer was $\frac{\mathrm{d}x}{\mathrm{d}y} = -18x-2y .$
I was wondering if I tackled this correctly? I am new to this.
I had the question $9x^2 - y^2 = 1$ and my answer was $\frac{\mathrm{d}x}{\mathrm{d}y} = -18x-2y .$
I was wondering if I tackled this correctly? I am new to this.
$ \frac{d}{dx}\left(9x^2 - y^2\right) = 18x - 2y\cdot\frac{dy}{dx} = \frac{d}{dx} 1 = 0. $ Then from $ 18x - 2y\cdot\frac{dy}{dx} = 0, $ you can find $dy/dx$.