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First of all, I would like to call a group immaculate provided that the orders of $G$ and $\Sigma$ (the order of $N$) where $N$ varies over all normal subgroups of $G$, are equal. From here it has been said that any abelianizer of a group whose order is less than that of $D(G)$, where $D(G)$ is the latter function defined above, is cyclic.

Then my question is: Is there any characterization of groups $G$ such that $G^{ab}$ is an imamculate group where $G^{ab}$ is the abelianizer of $G$ which coincides with the previous one in the case that $G$ is a cyclic group of the order a perfect number.

This may be referenced to here, in any case, thanks.

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    Well, @Steve D, can you be more specific, please, thanks.2011-02-17

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