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How do I find the symmetry point for a graph based on a quadratic equation?

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    Note that the graph of a quadratic equatio$n$ has a *li$n$e* of symmetry, not a *point* of symmetry.2011-05-04

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For an equation of the form $y= ax^2 + bx + c $ the axis of symmetry lies on the x-value $ \frac{-b}{2a}\ $.