Find the inflection point of the equation $\frac{1}{x^2y^3}=7$
Find the inflection point on the equation $\frac{1}{x^2y^3}=7$
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multivariable-calculus
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3Victor, people don't *really* care a$b$out your personal pro$b$lems and $t$his is not the place to share them or hope for pity. jspecter asked you to show what did you try to do to solve this problem, don't reply about how you cannot afford books. – 2011-12-17
1 Answers
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First notice that $x^2y^3=1/7$. Then it follows that $2xy^3+3x^2y^2(dy/dx)=0$ so that $dy/dx=-2y/3x$. Then, $d^2y/dx^2=((-6x(dy/dx))+6y)/(9x^2)$. Then find points where the second derivative is equal to zero or does not exist.