For my Homework I have four values: $N_1, N_2, A, C$.
Two values are chosen at random without replacement. X denotes how many N values are chosen.
$P(x=0) = \frac16 \qquad P(x=1) = \frac23 \qquad P(x=2) = \frac16 $
find the mean and variance.
I have taken the mean to be $\frac{(0+1+2)}{3} = \frac33 = 1$ However, I think this is wrong, and that the distribution must be taken into account.
The Variance is to be determined by the equation $ \text {Var}(x)=E(x^2)-E(x)^2$ However I am not certain what value to assign $x$.