Write as a single logarithm: $\log_8(5) - 2\log_8(6)$
To my understanding; because they are the same base you can just evaluate $\log_8\left(\frac{\log(5)}{\log(6)}\right)$ which is shown on the multiple choice I have as $\log_8\left(\frac{5}{12}\right)$.
However this is apparently not the correct answer. Where did I go wrong?
Thanks!