I found out this on Google+ yesterday and I was thinking about what's the trick. Can you tell?
How can you prove $3=2$?
This seems to be an anomaly or whatever you call in mathematics. Or maybe I'm just plain dense.
See this illustration:
$ -6 = -6 $
$ 9-15 = 4-10 $
Adding $\frac{25}{4}$ to both sides:
$ 9-15+ \frac{25}{4} = 4-10+ \frac{25}{4} $
Changing the order
$ 9+\frac{25}{4}-15 = 4+\frac{25}{4}-10 $
This is just like $a^2 + b^2 - 2a b = (a-b)^2$. Here $a_1 = 3, b_1=\frac{5}{2}$ for L.H.S, and $a_2 =2, b_2=\frac{5}{2}$ for R.H.S. So it can be expressed as follows:
$ \left(3-\frac{5}{2} \right) \left(3-\frac{5}{2} \right) = \left(2-\frac{5}{2} \right) \left( 2-\frac{5}{2} \right) $
Taking positive square root on both sides:
$ 3 - \frac{5}{2} = 2 - \frac{5}{2} $
$ 3 = 2 .$
I think it's something near the root.