Why this:
$(3 \ast (3^{k-1} + 1) - 2)$
equals to:
$(3 \ast 3^{k-1} + 3 - 2)$
and why/how from this we get to this:
$(3^k + 1)$
Multiplying brackets
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$\begingroup$
algebra-precalculus
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1Just evaluate from left to right, giving precedence to parentheses, exponents, multiplication, division, addition, subtraction (in that order, respectively). See solomoan's answer for more specifics to your particular question. – 2011-04-12
1 Answers
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Because $a*(b+c)=a*b+a*c$ and $x^m*x^n=x^{m+n}$