Possible Duplicate:
How to show that for any abelian group $G$, $\\text{Hom}(\\mathbb{Z},G)$ is isomorphic to $G$.
Simple question - is it true that $\mbox{Hom}(\mathbb{Z},G) \simeq G$ (probably by Yoneda Lemma, which I struggle to understand!)
Edit: $G$ is an abelian group