Are there any random variables so that $\mathrm{E}[XY]$ exists, but $\mathrm{E}[X]$ or $\mathrm{E}[Y]$ doesn't?
Are there any random variables so that $\mathrm{E}[XY]$ exists, but $\mathrm{E}[X]$ or $\mathrm{E}[Y]$ doesn't?
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probability
random
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0@Henry: the provided e-mails are the same and both are unregistered. I've merged the accounts. @Tzwick: to stop from making more duplicate accounts, please register your account. – 2011-04-09
2 Answers
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Yes. For example take $C$ as a Cauchy random variable and independently $H$ as $0$ or $1$ with equal probability.
Let $X=CH$ and $Y=C(1-H)$.
Then the expectations of $X$ and $Y$ would be half the expectation of $C$, except that it does not exist, while $XY=0$ and so $E[XY]=0$.
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Sure, let Y be the value $2^n$ with probability $\frac{1}{2^n}$. Let $X=1/Y$. Then $XY=1$ and $E(X)=\frac{4}{3}$ exists, but $E(Y)$ does not exist.
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0$Y$ definition is not complete. From your definition it is clear that $P(Y=2^n)=\frac{1}{2^n}$, but this leaves $1-2^{-n}$ of probability mass unassigned. – 2011-04-11