In a previous question I asked about how to apply $\operatorname{arctan2}$ to:
If $\sin(\theta) = \frac{-1}{2}$ and $\cos(\theta) = \frac{\sqrt{3}}{2}$ which is found as: $\operatorname{arctan2}( \frac{\sqrt{3}}{2} , \frac{-1}{2}) \implies \theta = \frac{-\pi}{6}$ or $-30^\circ$
Now I am asked to find:
If $\sin(\phi)\sin(\theta) = 0.2$ and $\sin(\phi) \cos(\theta) = -0.3$ and $\sin(\phi) > 0$ then, what is $\theta$? Repeat for $\sin(\phi) < 0$
I am confused as what I should do with the $\sin(\phi)$.