Believe it or not I graduated with a BSc in Computing Science, but apparently that means nothing after being out of school for a year.
The question is:
$\frac{(c+n)}{(t+n)}=\frac{1}{4}$
Solve for $n$.
My attempt:
$c+n=\frac{1}{4}(t+n)$
$c+n= \frac{1}{4}t+\frac{1}{4}n$
$c+\frac{3}{4}n=\frac{1}{4}t$
$\frac{3}{4}n=\frac{1}{4}t-c$
$n=\frac{4}{3}(\frac{1}{4}-c)$
But when I plug in the numbers I have, that doesn't work out, so there must be a mistake in there somewhere, but I can't seem to spot it.
Help?
The numbers I've got are:
$t=3035$
$c=413$
And the answer I expect for $n$ is $461$.