Using basic operators, derive the additional operator intersection.
$R \cap S = ?$
I thought it might be: $(R \cup S) - ((R -S) \cup (S -R))$ but I also think there might be an easier way of doing it?
Using basic operators, derive the additional operator intersection.
$R \cap S = ?$
I thought it might be: $(R \cup S) - ((R -S) \cup (S -R))$ but I also think there might be an easier way of doing it?
You could write $R \cap S = R-(R-S)$ or $R \cap S = S-(S-R)$. As Arturo mentioned, you are looking at one set and throwing away everything that is just in that set.