If I have $22x = 23y = 24z$ and $x+y+z = 3865$ how to obtain the values of $x$,$y$ and $z$ ?
Solving $x$, $y$ and $z$
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algebra-precalculus
arithmetic
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0Indeed substitution works like a charm :) – 2011-01-02
3 Answers
3
use $ y = \frac{22}{23}x$ and $z = \frac{22}{24}x$ in last equation.
5
First, try to express $y$ and $z$ by $x:$
$22x = 23y\Leftrightarrow y = \frac{22}{23}x$
$22x = 24z\Leftrightarrow z = \frac{11}{12}x$
Then put this into your term to find the value of $x\colon$
$x+y+z=3865\Leftrightarrow x+\frac{22}{23}x+\frac{11}{12}x=3865$
Now you have the value of $x.$ To figure out $y$ and $z$ is left as an exercise to you.