I am trying to solve for the following inequality:
$\frac{12}{2x-3}<1+2x$
In the given answer,
$\frac{12}{2x-3}-(1+2x)<0$
$\frac{-(2x+3)(2x-5)}{2x-3}<0 \rightarrow \textrm{ How do I get to this step?}$
$\frac{(2x+3)(2x-5)}{2x-3}>0$
$(2x+3)(2x-5)(2x-3)>0 \textrm{ via multiply both sides by }(2x-3)^2$