An interesting little problem:
I have found solutions $[a=3,b=2,c=1,d=5,e=4]$ but not able to find proof that these are all that exist.
Find, with proof, all integers $a$, $b$, $c$, $d$ and $e$ such that:
$a^2 = a + b - 2c + 2d + e - 8$
$b^2 = -a - 2b - c + 2d + 2e - 6$
$c^2 = 3a + 2b + c + 2d + 2e - 31$
$d^2 = 2a + b + c + 2d + 2e - 2$
$e^2 = a + 2b + 3c + 2d + e - 8$
It seems simple, but I cannot find a proof.
nikolai