Let $n_1,n_2,\dots,n_k$ be natural numbers (excluding 0), and for each $1\leq i\leq k$ let $\sigma_i(n_1,n_2,\dots,n_k)$ be the elementary symmetrical polynomial consisting of the sum of all products of $i$ distinct numbers, that is: $\sigma_i(n_1,n_2,\dots,n_k)= \sum_{1\leq j_1 < j_2 < \ldots < j_i \leq k} n_{j_1}\ldots n_{j_i}.$
Now, assume you have $k$ natural numbers $a_1,a_2,\ldots,a_k$, and you know that \begin{align*}(-1)^k \sigma_1=a_1,\ &(-1)^{k-1}\sigma_2=a_2,\ &\dots,\ &-\sigma_k=a_k. &\end{align*} My question is: Is there a way to obtain (algebraically) the unique set of natural numbers $n_1,n_2,\dots, n_k$ that satisfy these equations? To clearify: The $a_i$ are known, while the only thing we know about the $n_i$ is that they happen to be natural numbers and that they satisfy the above equations.
If I have understood correctly, this is equivalent to asking if there's a way of obtaining (algebraically) the $k$ roots of the polynomial $ t^k+a_{k}t^{k-1}+\cdots+a_3t^2+a_2t+a_1 ,$ knowing that these roots happen to be natural numbers...
Thanks in advance.