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I've been presented with a function expansion which I'm told is correct but I can't figure out where the sign in the second term might be coming from.

$ e^{i\alpha(x_\mu + \epsilon \, n_\mu)} = e^{i\alpha(x_\mu)} ( 1 - i\,\epsilon \,n^\nu\, \partial_\nu \alpha(x_\mu) ) $

$x_\mu$, $n_\mu$ are four vectors, the metric signature is + - - - and $\epsilon$ is infinitesimal.

Taylor expanding this myself about $x_\mu$ I get

$ e^{i\alpha(x_\mu + \epsilon \, n_\mu)} = e^{i\alpha(x_\mu)} ( 1 + i\,\epsilon \,n^\nu \,\partial_\nu \alpha(x_\mu) ) $

Am I missing something or is the presented equation wrong? Perhaps to do with the metric, or maybe they are doing something other than a Taylor expansion ? :-/

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    Thanks Fabian, perhaps you are right. I really just wanted to check that I wasn't missing something 'obvious'.2011-03-04

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