2
$\begingroup$

I am not able to solve this question from chapter "Similar & Congruent Triangles" in my book.

Can some one help to calculate AC?

HERE.

  • 0
    WAit! According to your question BD + DC = DC + ED = CE = BC. But triangle BDE would then be a straight line, if you remember the triangle inequality!2013-10-13

2 Answers 2

2

Hint: $\triangle ABC \sim \triangle CEB \sim \triangle BDE$.

  • 0
    hey thanks it worked ! i half thought of this but was fooled by the not-to-scale diagram!!!2011-10-16
0

enter image description here using triangle similarity here the triangle 1 is similar to the triangle 2, also the triangle 2 is similar to the triangle 3

  • 0
    and that's not required either :)2016-10-07