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4 items add up to and multiply to 7.11 what are the value of the items?
This is a question from the nrich website. I think I might have solved it, but the numbers it produce are not exact. The problem is in pounds and so I am assuming you can round the number to the nearest hundredth of a pound (i.e. pence).
My progress so far is as such: $a+b+c+d=abcd=711$(I just changed £7.11 to 711 pence so that it is easier to work with) $d={a+b+c\over abc-1}$ $\text{Thus } a+b+c<711$ Since $abcd=711$, a, b and c should be prime factors of a number close to 711 (lets call it $\alpha$) and should add up to close to that number. (i.e. $\alpha <711, \alpha=a+b+c\approx abc$)
Lets say that $\alpha = 710$, $\space a=708,\space b=1,\space c=1$
$d={708+1+1\over708\cdot1\cdot1-1}={710\over707}\approx1.0042$ $abcd=708\cdot1\cdot1\cdot{710\over707}=a+b+c+d=708+1+1+{710\over707}\approx711$
The general equation I came up with is (where $P_1$ is the total price): $a=P_1-3$ $b=1$ $c=1$ $d={P_1+1+1\over P_1 -1}$
I am pretty sure that this method is incorrect and I don't know if all my assumptions are correct, but I haven't though of any better way. Does anyone have any suggestions?