Can I, somewhat informally, state that d+1 points in $\mathbb{R}^d$ are affinely independent, if they don't lie in a $\mathbb{R}^{d-1}$ subspace?
affine independence
2
$\begingroup$
linear-algebra
1 Answers
2
Affine subspace, yes. (That's a translation of an ordinary vector subspace.)
-
0@stefan, yes, exactly. – 2011-05-05