Answer is given, and it equals to 1.
$ 2\cdot 16^{x}-2^{4x}-4^{2x-2}=15 $
$2^{4x-4}=-6,5$ <- This is where I reached, which is clearly wrong
Answer is given, and it equals to 1.
$ 2\cdot 16^{x}-2^{4x}-4^{2x-2}=15 $
$2^{4x-4}=-6,5$ <- This is where I reached, which is clearly wrong
Note that $2\cdot 16^x=2\cdot (2^4)^x=2\cdot2^{4x}=2^{4x+1}$ and $4^{2x-2}=(2^2)^{2x-2}=2^{4x-4}.$ So you want to solve $2\cdot16^x-2^{4x}-4^{2x-2}=15$ $2^{4x+1}-2^{4x}-2^{4x-4}=15$ See any good ways of factoring something out on the left side of the equation? I think you might have reached this stage but made a minor calculation error. If you want to check your work, here is a spoiler (if you put your cursor over the box, the next step will appear):
$2^{4x-4}(2^5-2^4-1)=15$