0
$\begingroup$

I have the following sequences that form a relationship:

x: 1 2 3 4 5
y: 1 2 4 8 16

Where each number in the second sequence is twice the previous number.

Is there a formula that will give me the correct value of y for a given value of x? Does it have a name, and how could I have gone about working this out for myself?

Many thanks in advance.

2 Answers 2

3

You have $y=2^{x-1}$ and some characters

  • 0
    @Ross: It is possible to work arou$n$d the character limit by hiding the padding in a HTML comment, like ``.2011-07-26
1

$y = 2^{x-1}$. This is a geometric sequence.