I'm trying to simplify the following booleans:
$Y=[\overline{ \overline{(A+B)} \quad \overline{(C+D)}}]$
My solution is:
$Y=[\overline{ \overline{(A+B)} \quad\overline{(C+D)}}]$ $ = [\overline{ \overline{(A+B)}} \quad \overline{ \overline{(C+D)}}]$
After this step my module is saying that the next step would be:
$Y = [(AB)(CD)]$
But I am not getting how,since I believe the next step is:$Y = [(A+B)(C+D)]$ which is just be canceling the negation both times,am I wrong?
This is a part of entire problem which is simplify: $Y= [(A+B)(C+D)] \cdot [\overline{ \overline{(A+B)} \quad\overline{(C+D)}}]$ my solution for which is $Y = [(A+B)(C+D)]$ but they are showing that $Y=ABCD$ should be the correct solution.