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How can I prove that $S^\infty$ is contractible? Is $S^\infty$ a CW complex?

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    In answer to your second question, $S^\infty$ is a CW complex. Let $X^0=*\coprod *$, and then obtain $X^{n+1}$ from $X^n$ by gluing two copies (the two hemispheres) of $D^{n+1}$ to $X^n$. Then $S^\infty\cong \operatorname{colim} X^n$.2011-09-10

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