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I am trying to figure out how to simply a canonical sum of products expression that is from this expression: $ f_1(x_1,x_2,x_3) = \sum m (2,3,4,6,7) $ where m is canonical minterms

I got: $ \bar{x}_{1}x_2\bar{x}_3 + \bar{x}_{1}x_2x_3+x_1\bar{x}_{2}\bar{x}_{3}+x_1x_2\bar{x}_{3} + x_1x_2x_3 $

then I simplify and get: $ x_2+x_1x_2 $

which is incorrect. I the answer in the book is: $ x_2+x_1\bar{x}_{3} $

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    Sorry, I edited question for further clarity.2011-09-22

1 Answers 1

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Let $a = x_{1}$, $b = x_{2}$, and $c = x_{3}$.

Then to simplify a'bc' + a'bc + ab'c' + abc' + abc

a'(bc' + bc) + a(b'c' + bc') + abc

a'(b(c' + c)) + a(c'(b' + b)) + abc

a'b + ac' + abc

a'b + a(c' + bc)

a'b + a(c' + b)

a'b + ac' + ab

b(a' + a) + ac'

b + ac'

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    genius! Thank you. I was doing fuzzy math, haha.2011-09-22