$\lim \limits_{h \to 0} \frac{\frac{1}{5+h}-\frac{1}{5}}{h}$
I simplified, even made a table and came up with $-1/25$ but it appears to be incorrect, according to my submit module.
If anyone has any tips or tricks on finding these limits, it would be greatly appreciated! I understand that the one with h and x will have to be in terms of x in some form or another.
$\lim \limits_{h \to 0} \frac{\frac{1}{x+h+3}-\frac{1}{x+3}}{h}$
EDIT: What a typo, it is supposed to be subtraction on the top.
I'm going to add the full original problem to make sure I didn't make any mistakes early on, so I know if the module has a wrong answer or not.
The problem states:
$f(x)=\frac{1}{x+3}$
Compute the limit of the difference quotients $\lim \limits_{h \to 0} \frac{f(2+h)-f(2)}{h}$