I have my discrete math final coming up on Monday and am trying to figure out how to do a few problems. The one I am having the most problem with is just very confusing because I don't know how to go about solving it, much less solving it. Here is the question
A group contains 5 men and 6 women. how many ways are there to arrange these people in a row if the men and women alternate? Hint: arrange the women first.
part of me thinks of doing a combination $C(6,5)$ where there are $6$ groups and $5$ need to be ordered. However, a friend says to multiply $5!\times 6!$. Then my teacher has another long explantation that I can't even follow because he runs through it so fast
I have no doubt this will be on the test, but I just don't understand how solve it.